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Diode in opposite direction?



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Trying to understand flyback diodes and general diode orientationDiode parallel to resistor on H-Bridge MOSFETs gatesQuestion about fly-back diodeWhy is this diode here?Unknown diode identification (27 XD or XD 27 markings)Diode pin labels swapped in this circuit?Why do diode rings multiply?How to solve this diode circuit?NPN driving PNP, Diode from NPN Base to PNP Collector?confused about diode polarity vs circuit polarity



.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;








5












$begingroup$


Its really bothering me that the diode is shown in the opposite direction here and i don't understand why its been put like that? the input voltage will come from the left side of the circuit then why is the diode's cathode connected to the output of the op amp? does the polarity even matter here?



AM radio receiver circuit diagram










share|improve this question









$endgroup$


















    5












    $begingroup$


    Its really bothering me that the diode is shown in the opposite direction here and i don't understand why its been put like that? the input voltage will come from the left side of the circuit then why is the diode's cathode connected to the output of the op amp? does the polarity even matter here?



    AM radio receiver circuit diagram










    share|improve this question









    $endgroup$














      5












      5








      5


      1



      $begingroup$


      Its really bothering me that the diode is shown in the opposite direction here and i don't understand why its been put like that? the input voltage will come from the left side of the circuit then why is the diode's cathode connected to the output of the op amp? does the polarity even matter here?



      AM radio receiver circuit diagram










      share|improve this question









      $endgroup$




      Its really bothering me that the diode is shown in the opposite direction here and i don't understand why its been put like that? the input voltage will come from the left side of the circuit then why is the diode's cathode connected to the output of the op amp? does the polarity even matter here?



      AM radio receiver circuit diagram







      diodes radio receiver






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked Mar 24 at 15:36









      HaidyEHaidyE

      304




      304




















          3 Answers
          3






          active

          oldest

          votes


















          7












          $begingroup$

          In this particular circuit application, the demodulation of amplitude modulated RF, no, the polarity of the diode does not matter. If you reverse the diode, you simply track the positive part of the envelope rather than the negative part. Either will give you the demodulated signal.






          share|improve this answer









          $endgroup$












          • $begingroup$
            will the gain not make a difference then? we use three op amps.
            $endgroup$
            – HaidyE
            Mar 24 at 15:43










          • $begingroup$
            @HaidyE no, I don't understand your comment. Neither gain nor number of opamps used makes a difference to the fact that inverting the polarity of the diode will not have a significant effect on the audio recovered from the RF signal, except that is, the polarity of the recovered signal.
            $endgroup$
            – Neil_UK
            Mar 24 at 15:53










          • $begingroup$
            @HaidyE Your RF "Amp" (between L1C2 and Diode) is an op-amp? A large portion of available opamps haven't much gain available for radio-frequency signals. Audio signals after the detector stage are considered low-frequency, and op-amps have lots of useful gain. That first amplifier really needs a large GBW product (gain x bandwidth)...if you use an op-amp, select carefully for this spec.
            $endgroup$
            – glen_geek
            Mar 24 at 16:01






          • 2




            $begingroup$
            The RF amp may have a open collector output, so the diode would have to have its cathode facing the IC.
            $endgroup$
            – Sparky256
            Mar 24 at 16:01










          • $begingroup$
            i have used 3 op amps with a gain of 5 as i have mentioned before
            $endgroup$
            – HaidyE
            Mar 24 at 16:07


















          10












          $begingroup$

          At the point just before the first amp, the radio waves have been filtered to a particular frequency by L1, C1 & C2. That first amplifier is not an op-amp, it is an RF gain amplifier. It amplifies the incoming signal by a number of dB. The signal before and after will be an AC signal, equally biased around ground.



          The diode or detector gets rid of one half of the signal (either the positive half or the negative half, depending on which way the diode is). Description of AM Detector.



          The next stage filters off the carrier signal with a low-pass filter.



          As the next amp, an op-amp has a bipolar power supply so it can handle either the positive or negative signal. It amplifies the sound waveform for the speaker.






          share|improve this answer











          $endgroup$




















            0












            $begingroup$

            The signal into the diode is a (presumably) AM (amplitude modulated) signal. The variations in amplitude are what is of interest to the listener and are what the amplifier chain is seeking to recover.



