Balls and Boxes The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Calculating the median in the St. Petersburg paradoxIs there a formula that can scale to find linear combinations that equal a sum?Nil and nilpotent restricted lie algebrasAny odd > 1 is the average of three primesRSA Encryption Original Primes $p$ and $q$On the Collatz Conjecture with odd multiplier of five and with the starting value, n_0 = 7.picking a present box with more than one characteristicssI am struggling with eqation/algorith to adjust (normalize) user ratings according to their recency, number and user profile strenght;Improving clarity and argumentation with hard-to-describe combinatorial proof3-Cycles and Twisty Puzzles

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Balls and Boxes



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Calculating the median in the St. Petersburg paradoxIs there a formula that can scale to find linear combinations that equal a sum?Nil and nilpotent restricted lie algebrasAny odd > 1 is the average of three primesRSA Encryption Original Primes $p$ and $q$On the Collatz Conjecture with odd multiplier of five and with the starting value, n_0 = 7.picking a present box with more than one characteristicssI am struggling with eqation/algorith to adjust (normalize) user ratings according to their recency, number and user profile strenght;Improving clarity and argumentation with hard-to-describe combinatorial proof3-Cycles and Twisty Puzzles










7












$begingroup$


Three boxes contain balls. Each box is large enough to contain all balls. We call $bftarget box$, box that receive balls from one of the others boxes. We allow only one process: moving balls from a box to a $bftarget box$ as long as the numbers of balls in the $bftarget box$ doubles.



Show that it is possible, whatever the initial configuration was, to have an empty box after processing.










share|cite|improve this question











$endgroup$











  • $begingroup$
    If the number of balls in the third box doubles at a stage then can we put remaining balls of the second container to the first one so that the second container is empty?
    $endgroup$
    – Sahil Silare
    Feb 14 at 18:18






  • 2




    $begingroup$
    This looks like an interesting question. Please give us some context, such as where it comes from, what you've tried so far, etc. Thanks.
    $endgroup$
    – John Omielan
    Feb 14 at 18:28






  • 1




    $begingroup$
    @almagest The question does appear to be worded weirdly. I think it means that there are three boxes and you are allowed to move balls from one box to another box as long as the number of balls in the target box doubles. Thus I suspect that valid moves are moving two balls from either box 1 or 3 to box 2 and moving two balls from either box 2 or 3 to box 1.
    $endgroup$
    – jgon
    Feb 14 at 22:18






  • 5




    $begingroup$
    I generated some interesting thoughts: the ball transitions between boxes can be expressed as six $3times 3$ matrices operating on $mathbb Z^3$. Since the number of balls is constant, these transformations are pushing around points of the plane $x+y+z=n$ where $n$ is the number of balls. The goal is to push a given point to the edge of the triangle this plane cuts in the first quadrant. Of course, this is all overkill if there is an arithmetic answer, but I couldn't help but try to look at what's happening with the geometry...
    $endgroup$
    – rschwieb
    Feb 15 at 14:24







  • 2




    $begingroup$
    @HAMIDINESOUMARE What would be the point of writing an answer with no solution given? Besides, you have not mentioned anything about your progress, yet.
    $endgroup$
    – rschwieb
    Feb 15 at 17:37
















7












$begingroup$


Three boxes contain balls. Each box is large enough to contain all balls. We call $bftarget box$, box that receive balls from one of the others boxes. We allow only one process: moving balls from a box to a $bftarget box$ as long as the numbers of balls in the $bftarget box$ doubles.



Show that it is possible, whatever the initial configuration was, to have an empty box after processing.










share|cite|improve this question











$endgroup$











  • $begingroup$
    If the number of balls in the third box doubles at a stage then can we put remaining balls of the second container to the first one so that the second container is empty?
    $endgroup$
    – Sahil Silare
    Feb 14 at 18:18






  • 2




    $begingroup$
    This looks like an interesting question. Please give us some context, such as where it comes from, what you've tried so far, etc. Thanks.
    $endgroup$
    – John Omielan
    Feb 14 at 18:28






