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Why is this plotted summation of two sine functions not eveloped?
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Amplitude versus time producing unexpected patterns.Sum of Sinusoids with Same Frequency = Sinusoid (proof)Why can't I obtain values of Sine/Cosine with $f(x)=sqrt1-x^2?$Discrete-time sinusoids with same frequencyEnvelope of two sine waves interferingIs the limit of $left(sum_i=-n^i=n tanh(x - i)right)-2x$ a sine wave?Superposition of two wavesHow to calculate the angular frequency of a cosine wave and sine wave added together?How to find the phase-shift from the sum of two sines?What does it mean to multiply two sine waves together
$begingroup$
I am simply plotting a sum of two different sine waves:
$$x(t)=asin(omega_0t)+bsin((1+epsilon)omega_0t)$$
According to this article about beat, the sum should be an enveloped sine wave:
However, when I do this myself, the result is different:
I notice the red sum wave simply has the frequency of the higher frequency wave, and its amplitude's pattern follows the amplitude's pattern of the other one, not oscillates between $pm g(t)=pmsqrta^2+b^2+2*a*b*cos(epsilonomega_0*t)$ as it theoretically should be.
Where did I do wrong? Here are the code input for MathStudio:
Slider([b, e], .1, 10, 0.1)
w=1;a=1
Plot(a*sin(w*x), color=PaleGreen)
Plot(b*sin((1+e)*w*x), color=LightBlue)
Plot(a*sin(w*x)+b*sin((1+e)*w*x), color=Crimson)
/*Plot(sqrt(a^2+b^2+2*a*b*cos(e*w*x)) */
trigonometry summation
$endgroup$
add a comment |
$begingroup$
I am simply plotting a sum of two different sine waves:
$$x(t)=asin(omega_0t)+bsin((1+epsilon)omega_0t)$$
According to this article about beat, the sum should be an enveloped sine wave:
However, when I do this myself, the result is different:
I notice the red sum wave simply has the frequency of the higher frequency wave, and its amplitude's pattern follows the amplitude's pattern of the other one, not oscillates between $pm g(t)=pmsqrta^2+b^2+2*a*b*cos(epsilonomega_0*t)$ as it theoretically should be.
Where did I do wrong? Here are the code input for MathStudio:
Slider([b, e], .1, 10, 0.1)
w=1;a=1
Plot(a*sin(w*x), color=PaleGreen)
Plot(b*sin((1+e)*w*x), color=LightBlue)
Plot(a*sin(w*x)+b*sin((1+e)*w*x), color=Crimson)
/*Plot(sqrt(a^2+b^2+2*a*b*cos(e*w*x)) */
trigonometry summation
$endgroup$
$begingroup$
You should see the effect if you make $epsilon << 1$
$endgroup$
– WW1
Jul 1 '17 at 20:41
$begingroup$
When the two sine waves have almost the same frequency you get the upper graph. When one has much lower frequency than the other you get the lower graph.
$endgroup$
– md2perpe
Jul 1 '17 at 23:35
$begingroup$
@WW1 why does that happen? The article uses $epsilon=0.1$, which I also used, but I didn't see the expected result.
$endgroup$
– Ooker
Jul 2 '17 at 4:52
$begingroup$
Why do you say you used the same number as the article? $10 neq 0.1.$ If you have another attempt with the slider at the far left (so that $e = 0.1$) then you should be showing us that attempt instead of the one with $e=10.$
$endgroup$
– David K
Mar 24 at 19:22
$begingroup$
@DavidK sorry. At the time of posting I don't know the importance of $epsilon$, so I just pick a random graph.
$endgroup$
– Ooker
Mar 25 at 0:09
add a comment |
$begingroup$
I am simply plotting a sum of two different sine waves:
$$x(t)=asin(omega_0t)+bsin((1+epsilon)omega_0t)$$
According to this article about beat, the sum should be an enveloped sine wave:
However, when I do this myself, the result is different:
I notice the red sum wave simply has the frequency of the higher frequency wave, and its amplitude's pattern follows the amplitude's pattern of the other one, not oscillates between $pm g(t)=pmsqrta^2+b^2+2*a*b*cos(epsilonomega_0*t)$ as it theoretically should be.
Where did I do wrong? Here are the code input for MathStudio:
Slider([b, e], .1, 10, 0.1)
w=1;a=1
Plot(a*sin(w*x), color=PaleGreen)
Plot(b*sin((1+e)*w*x), color=LightBlue)
Plot(a*sin(w*x)+b*sin((1+e)*w*x), color=Crimson)
/*Plot(sqrt(a^2+b^2+2*a*b*cos(e*w*x)) */
trigonometry summation
$endgroup$
I am simply plotting a sum of two different sine waves:
$$x(t)=asin(omega_0t)+bsin((1+epsilon)omega_0t)$$
According to this article about beat, the sum should be an enveloped sine wave:
However, when I do this myself, the result is different:
I notice the red sum wave simply has the frequency of the higher frequency wave, and its amplitude's pattern follows the amplitude's pattern of the other one, not oscillates between $pm g(t)=pmsqrta^2+b^2+2*a*b*cos(epsilonomega_0*t)$ as it theoretically should be.