            As shown the diode rectifies negative going halves of the signal.

            If reversed it would rectify positive going half cycles.
            Either way, Cd provides a filter that smooths out (and so removes) the RF variations and results in a voltage that varies with the amplitude of the incoming signal. As shown you get negative variations which are smoothed. Reverse the diode and you would get positive going variations. The two are the same except inverted.



            In either case the resultant "envelope" is AC coupled by Cb, and is DC ground referenced by Rb. So EITHER way "Amplifier" "sees" an AC signal centred around ground. This is amplified and, again, AC coupled vi C3 to the headphones.



            So, either way the result is much the same to the end user.






            share|improve this answer









            $endgroup$













              Your Answer






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              3 Answers
              3






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              3 Answers
              3






              active

              oldest

              votes









              active

              oldest

              votes






              active

              oldest

              votes









              7












              $begingroup$

              In this particular circuit application, the demodulation of amplitude modulated RF, no, the polarity of the diode does not matter. If you reverse the diode, you simply track the positive part of the envelope rather than the negative part. Either will give you the demodulated signal.






              share|improve this answer









              $endgroup$












              • $begingroup$
                will the gain not make a difference then? we use three op amps.
                $endgroup$
                – HaidyE
                Mar 24 at 15:43










              • $begingroup$
                @HaidyE no, I don't understand your comment. Neither gain nor number of opamps used makes a difference to the fact that inverting the polarity of the diode will not have a significant effect on the audio recovered from the RF signal, except that is, the polarity of the recovered signal.
                $endgroup$
                – Neil_UK
                Mar 24 at 15:53










              • $begingroup$
                @HaidyE Your RF "Amp" (between L1C2 and Diode) is an op-amp? A large portion of available opamps haven't much gain available for radio-frequency signals. Audio signals after the detector stage are considered low-frequency, and op-amps have lots of useful gain. That first amplifier really needs a large GBW product (gain x bandwidth)...if you use an op-amp, select carefully for this spec.
                $endgroup$
                – glen_geek
                Mar 24 at 16:01






              • 2




                $begingroup$
                The RF amp may have a open collector output, so the diode would have to have its cathode facing the IC.
                $endgroup$
                – Sparky256
                Mar 24 at 16:01










              • $begingroup$
                i have used 3 op amps with a gain of 5 as i have mentioned before
                $endgroup$
                – HaidyE
                Mar 24 at 16:07















              7












              $begingroup$

              In this particular circuit application, the demodulation of amplitude modulated RF, no, the polarity of the diode does not matter. If you reverse the diode, you simply track the positive part of the envelope rather than the negative part. Either will give you the demodulated signal.






              share|improve this answer









              $endgroup$












              • $begingroup$
                will the gain not make a difference then? we use three op amps.
                $endgroup$
                – HaidyE
                Mar 24 at 15:43










              • $begingroup$
                @HaidyE no, I don't understand your comment. Neither gain nor number of opamps used makes a difference to the fact that inverting the polarity of the diode will not have a significant effect on the audio recovered from the RF signal, except that is, the polarity of the recovered signal.
                $endgroup$
                – Neil_UK
                Mar 24 at 15:53










              • $begingroup$
                @HaidyE Your RF "Amp" (between L1C2 and Diode) is an op-amp? A large portion of available opamps haven't much gain available for radio-frequency signals. Audio signals after the detector stage are considered low-frequency, and op-amps have lots of useful gain. That first amplifier really needs a large GBW product (gain x bandwidth)...if you use an op-amp, select carefully for this spec.
                $endgroup$
                – glen_geek
                Mar 24 at 16:01






              • 2




                $begingroup$
                The RF amp may have a open collector output, so the diode would have to have its cathode facing the IC.
                $endgroup$
                – Sparky256
                Mar 24 at 16:01










              • $begingroup$
                i have used 3 op amps with a gain of 5 as i have mentioned before
                $endgroup$
                – HaidyE
                Mar 24 at 16:07













              7












              7








              7





              $begingroup$

              In this particular circuit application, the demodulation of amplitude modulated RF, no, the polarity of the diode does not matter. If you reverse the diode, you simply track the positive part of the envelope rather than the negative part. Either will give you the demodulated signal.






