Cross-fading between 2 values on number lines. The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Simple lowpass frequency responseSpeech processing pre-emphasis: how does it work?Given a signal in the time domain, is there a way to determine a function that produces that signal?Using the FFT to align two instances of the same signalWhich of arithmetic, geometric or harmonic mean is the most appropriate in this case?Negative autocorrelation valuesVisualize signal dropsDerivative of arctangentCorrelation between 2 signals of uneven dimensionsDiscrete Representations of Continuous Surfaces
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Cross-fading between 2 values on number lines.
The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Simple lowpass frequency responseSpeech processing pre-emphasis: how does it work?Given a signal in the time domain, is there a way to determine a function that produces that signal?Using the FFT to align two instances of the same signalWhich of arithmetic, geometric or harmonic mean is the most appropriate in this case?Negative autocorrelation valuesVisualize signal dropsDerivative of arctangentCorrelation between 2 signals of uneven dimensionsDiscrete Representations of Continuous Surfaces
$begingroup$
Background:
I'm working on writing a software application where I need to cross fade between 2 digital audio signals. In the software I have 4 variables that play a role:
float sampleA; //The value of signal A in this very instant (values from -1 to 1).
float sampleB; //The value of signal B in this very instant (values from -1 to 1).
float index; //The index of the crossfade in this very instant (values from 0 to 1).
float result; //The resulting value of the signal after the crossfade is applied.
However I have no idea how I would achieve this crossfade.
Problem Description:
I've decided to make a visual representation of the problem:
As you can see we have 3 number lines A(blue), B(red), and i(green). A and B represent the 2 floating point values of sampleA and sampleB which can vary between 1 and -1 while i is the crossfade index, a value which determines how far into the crossfade we are. Now what I've done is I've added some values for A, B and i on their respective numberlines and I've connected the points for A and B with a line.
If we then project the value of i on the line between point A and B we get a new point, Let's call this point R. If we project point R on either the numberline for A or B we can then get the final result.
Problem:
What is a formula which I can use, given a value for A, B and i, to calculate the value of R projected on the numberline?
signal-processing
asked Mar 24 at 16:09
BRHSMBRHSM
1053
$endgroup$
add a comment |
$begingroup$
Background:
I'm working on writing a software application where I need to cross fade between 2 digital audio signals. In the software I have 4 variables that play a role:
float sampleA; //The value of signal A in this very instant (values from -1 to 1).
float sampleB; //The value of signal B in this very instant (values from -1 to 1).
float index; //The index of the crossfade in this very instant (values from 0 to 1).
float result; //The resulting value of the signal after the crossfade is applied.
However I have no idea how I would achieve this crossfade.
Problem Description:
I've decided to make a visual representation of the problem:
As you can see we have 3 number lines A(blue), B(red), and i(green). A and B represent the 2 floating point values of sampleA and sampleB which can vary between 1 and -1 while i is the crossfade index, a value which determines how far into the crossfade we are. Now what I've done is I've added some values for A, B and i on their respective numberlines and I've connected the points for A and B with a line.
If we then project the value of i on the line between point A and B we get a new point, Let's call this point R. If we project point R on either the numberline for A or B we can then get the final result.
Problem:
What is a formula which I can use, given a value for A, B and i, to calculate the value of R projected on the numberline?
signal-processing
asked Mar 24 at 16:09
BRHSMBRHSM
1053
$endgroup$
$begingroup$
This is often called a "reset" or a "linear reset" in programming languages which support it. Since your input and output ranges are of equal length, some of the math can be simplified.
$endgroup$
– abiessu
Mar 24 at 16:16
$begingroup$
@abiessu i know about things like remapping but i don't know how that can help here, i tried looking around google for the linear reset or reset thing you mentiond but I can't seem to find any relevant information
$endgroup$
– BRHSM
Mar 24 at 17:21
add a comment |
$begingroup$
Background:
I'm working on writing a software application where I need to cross fade between 2 digital audio signals. In the software I have 4 variables that play a role:
float sampleA; //The value of signal A in this very instant (values from -1 to 1).
float sampleB; //The value of signal B in this very instant (values from -1 to 1).
float index; //The index of the crossfade in this very instant (values from 0 to 1).
float result; //The resulting value of the signal after the crossfade is applied.
However I have no idea how I would achieve this crossfade.
Problem Description:
I've decided to make a visual representation of the problem:
As you can see we have 3 number lines A(blue), B(red), and i(green). A and B represent the 2 floating point values of sampleA and sampleB which can vary between 1 and -1 while i is the crossfade index, a value which determines how far into the crossfade we are. Now what I've done is I've added some values for A, B and i on their respective numberlines and I've connected the points for A and B with a line.
If we then project the value of i on the line between point A and B we get a new point, Let's call this point R. If we project point R on either the numberline for A or B we can then get the final result.
Problem:
What is a formula which I can use, given a value for A, B and i, to calculate the value of R projected on the numberline?
signal-processing
asked Mar 24 at 16:09
BRHSMBRHSM
1053
$endgroup$
Background:
I'm working on writing a software application where I need to cross fade between 2 digital audio signals. In the software I have 4 variables that play a role:
float sampleA; //The value of signal A in this very instant (values from -1 to 1).
float sampleB; //The value of signal B in this very instant (values from -1 to 1).
float index; //The index of the crossfade in this very instant (values from 0 to 1).
float result; //The resulting value of the signal after the crossfade is applied.
However I have no idea how I would achieve this crossfade.
