Merging two orthonormal bases without Gram-Schmidt The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Question about Gram-Schmidt algorithm. Orthogonal diagonalization. Does GS conserve eigen-ness propertyUnderstanding the Gram-Schmidt processFinding an Orthonormal Basis using Gram SchmidtGram-Schmidt: Do the sets have some sort of order?Gram-Schmidt Process to find an orthonormal basis for a matrixGram-Schmidt process in Minkowski space $Bbb L^n$.The need for the Gram–Schmidt processthe Inner product of pre-Gram–Schmidt vectors and post-Gram–SchmidtLet $B_1$ be some basis of $mathbbR^3$ and $B_2$ be the ONB produced by $B_1$ after the Gram-schmidt processUsing Gram-Schmidt to Construct orthonormal basis for $mathbbC^k+1$ that includes a unit eigenvector of a matrix

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Merging two orthonormal bases without Gram-Schmidt



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Question about Gram-Schmidt algorithm. Orthogonal diagonalization. Does GS conserve eigen-ness propertyUnderstanding the Gram-Schmidt processFinding an Orthonormal Basis using Gram SchmidtGram-Schmidt: Do the sets have some sort of order?Gram-Schmidt Process to find an orthonormal basis for a matrixGram-Schmidt process in Minkowski space $Bbb L^n$.The need for the Gram–Schmidt processthe Inner product of pre-Gram–Schmidt vectors and post-Gram–SchmidtLet $B_1$ be some basis of $mathbbR^3$ and $B_2$ be the ONB produced by $B_1$ after the Gram-schmidt processUsing Gram-Schmidt to Construct orthonormal basis for $mathbbC^k+1$ that includes a unit eigenvector of a matrix










1












$begingroup$


I have two sets of column vectors: $A = a_1,a_2,dotsc,a_m$ and $B = b_1,b_2,dotsc,b_n$. I have orthornormal basis for both of them individiaully. $u_1,dotsc,u_p$ is an othornormal basis for $A$ and $v_1,dotsc,v_p$ is an othornormal basis for $B$.



Is there a way to find an orthonormal basis for $Acup B$ without using Gram -Schmidt orthogonalization on $u_icup v_i$?.










share|cite|improve this question









$endgroup$











  • $begingroup$
    There are other algorithms.
    $endgroup$
    – user647486
    Mar 24 at 16:31















1












$begingroup$


I have two sets of column vectors: $A = a_1,a_2,dotsc,a_m$ and $B = b_1,b_2,dotsc,b_n$. I have orthornormal basis for both of them individiaully. $u_1,dotsc,u_p$ is an othornormal basis for $A$ and $v_1,dotsc,v_p$ is an othornormal basis for $B$.



Is there a way to find an orthonormal basis for $Acup B$ without using Gram -Schmidt orthogonalization on $u_icup v_i$?.










share|cite|improve this question









$endgroup$











  • $begingroup$
    There are other algorithms.
    $endgroup$
    – user647486
    Mar 24 at 16:31













1












1








1





$begingroup$


I have two sets of column vectors: $A = a_1,a_2,dotsc,a_m$ and $B = b_1,b_2,dotsc,b_n$. I have orthornormal basis for both of them individiaully. $u_1,dotsc,u_p$ is an othornormal basis for $A$ and $v_1,dotsc,v_p$ is an othornormal basis for $B$.



Is there a way to find an orthonormal basis for $Acup B$ without using Gram -Schmidt orthogonalization on $u_icup v_i$?.










share|cite|improve this question









$endgroup$




I have two sets of column vectors: $A = a_1,a_2,dotsc,a_m$ and $B = b_1,b_2,dotsc,b_n$. I have orthornormal basis for both of them individiaully. $u_1,dotsc,u_p$ is an othornormal basis for $A$ and $v_1,dotsc,v_p$ is an othornormal basis for $B$.



Is there a way to find an orthonormal basis for $Acup B$ without using Gram -Schmidt orthogonalization on $u_icup v_i$?.







linear-algebra orthonormal






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 24 at 16:14









dexter04dexter04

1,6851027




1,6851027











  • $begingroup$
    There are other algorithms.
    $endgroup$
    – user647486
    Mar 24 at 16:31
















  • $begingroup$
    There are other algorithms.
    $endgroup$
    – user647486
    Mar 24 at 16:31















$begingroup$
There are other algorithms.
$endgroup$
– user647486
Mar 24 at 16:31




$begingroup$
There are other algorithms.
$endgroup$
– user647486
Mar 24 at 16:31










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