              share|improve this answer









              $endgroup$



              In this particular circuit application, the demodulation of amplitude modulated RF, no, the polarity of the diode does not matter. If you reverse the diode, you simply track the positive part of the envelope rather than the negative part. Either will give you the demodulated signal.







              share|improve this answer












              share|improve this answer



              share|improve this answer










              answered Mar 24 at 15:42









              Neil_UKNeil_UK

              79k285182




              79k285182











              • $begingroup$
                will the gain not make a difference then? we use three op amps.
                $endgroup$
                – HaidyE
                Mar 24 at 15:43










              • $begingroup$
                @HaidyE no, I don't understand your comment. Neither gain nor number of opamps used makes a difference to the fact that inverting the polarity of the diode will not have a significant effect on the audio recovered from the RF signal, except that is, the polarity of the recovered signal.
                $endgroup$
                – Neil_UK
                Mar 24 at 15:53










              • $begingroup$
                @HaidyE Your RF "Amp" (between L1C2 and Diode) is an op-amp? A large portion of available opamps haven't much gain available for radio-frequency signals. Audio signals after the detector stage are considered low-frequency, and op-amps have lots of useful gain. That first amplifier really needs a large GBW product (gain x bandwidth)...if you use an op-amp, select carefully for this spec.
                $endgroup$
                – glen_geek
                Mar 24 at 16:01






              • 2




                $begingroup$
                The RF amp may have a open collector output, so the diode would have to have its cathode facing the IC.
                $endgroup$
                – Sparky256
                Mar 24 at 16:01










              • $begingroup$
                i have used 3 op amps with a gain of 5 as i have mentioned before
                $endgroup$
                – HaidyE
                Mar 24 at 16:07
















              • $begingroup$
                will the gain not make a difference then? we use three op amps.
                $endgroup$
                – HaidyE
                Mar 24 at 15:43










              • $begingroup$
                @HaidyE no, I don't understand your comment. Neither gain nor number of opamps used makes a difference to the fact that inverting the polarity of the diode will not have a significant effect on the audio recovered from the RF signal, except that is, the polarity of the recovered signal.
                $endgroup$
                – Neil_UK
                Mar 24 at 15:53










              • $begingroup$
                @HaidyE Your RF "Amp" (between L1C2 and Diode) is an op-amp? A large portion of available opamps haven't much gain available for radio-frequency signals. Audio signals after the detector stage are considered low-frequency, and op-amps have lots of useful gain. That first amplifier really needs a large GBW product (gain x bandwidth)...if you use an op-amp, select carefully for this spec.
                $endgroup$
                – glen_geek
                Mar 24 at 16:01






              • 2




                $begingroup$
                The RF amp may have a open collector output, so the diode would have to have its cathode facing the IC.
                $endgroup$
                – Sparky256
                Mar 24 at 16:01










              • $begingroup$
                i have used 3 op amps with a gain of 5 as i have mentioned before
                $endgroup$
                – HaidyE
                Mar 24 at 16:07















              $begingroup$
              will the gain not make a difference then? we use three op amps.
              $endgroup$
              – HaidyE
              Mar 24 at 15:43




              $begingroup$
              will the gain not make a difference then? we use three op amps.
              $endgroup$
              – HaidyE
              Mar 24 at 15:43












              $begingroup$
              @HaidyE no, I don't understand your comment. Neither gain nor number of opamps used makes a difference to the fact that inverting the polarity of the diode will not have a significant effect on the audio recovered from the RF signal, except that is, the polarity of the recovered signal.
              $endgroup$
              – Neil_UK
              Mar 24 at 15:53




              $begingroup$
              @HaidyE no, I don't understand your comment. Neither gain nor number of opamps used makes a difference to the fact that inverting the polarity of the diode will not have a significant effect on the audio recovered from the RF signal, except that is, the polarity of the recovered signal.
              $endgroup$
              – Neil_UK
              Mar 24 at 15:53












              $begingroup$
              @HaidyE Your RF "Amp" (between L1C2 and Diode) is an op-amp? A large portion of available opamps haven't much gain available for radio-frequency signals. Audio signals after the detector stage are considered low-frequency, and op-amps have lots of useful gain. That first amplifier really needs a large GBW product (gain x bandwidth)...if you use an op-amp, select carefully for this spec.
              $endgroup$
              – glen_geek
              Mar 24 at 16:01




