Intersecting Integral points $(x,y,z)$ of $3x+5y+4z=45$ and $z^2+xy=15$? The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)An elliptic curve for the multigrade $sum^8 a_n^k = sum^8 b_n^k$ for $k=1,2,3,4,5,9$?How can I intuitively understand the algorithm for finding the integer solutions to $ax+by=c$?“Necessary” condition for Power Diophantine Equation.Determine for what values of $n$ the number $fracn+72n+1$ is an integerA “flowchart” for handling Diophantine equationsPell equation ($x^2 - ny^2 = 1$): Why does $(x_1+y_1sqrt n)^k$ give all solutions?Did Lagrange and/or Lebesgue and/or Lucas solve Ljunggren's equation?Solve $32x^2 -y^2 = 448$Integer points on a hyperbolaPythagorean like Diophantine Equation

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Intersecting Integral points $(x,y,z)$ of $3x+5y+4z=45$ and $z^2+xy=15$?



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)An elliptic curve for the multigrade $sum^8 a_n^k = sum^8 b_n^k$ for $k=1,2,3,4,5,9$?How can I intuitively understand the algorithm for finding the integer solutions to $ax+by=c$?“Necessary” condition for Power Diophantine Equation.Determine for what values of $n$ the number $fracn+72n+1$ is an integerA “flowchart” for handling Diophantine equationsPell equation ($x^2 - ny^2 = 1$): Why does $(x_1+y_1sqrt n)^k$ give all solutions?Did Lagrange and/or Lebesgue and/or Lucas solve Ljunggren's equation?Solve $32x^2 -y^2 = 448$Integer points on a hyperbolaPythagorean like Diophantine Equation










0












$begingroup$


I am trying to find all the intersecting integral points $(x,y,z)$ of the plane $$3x+5y+4z=45$$ and the one-sheeted paraboloid $$z^2+xz=15$$.



I noticed that
$$x=4t-(9-y)$$
$$z=-3t+2(9-y)$$
So I replaced $x,z$. I ended up with the hyperbola $$9 t^2 + 16 t y - 108 t + 5 y^2 - 81 y + 309 = 0$$
which I solved to find infinitely many integral solutions including $$(2,7,1)$$.
My question is: Is there any easier method to find all those points knowing a common intersecting integral point?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    The equation of hyperbola you got, put it in standard form and then you can find all rational (integral) solutions by using this parametrization of hyperbola.
    $endgroup$
    – ersh
    Mar 24 at 16:41










  • $begingroup$
    Thanks for your input. I’ll try it.
    $endgroup$
    – NumThcurious
    Mar 24 at 17:12















0












$begingroup$


I am trying to find all the intersecting integral points $(x,y,z)$ of the plane $$3x+5y+4z=45$$ and the one-sheeted paraboloid $$z^2+xz=15$$.



I noticed that
$$x=4t-(9-y)$$
$$z=-3t+2(9-y)$$
So I replaced $x,z$. I ended up with the hyperbola $$9 t^2 + 16 t y - 108 t + 5 y^2 - 81 y + 309 = 0$$
which I solved to find infinitely many integral solutions including $$(2,7,1)$$.
My question is: Is there any easier method to find all those points knowing a common intersecting integral point?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    The equation of hyperbola you got, put it in standard form and then you can find all rational (integral) solutions by using this parametrization of hyperbola.
    $endgroup$
    – ersh
    Mar 24 at 16:41










  • $begingroup$
    Thanks for your input. I’ll try it.
    $endgroup$
    – NumThcurious
    Mar 24 at 17:12













0












0








0





$begingroup$


I am trying to find all the intersecting integral points $(x,y,z)$ of the plane $$3x+5y+4z=45$$ and the one-sheeted paraboloid $$z^2+xz=15$$.



I noticed that
$$x=4t-(9-y)$$
$$z=-3t+2(9-y)$$
So I replaced $x,z$. I ended up with the hyperbola $$9 t^2 + 16 t y - 108 t + 5 y^2 - 81 y + 309 = 0$$
which I solved to find infinitely many integral solutions including $$(2,7,1)$$.
My question is: Is there any easier method to find all those points knowing a common intersecting integral point?










share|cite|improve this question











$endgroup$




I am trying to find all the intersecting integral points $(x,y,z)$ of the plane $$3x+5y+4z=45$$ and the one-sheeted paraboloid $$z^2+xz=15$$.



I noticed that
$$x=4t-(9-y)$$
$$z=-3t+2(9-y)$$
So I replaced $x,z$. I ended up with the hyperbola $$9 t^2 + 16 t y - 108 t + 5 y^2 - 81 y + 309 = 0$$
which I solved to find infinitely many integral solutions including $$(2,7,1)$$.
My question is: Is there any easier method to find all those points knowing a common intersecting integral point?







diophantine-equations






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 25 at 14:53







NumThcurious

















asked Mar 24 at 16:29









NumThcuriousNumThcurious

1013




1013







  • 1




    $begingroup$
    The equation of hyperbola you got, put it in standard form and then you can find all rational (integral) solutions by using this parametrization of hyperbola.
    $endgroup$
    – ersh
    Mar 24 at 16:41










  • $begingroup$
    Thanks for your input. I’ll try it.
    $endgroup$
    – NumThcurious
    Mar 24 at 17:12












  • 1




    $begingroup$
    The equation of hyperbola you got, put it in standard form and then you can find all rational (integral) solutions by using this parametrization of hyperbola.
    $endgroup$
    – ersh
    Mar 24 at 16:41










  • $begingroup$
    Thanks for your input. I’ll try it.
    $endgroup$
    – NumThcurious
    Mar 24 at 17:12







1




1




$begingroup$
The equation of hyperbola you got, put it in standard form and then you can find all rational (integral) solutions by using this parametrization of hyperbola.
$endgroup$
– ersh
Mar 24 at 16:41




$begingroup$
The equation of hyperbola you got, put it in standard form and then you can find all rational (integral) solutions by using this parametrization of hyperbola.
$endgroup$
– ersh
Mar 24 at 16:41












$begingroup$
Thanks for your input. I’ll try it.
$endgroup$
– NumThcurious
Mar 24 at 17:12




$begingroup$
Thanks for your input. I’ll try it.
$endgroup$
– NumThcurious
Mar 24 at 17:12










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