  • 1




    $begingroup$
    @almagest The question does appear to be worded weirdly. I think it means that there are three boxes and you are allowed to move balls from one box to another box as long as the number of balls in the target box doubles. Thus I suspect that valid moves are moving two balls from either box 1 or 3 to box 2 and moving two balls from either box 2 or 3 to box 1.
    $endgroup$
    – jgon
    Feb 14 at 22:18






  • 5




    $begingroup$
    I generated some interesting thoughts: the ball transitions between boxes can be expressed as six $3times 3$ matrices operating on $mathbb Z^3$. Since the number of balls is constant, these transformations are pushing around points of the plane $x+y+z=n$ where $n$ is the number of balls. The goal is to push a given point to the edge of the triangle this plane cuts in the first quadrant. Of course, this is all overkill if there is an arithmetic answer, but I couldn't help but try to look at what's happening with the geometry...
    $endgroup$
    – rschwieb
    Feb 15 at 14:24







  • 2




    $begingroup$
    @HAMIDINESOUMARE What would be the point of writing an answer with no solution given? Besides, you have not mentioned anything about your progress, yet.
    $endgroup$
    – rschwieb
    Feb 15 at 17:37














7












7








7


6



$begingroup$


Three boxes contain balls. Each box is large enough to contain all balls. We call $bftarget box$, box that receive balls from one of the others boxes. We allow only one process: moving balls from a box to a $bftarget box$ as long as the numbers of balls in the $bftarget box$ doubles.



Show that it is possible, whatever the initial configuration was, to have an empty box after processing.










share|cite|improve this question











$endgroup$




Three boxes contain balls. Each box is large enough to contain all balls. We call $bftarget box$, box that receive balls from one of the others boxes. We allow only one process: moving balls from a box to a $bftarget box$ as long as the numbers of balls in the $bftarget box$ doubles.



Show that it is possible, whatever the initial configuration was, to have an empty box after processing.







abstract-algebra number-theory arithmetic






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 1 at 16:41







HAMIDINE SOUMARE

















asked Feb 14 at 17:48









HAMIDINE SOUMAREHAMIDINE SOUMARE

2,076212




2,076212











  • $begingroup$
    If the number of balls in the third box doubles at a stage then can we put remaining balls of the second container to the first one so that the second container is empty?
    $endgroup$
    – Sahil Silare
    Feb 14 at 18:18






  • 2




    $begingroup$
    This looks like an interesting question. Please give us some context, such as where it comes from, what you've tried so far, etc. Thanks.
    $endgroup$
    – John Omielan
    Feb 14 at 18:28






  • 1




    $begingroup$
    @almagest The question does appear to be worded weirdly. I think it means that there are three boxes and you are allowed to move balls from one box to another box as long as the number of balls in the target box doubles. Thus I suspect that valid moves are moving two balls from either box 1 or 3 to box 2 and moving two balls from either box 2 or 3 to box 1.
    $endgroup$
    – jgon
    Feb 14 at 22:18






  • 5




    $begingroup$
    I generated some interesting thoughts: the ball transitions between boxes can be expressed as six $3times 3$ matrices operating on $mathbb Z^3$. Since the number of balls is constant, these transformations are pushing around points of the plane $x+y+z=n$ where $n$ is the number of balls. The goal is to push a given point to the edge of the triangle this plane cuts in the first quadrant. Of course, this is all overkill if there is an arithmetic answer, but I couldn't help but try to look at what's happening with the geometry...
    $endgroup$
    – rschwieb
    Feb 15 at 14:24







  • 2




    $begingroup$
    @HAMIDINESOUMARE What would be the point of writing an answer with no solution given? Besides, you have not mentioned anything about your progress, yet.
    $endgroup$
    – rschwieb
    Feb 15 at 17:37

















  • $begingroup$
    If the number of balls in the third box doubles at a stage then can we put remaining balls of the second container to the first one so that the second container is empty?
    $endgroup$
    – Sahil Silare
    Feb 14 at 18:18






  • 2




    $begingroup$
    This looks like an interesting question. Please give us some context, such as where it comes from, what you've tried so far, etc. Thanks.
    $endgroup$
    – John Omielan
    Feb 14 at 18:28