              $begingroup$
              @HaidyE Your RF "Amp" (between L1C2 and Diode) is an op-amp? A large portion of available opamps haven't much gain available for radio-frequency signals. Audio signals after the detector stage are considered low-frequency, and op-amps have lots of useful gain. That first amplifier really needs a large GBW product (gain x bandwidth)...if you use an op-amp, select carefully for this spec.
              $endgroup$
              – glen_geek
              Mar 24 at 16:01




              2




              2




              $begingroup$
              The RF amp may have a open collector output, so the diode would have to have its cathode facing the IC.
              $endgroup$
              – Sparky256
              Mar 24 at 16:01




              $begingroup$
              The RF amp may have a open collector output, so the diode would have to have its cathode facing the IC.
              $endgroup$
              – Sparky256
              Mar 24 at 16:01












              $begingroup$
              i have used 3 op amps with a gain of 5 as i have mentioned before
              $endgroup$
              – HaidyE
              Mar 24 at 16:07




              $begingroup$
              i have used 3 op amps with a gain of 5 as i have mentioned before
              $endgroup$
              – HaidyE
              Mar 24 at 16:07













              10












              $begingroup$

              At the point just before the first amp, the radio waves have been filtered to a particular frequency by L1, C1 & C2. That first amplifier is not an op-amp, it is an RF gain amplifier. It amplifies the incoming signal by a number of dB. The signal before and after will be an AC signal, equally biased around ground.



              The diode or detector gets rid of one half of the signal (either the positive half or the negative half, depending on which way the diode is). Description of AM Detector.



              The next stage filters off the carrier signal with a low-pass filter.



              As the next amp, an op-amp has a bipolar power supply so it can handle either the positive or negative signal. It amplifies the sound waveform for the speaker.






              share|improve this answer











              $endgroup$

















                10












                $begingroup$

                At the point just before the first amp, the radio waves have been filtered to a particular frequency by L1, C1 & C2. That first amplifier is not an op-amp, it is an RF gain amplifier. It amplifies the incoming signal by a number of dB. The signal before and after will be an AC signal, equally biased around ground.



                The diode or detector gets rid of one half of the signal (either the positive half or the negative half, depending on which way the diode is). Description of AM Detector.



                The next stage filters off the carrier signal with a low-pass filter.



                As the next amp, an op-amp has a bipolar power supply so it can handle either the positive or negative signal. It amplifies the sound waveform for the speaker.






                share|improve this answer











                $endgroup$















                  10












                  10








                  10





                  $begingroup$

                  At the point just before the first amp, the radio waves have been filtered to a particular frequency by L1, C1 & C2. That first amplifier is not an op-amp, it is an RF gain amplifier. It amplifies the incoming signal by a number of dB. The signal before and after will be an AC signal, equally biased around ground.



                  The diode or detector gets rid of one half of the signal (either the positive half or the negative half, depending on which way the diode is). Description of AM Detector.



                  The next stage filters off the carrier signal with a low-pass filter.



                  As the next amp, an op-amp has a bipolar power supply so it can handle either the positive or negative signal. It amplifies the sound waveform for the speaker.






                  share|improve this answer











                  $endgroup$



                  At the point just before the first amp, the radio waves have been filtered to a particular frequency by L1, C1 & C2. That first amplifier is not an op-amp, it is an RF gain amplifier. It amplifies the incoming signal by a number of dB. The signal before and after will be an AC signal, equally biased around ground.



                  The diode or detector gets rid of one half of the signal (either the positive half or the negative half, depending on which way the diode is). Description of AM Detector.



                  The next stage filters off the carrier signal with a low-pass filter.



                  As the next amp, an op-amp has a bipolar power supply so it can handle either the positive or negative signal. It amplifies the sound waveform for the speaker.







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Mar 24 at 20:41









                  SamGibson

                  11.7k41739




                  11.7k41739










                  answered Mar 24 at 17:17









                  TpKnetTpKnet

                  1015




                  1015





















                      0












                      $begingroup$

                      The signal into the diode is a (presumably) AM (amplitude modulated) signal. The variations in amplitude are what is of interest to the listener and are what the amplifier chain is seeking to recover.