Problem Description:
I've decided to make a visual representation of the problem:
As you can see we have 3 number lines A(blue), B(red), and i(green). A and B represent the 2 floating point values of sampleA and sampleB which can vary between 1 and -1 while i is the crossfade index, a value which determines how far into the crossfade we are. Now what I've done is I've added some values for A, B and i on their respective numberlines and I've connected the points for A and B with a line.
If we then project the value of i on the line between point A and B we get a new point, Let's call this point R. If we project point R on either the numberline for A or B we can then get the final result.
Problem:
What is a formula which I can use, given a value for A, B and i, to calculate the value of R projected on the numberline?
signal-processing
signal-processing
asked Mar 24 at 16:09
BRHSMBRHSM
1053
asked Mar 24 at 16:09
BRHSMBRHSM
1053
asked Mar 24 at 16:09
BRHSMBRHSM
1053
asked Mar 24 at 16:09
BRHSMBRHSM
1053
asked Mar 24 at 16:09
BRHSMBRHSM
1053
1053
$begingroup$
This is often called a "reset" or a "linear reset" in programming languages which support it. Since your input and output ranges are of equal length, some of the math can be simplified.
$endgroup$
– abiessu
Mar 24 at 16:16
$begingroup$
@abiessu i know about things like remapping but i don't know how that can help here, i tried looking around google for the linear reset or reset thing you mentiond but I can't seem to find any relevant information
$endgroup$
– BRHSM
Mar 24 at 17:21
add a comment |
$begingroup$
This is often called a "reset" or a "linear reset" in programming languages which support it. Since your input and output ranges are of equal length, some of the math can be simplified.
$endgroup$
– abiessu
Mar 24 at 16:16
$begingroup$
@abiessu i know about things like remapping but i don't know how that can help here, i tried looking around google for the linear reset or reset thing you mentiond but I can't seem to find any relevant information
$endgroup$
– BRHSM
Mar 24 at 17:21
$begingroup$
This is often called a "reset" or a "linear reset" in programming languages which support it. Since your input and output ranges are of equal length, some of the math can be simplified.
$endgroup$
– abiessu
Mar 24 at 16:16
$begingroup$
This is often called a "reset" or a "linear reset" in programming languages which support it. Since your input and output ranges are of equal length, some of the math can be simplified.
$endgroup$
– abiessu
Mar 24 at 16:16
$begingroup$
@abiessu i know about things like remapping but i don't know how that can help here, i tried looking around google for the linear reset or reset thing you mentiond but I can't seem to find any relevant information
$endgroup$
– BRHSM
Mar 24 at 17:21
$begingroup$
@abiessu i know about things like remapping but i don't know how that can help here, i tried looking around google for the linear reset or reset thing you mentiond but I can't seem to find any relevant information
$endgroup$
– BRHSM
Mar 24 at 17:21
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
From the visual I interpret this as
$$R=a+i(b-a)$$
because the value of $R$ is equal to that of $a$ plus some fraction $i$ of the difference between $b$ and $a$.
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
$endgroup$
$begingroup$
I'm not getting the desired output i want so let me play with it some more and see if i can get this to work!
$endgroup$
– BRHSM
Mar 24 at 17:19
add a comment |
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
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active
oldest
votes
$begingroup$
From the visual I interpret this as
$$R=a+i(b-a)$$
because the value of $R$ is equal to that of $a$ plus some fraction $i$ of the difference between $b$ and $a$.
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
$endgroup$
$begingroup$
I'm not getting the desired output i want so let me play with it some more and see if i can get this to work!
$endgroup$
– BRHSM
Mar 24 at 17:19
add a comment |
$begingroup$
From the visual I interpret this as
$$R=a+i(b-a)$$
because the value of $R$ is equal to that of $a$ plus some fraction $i$ of the difference between $b$ and $a$.
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
$endgroup$
$begingroup$
I'm not getting the desired output i want so let me play with it some more and see if i can get this to work!
$endgroup$
– BRHSM
Mar 24 at 17:19
add a comment |
$begingroup$
From the visual I interpret this as
$$R=a+i(b-a)$$
because the value of $R$ is equal to that of $a$ plus some fraction $i$ of the difference between $b$ and $a$.
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
$endgroup$
From the visual I interpret this as
$$R=a+i(b-a)$$
because the value of $R$ is equal to that of $a$ plus some fraction $i$ of the difference between $b$ and $a$.
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
answered Mar 24 at 16:19
Peter ForemanPeter Foreman
7,1841318
7,1841318
$begingroup$
I'm not getting the desired output i want so let me play with it some more and see if i can get this to work!
$endgroup$
– BRHSM
Mar 24 at 17:19
add a comment |
$begingroup$
I'm not getting the desired output i want so let me play with it some more and see if i can get this to work!
$endgroup$
– BRHSM
Mar 24 at 17:19
$begingroup$
I'm not getting the desired output i want so let me play with it some more and see if i can get this to work!
$endgroup$
– BRHSM
Mar 24 at 17:19
$begingroup$
I'm not getting the desired output i want so let me play with it some more and see if i can get this to work!
$endgroup$
– BRHSM
Mar 24 at 17:19
add a comment |
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$begingroup$
This is often called a "reset" or a "linear reset" in programming languages which support it. Since your input and output ranges are of equal length, some of the math can be simplified.
$endgroup$
– abiessu
Mar 24 at 16:16
$begingroup$
@abiessu i know about things like remapping but i don't know how that can help here, i tried looking around google for the linear reset or reset thing you mentiond but I can't seem to find any relevant information
$endgroup$
– BRHSM
Mar 24 at 17:21