  • 1




    $begingroup$
    @almagest The question does appear to be worded weirdly. I think it means that there are three boxes and you are allowed to move balls from one box to another box as long as the number of balls in the target box doubles. Thus I suspect that valid moves are moving two balls from either box 1 or 3 to box 2 and moving two balls from either box 2 or 3 to box 1.
    $endgroup$
    – jgon
    Feb 14 at 22:18






  • 5




    $begingroup$
    I generated some interesting thoughts: the ball transitions between boxes can be expressed as six $3times 3$ matrices operating on $mathbb Z^3$. Since the number of balls is constant, these transformations are pushing around points of the plane $x+y+z=n$ where $n$ is the number of balls. The goal is to push a given point to the edge of the triangle this plane cuts in the first quadrant. Of course, this is all overkill if there is an arithmetic answer, but I couldn't help but try to look at what's happening with the geometry...
    $endgroup$
    – rschwieb
    Feb 15 at 14:24







  • 2




    $begingroup$
    @HAMIDINESOUMARE What would be the point of writing an answer with no solution given? Besides, you have not mentioned anything about your progress, yet.
    $endgroup$
    – rschwieb
    Feb 15 at 17:37
















$begingroup$
If the number of balls in the third box doubles at a stage then can we put remaining balls of the second container to the first one so that the second container is empty?
$endgroup$
– Sahil Silare
Feb 14 at 18:18




$begingroup$
If the number of balls in the third box doubles at a stage then can we put remaining balls of the second container to the first one so that the second container is empty?
$endgroup$
– Sahil Silare
Feb 14 at 18:18




2




2




$begingroup$
This looks like an interesting question. Please give us some context, such as where it comes from, what you've tried so far, etc. Thanks.
$endgroup$
– John Omielan
Feb 14 at 18:28




$begingroup$
This looks like an interesting question. Please give us some context, such as where it comes from, what you've tried so far, etc. Thanks.
$endgroup$
– John Omielan
Feb 14 at 18:28




1




1




$begingroup$
@almagest The question does appear to be worded weirdly. I think it means that there are three boxes and you are allowed to move balls from one box to another box as long as the number of balls in the target box doubles. Thus I suspect that valid moves are moving two balls from either box 1 or 3 to box 2 and moving two balls from either box 2 or 3 to box 1.
$endgroup$
– jgon
Feb 14 at 22:18




$begingroup$
@almagest The question does appear to be worded weirdly. I think it means that there are three boxes and you are allowed to move balls from one box to another box as long as the number of balls in the target box doubles. Thus I suspect that valid moves are moving two balls from either box 1 or 3 to box 2 and moving two balls from either box 2 or 3 to box 1.
$endgroup$
– jgon
Feb 14 at 22:18




5




5




$begingroup$
I generated some interesting thoughts: the ball transitions between boxes can be expressed as six $3times 3$ matrices operating on $mathbb Z^3$. Since the number of balls is constant, these transformations are pushing around points of the plane $x+y+z=n$ where $n$ is the number of balls. The goal is to push a given point to the edge of the triangle this plane cuts in the first quadrant. Of course, this is all overkill if there is an arithmetic answer, but I couldn't help but try to look at what's happening with the geometry...
$endgroup$
– rschwieb
Feb 15 at 14:24





$begingroup$
I generated some interesting thoughts: the ball transitions between boxes can be expressed as six $3times 3$ matrices operating on $mathbb Z^3$. Since the number of balls is constant, these transformations are pushing around points of the plane $x+y+z=n$ where $n$ is the number of balls. The goal is to push a given point to the edge of the triangle this plane cuts in the first quadrant. Of course, this is all overkill if there is an arithmetic answer, but I couldn't help but try to look at what's happening with the geometry...
$endgroup$
– rschwieb
Feb 15 at 14:24





2




2




$begingroup$
@HAMIDINESOUMARE What would be the point of writing an answer with no solution given? Besides, you have not mentioned anything about your progress, yet.
$endgroup$
– rschwieb
Feb 15 at 17:37





$begingroup$
@HAMIDINESOUMARE What would be the point of writing an answer with no solution given? Besides, you have not mentioned anything about your progress, yet.
$endgroup$
– rschwieb
Feb 15 at 17:37











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