                      As shown the diode rectifies negative going halves of the signal.

                      If reversed it would rectify positive going half cycles.
                      Either way, Cd provides a filter that smooths out (and so removes) the RF variations and results in a voltage that varies with the amplitude of the incoming signal. As shown you get negative variations which are smoothed. Reverse the diode and you would get positive going variations. The two are the same except inverted.



                      In either case the resultant "envelope" is AC coupled by Cb, and is DC ground referenced by Rb. So EITHER way "Amplifier" "sees" an AC signal centred around ground. This is amplified and, again, AC coupled vi C3 to the headphones.



                      So, either way the result is much the same to the end user.






                      share|improve this answer









                      $endgroup$

















                        0












                        $begingroup$

                        The signal into the diode is a (presumably) AM (amplitude modulated) signal. The variations in amplitude are what is of interest to the listener and are what the amplifier chain is seeking to recover.



                        As shown the diode rectifies negative going halves of the signal.

                        If reversed it would rectify positive going half cycles.
                        Either way, Cd provides a filter that smooths out (and so removes) the RF variations and results in a voltage that varies with the amplitude of the incoming signal. As shown you get negative variations which are smoothed. Reverse the diode and you would get positive going variations. The two are the same except inverted.



                        In either case the resultant "envelope" is AC coupled by Cb, and is DC ground referenced by Rb. So EITHER way "Amplifier" "sees" an AC signal centred around ground. This is amplified and, again, AC coupled vi C3 to the headphones.



                        So, either way the result is much the same to the end user.






                        share|improve this answer









                        $endgroup$















                          0












                          0








                          0





                          $begingroup$

                          The signal into the diode is a (presumably) AM (amplitude modulated) signal. The variations in amplitude are what is of interest to the listener and are what the amplifier chain is seeking to recover.



                          As shown the diode rectifies negative going halves of the signal.

                          If reversed it would rectify positive going half cycles.
                          Either way, Cd provides a filter that smooths out (and so removes) the RF variations and results in a voltage that varies with the amplitude of the incoming signal. As shown you get negative variations which are smoothed. Reverse the diode and you would get positive going variations. The two are the same except inverted.



                          In either case the resultant "envelope" is AC coupled by Cb, and is DC ground referenced by Rb. So EITHER way "Amplifier" "sees" an AC signal centred around ground. This is amplified and, again, AC coupled vi C3 to the headphones.



                          So, either way the result is much the same to the end user.






                          share|improve this answer









                          $endgroup$



                          The signal into the diode is a (presumably) AM (amplitude modulated) signal. The variations in amplitude are what is of interest to the listener and are what the amplifier chain is seeking to recover.



                          As shown the diode rectifies negative going halves of the signal.

                          If reversed it would rectify positive going half cycles.
                          Either way, Cd provides a filter that smooths out (and so removes) the RF variations and results in a voltage that varies with the amplitude of the incoming signal. As shown you get negative variations which are smoothed. Reverse the diode and you would get positive going variations. The two are the same except inverted.



                          In either case the resultant "envelope" is AC coupled by Cb, and is DC ground referenced by Rb. So EITHER way "Amplifier" "sees" an AC signal centred around ground. This is amplified and, again, AC coupled vi C3 to the headphones.



                          So, either way the result is much the same to the end user.







                          share|improve this answer












                          share|improve this answer



                          share|improve this answer










                          answered Mar 25 at 5:54









                          Russell McMahonRussell McMahon

                          118k9165297




                          118k9165297



























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                              Lowndes Grove History Architecture References Navigation menu32°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661132°48′6″N 79°57′58″W / 32.80167°N 79.96611°W / 32.80167; -79.9661178002500"National Register Information System"Historic houses of South Carolina"Lowndes Grove""+32° 48' 6.00", −79° 57' 58.00""Lowndes Grove, Charleston County (260 St. Margaret St., Charleston)""Lowndes Grove"The Charleston ExpositionIt Happened in South Carolina"Lowndes Grove (House), Saint Margaret Street & Sixth Avenue, Charleston, Charleston County, SC(Photographs)"Plantations of the Carolina Low Countrye