Where did I do wrong? Here are the code input for MathStudio:
Slider([b, e], .1, 10, 0.1)
w=1;a=1
Plot(a*sin(w*x), color=PaleGreen)
Plot(b*sin((1+e)*w*x), color=LightBlue)
Plot(a*sin(w*x)+b*sin((1+e)*w*x), color=Crimson)
/*Plot(sqrt(a^2+b^2+2*a*b*cos(e*w*x)) */
trigonometry summation
trigonometry summation
edited Mar 24 at 17:56
J. M. is not a mathematician
61.2k5152291
61.2k5152291
asked Jul 1 '17 at 20:29
OokerOoker
349319
349319
$begingroup$
You should see the effect if you make $epsilon << 1$
$endgroup$
– WW1
Jul 1 '17 at 20:41
$begingroup$
When the two sine waves have almost the same frequency you get the upper graph. When one has much lower frequency than the other you get the lower graph.
$endgroup$
– md2perpe
Jul 1 '17 at 23:35
$begingroup$
@WW1 why does that happen? The article uses $epsilon=0.1$, which I also used, but I didn't see the expected result.
$endgroup$
– Ooker
Jul 2 '17 at 4:52
$begingroup$
Why do you say you used the same number as the article? $10 neq 0.1.$ If you have another attempt with the slider at the far left (so that $e = 0.1$) then you should be showing us that attempt instead of the one with $e=10.$
$endgroup$
– David K
Mar 24 at 19:22
$begingroup$
@DavidK sorry. At the time of posting I don't know the importance of $epsilon$, so I just pick a random graph.
$endgroup$
– Ooker
Mar 25 at 0:09
add a comment |
$begingroup$
You should see the effect if you make $epsilon << 1$
$endgroup$
– WW1
Jul 1 '17 at 20:41
$begingroup$
When the two sine waves have almost the same frequency you get the upper graph. When one has much lower frequency than the other you get the lower graph.
$endgroup$
– md2perpe
Jul 1 '17 at 23:35
$begingroup$
@WW1 why does that happen? The article uses $epsilon=0.1$, which I also used, but I didn't see the expected result.
$endgroup$
– Ooker
Jul 2 '17 at 4:52
$begingroup$
Why do you say you used the same number as the article? $10 neq 0.1.$ If you have another attempt with the slider at the far left (so that $e = 0.1$) then you should be showing us that attempt instead of the one with $e=10.$
$endgroup$
– David K
Mar 24 at 19:22
$begingroup$
@DavidK sorry. At the time of posting I don't know the importance of $epsilon$, so I just pick a random graph.
$endgroup$
– Ooker
Mar 25 at 0:09
$begingroup$
You should see the effect if you make $epsilon << 1$
$endgroup$
– WW1
Jul 1 '17 at 20:41
$begingroup$
You should see the effect if you make $epsilon << 1$
$endgroup$
– WW1
Jul 1 '17 at 20:41
$begingroup$
When the two sine waves have almost the same frequency you get the upper graph. When one has much lower frequency than the other you get the lower graph.
$endgroup$
– md2perpe
Jul 1 '17 at 23:35
$begingroup$
When the two sine waves have almost the same frequency you get the upper graph. When one has much lower frequency than the other you get the lower graph.
$endgroup$
– md2perpe
Jul 1 '17 at 23:35
$begingroup$
@WW1 why does that happen? The article uses $epsilon=0.1$, which I also used, but I didn't see the expected result.
$endgroup$
– Ooker
Jul 2 '17 at 4:52
$begingroup$
@WW1 why does that happen? The article uses $epsilon=0.1$, which I also used, but I didn't see the expected result.
$endgroup$
– Ooker
Jul 2 '17 at 4:52
$begingroup$
Why do you say you used the same number as the article? $10 neq 0.1.$ If you have another attempt with the slider at the far left (so that $e = 0.1$) then you should be showing us that attempt instead of the one with $e=10.$
$endgroup$
– David K
Mar 24 at 19:22
$begingroup$
Why do you say you used the same number as the article? $10 neq 0.1.$ If you have another attempt with the slider at the far left (so that $e = 0.1$) then you should be showing us that attempt instead of the one with $e=10.$
$endgroup$
– David K
Mar 24 at 19:22
$begingroup$
@DavidK sorry. At the time of posting I don't know the importance of $epsilon$, so I just pick a random graph.
$endgroup$
– Ooker
Mar 25 at 0:09
$begingroup$
@DavidK sorry. At the time of posting I don't know the importance of $epsilon$, so I just pick a random graph.
$endgroup$
– Ooker
Mar 25 at 0:09
add a comment |
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$begingroup$
You should see the effect if you make $epsilon << 1$
$endgroup$
– WW1
Jul 1 '17 at 20:41
$begingroup$
When the two sine waves have almost the same frequency you get the upper graph. When one has much lower frequency than the other you get the lower graph.
$endgroup$
– md2perpe
Jul 1 '17 at 23:35
$begingroup$
@WW1 why does that happen? The article uses $epsilon=0.1$, which I also used, but I didn't see the expected result.
$endgroup$
– Ooker
Jul 2 '17 at 4:52
$begingroup$
Why do you say you used the same number as the article? $10 neq 0.1.$ If you have another attempt with the slider at the far left (so that $e = 0.1$) then you should be showing us that attempt instead of the one with $e=10.$
$endgroup$
– David K
Mar 24 at 19:22
$begingroup$
@DavidK sorry. At the time of posting I don't know the importance of $epsilon$, so I just pick a random graph.
$endgroup$
– Ooker
Mar 25 at 0:09