$S$ is domain(open set and connected) and $gamma$ is closed curve in $S$ . If $f(z)$ analytic on $S$ and $f'(z)$ continous on $S$ The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.$f,g$ are continuous on closed unit disk but analytic on open unit disk and $f(z)=g(z)$Real valued analytic function defined on a connected set is constantSuppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.Finding a domain (open and connected set) that contains the unit circleClosed curve is homologous to zero in simply connected domainsComplex integralsMorera Theorem And Cauchy's Integral TheoremLet $gamma$ be a piece wise smooth closed curve .show that $∫z^mdz=0$show that for any closed curve $gamma$ containing $z_0$, $int _gamma f=0$Ahlfors' Complex Analysis Problem 4.1.3.5 $int limits_gammaoverlinef(z)f'(z), mathrmdz$

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$S$ is domain(open set and connected) and $gamma$ is closed curve in $S$ . If $f(z)$ analytic on $S$ and $f'(z)$ continous on $S$



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.$f,g$ are continuous on closed unit disk but analytic on open unit disk and $f(z)=g(z)$Real valued analytic function defined on a connected set is constantSuppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.Finding a domain (open and connected set) that contains the unit circleClosed curve is homologous to zero in simply connected domainsComplex integralsMorera Theorem And Cauchy's Integral TheoremLet $gamma$ be a piece wise smooth closed curve .show that $∫z^mdz=0$show that for any closed curve $gamma$ containing $z_0$, $int _gamma f=0$Ahlfors' Complex Analysis Problem 4.1.3.5 $int limits_gammaoverlinef(z)f'(z), mathrmdz$










0












$begingroup$


$S$ is domain(open set and connected) and $gamma$ is closed curve in $S$ . If $f(z)$ analytic on $S$ and $f'(z)$ continous on $S$ . Show that $int _gamma overlinef(z)f'(z) dz$ is only imajiner part



I stuck to prove that the real part is zero -__-










share|cite|improve this question









$endgroup$







  • 2




    $begingroup$
    Possible duplicate of Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.
    $endgroup$
    – kobe
    Mar 24 at 17:04










  • $begingroup$
    Thank you for your information
    $endgroup$
    – lio
    Mar 24 at 17:09















0












$begingroup$


$S$ is domain(open set and connected) and $gamma$ is closed curve in $S$ . If $f(z)$ analytic on $S$ and $f'(z)$ continous on $S$ . Show that $int _gamma overlinef(z)f'(z) dz$ is only imajiner part



I stuck to prove that the real part is zero -__-










share|cite|improve this question









$endgroup$







  • 2




    $begingroup$
    Possible duplicate of Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.
    $endgroup$
    – kobe
    Mar 24 at 17:04










  • $begingroup$
    Thank you for your information
    $endgroup$
    – lio
    Mar 24 at 17:09













0












0








0





$begingroup$


$S$ is domain(open set and connected) and $gamma$ is closed curve in $S$ . If $f(z)$ analytic on $S$ and $f'(z)$ continous on $S$ . Show that $int _gamma overlinef(z)f'(z) dz$ is only imajiner part



I stuck to prove that the real part is zero -__-










share|cite|improve this question









$endgroup$




$S$ is domain(open set and connected) and $gamma$ is closed curve in $S$ . If $f(z)$ analytic on $S$ and $f'(z)$ continous on $S$ . Show that $int _gamma overlinef(z)f'(z) dz$ is only imajiner part



I stuck to prove that the real part is zero -__-







complex-analysis complex-integration






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 24 at 16:51









liolio

20516




20516







  • 2




    $begingroup$
    Possible duplicate of Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.
    $endgroup$
    – kobe
    Mar 24 at 17:04










  • $begingroup$
    Thank you for your information
    $endgroup$
    – lio
    Mar 24 at 17:09












  • 2




    $begingroup$
    Possible duplicate of Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.
    $endgroup$
    – kobe
    Mar 24 at 17:04










  • $begingroup$
    Thank you for your information
    $endgroup$
    – lio
    Mar 24 at 17:09







2




2




$begingroup$
Possible duplicate of Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.
$endgroup$
– kobe
Mar 24 at 17:04




$begingroup$
Possible duplicate of Suppose that $f$ is analytic on a close curve γ. Prove or disprove $int_gamma overlinef(z)f'(z)dz$ is purely imagine.
$endgroup$
– kobe
Mar 24 at 17:04












$begingroup$
Thank you for your information
$endgroup$
– lio
Mar 24 at 17:09




$begingroup$
Thank you for your information
$endgroup$
– lio
Mar 24 at 17:09










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