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How to prove a Markov chain is irreducible in general?
Irreducible Markov chainMarkov chain monte carloWhat is the difference between a reversible markov chain and a reversible in equilibrium markov chain?How to prove irreducible and aperiodic Markov chain is regularIs $X_n$ a Markov chain?Does product Markov chain hit diagonal?Is it true that a irreducible, recurrent markov chain with nonzero stationary distribution tends to stay in the same state?Are the stationary probabilities of an irreducible Markov chain zero, infinite or something else?Harmonic functions on an irreducible recurrent Markov chain are constantLet $Y_n=X_3n.$ Show that $Y_0,Y_1,…$ is a Markov chain.
$begingroup$
Consider the following example:
Given a random variable $X_n$ is $Markov(pi,P)$, where $P$ is irreducible and has an stationary distribution $pi$.
Then I can show that the time reversal of $X_n$, $Y_n=X_N-n$ is also a Markov chain. with transition probability $$P(Y_n+1=j|Y_n=i)=hatp_ij=fracpi_jp_jipi_i$$
However, is the Markov chain for $Y_n$ also irreducible?
My reasoningss:
From definition, In order to prove irreducibility I need to show that
$$P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$$ for some $n>0$
The only thing I can think of now is
beginalign
P(Y_n=j | Y_0=i)&=hatp_ik_1hatp_k_1k_2hatp_k_2k_3...hatp_k_n-1j\& = fracpi_k_1p_k_1ipi_ifracpi_k_2p_k_2k_1pi_k_1fracpi_k_3p_k_3k_2pi_k_2...fracpi_jp_jk_n-1pi_k_n-1\
&=fracpi_jp^(n)_jipi_iendalign
Since the Markov chain for $X_n$ is irreducible, we know that $p^(n)_ji>0$ for some $n$. However, I cannot argue $pi_i$ and $pi_j$ are always greater than $0$, so we are not 100% sure that $P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$, since it is possible that $pi_i=0$ or $pi_j=0$ for some $i$ and $j$.
So, how do we show that a Markov chain is irreducible in general? What am I missing here?
proof-verification proof-writing stochastic-processes markov-chains
$endgroup$
add a comment |
$begingroup$
Consider the following example:
Given a random variable $X_n$ is $Markov(pi,P)$, where $P$ is irreducible and has an stationary distribution $pi$.
Then I can show that the time reversal of $X_n$, $Y_n=X_N-n$ is also a Markov chain. with transition probability $$P(Y_n+1=j|Y_n=i)=hatp_ij=fracpi_jp_jipi_i$$
However, is the Markov chain for $Y_n$ also irreducible?
My reasoningss:
From definition, In order to prove irreducibility I need to show that
$$P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$$ for some $n>0$
The only thing I can think of now is
beginalign
P(Y_n=j | Y_0=i)&=hatp_ik_1hatp_k_1k_2hatp_k_2k_3...hatp_k_n-1j\& = fracpi_k_1p_k_1ipi_ifracpi_k_2p_k_2k_1pi_k_1fracpi_k_3p_k_3k_2pi_k_2...fracpi_jp_jk_n-1pi_k_n-1\
&=fracpi_jp^(n)_jipi_iendalign
Since the Markov chain for $X_n$ is irreducible, we know that $p^(n)_ji>0$ for some $n$. However, I cannot argue $pi_i$ and $pi_j$ are always greater than $0$, so we are not 100% sure that $P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$, since it is possible that $pi_i=0$ or $pi_j=0$ for some $i$ and $j$.
So, how do we show that a Markov chain is irreducible in general? What am I missing here?
proof-verification proof-writing stochastic-processes markov-chains
$endgroup$
1
$begingroup$
"However, I cannot argue $π_i$ and $π_j$ are always greater than $0$" - actually you can, because $X_n$ is irreducible. If $pi$ is an stationary distribution, then a state $i$ is transient if and only if $pi_i=0$. An irreducible Markov chain either has all recurrent states or all transient states.
$endgroup$
– Math1000
yesterday
$begingroup$
Just to double confirm your last statement. Since "if the chain is irreducible, then either all states are recurrent or all are transient." If all states are transient, then the stationary distribution wouldn't exist. So, it should be an irreducible stationary Markov chain has no transient states, am I right?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
You are correct.
$endgroup$
– Math1000
yesterday
1
$begingroup$
There's so many concepts in Markov chain. If I don't know which concept to use, I can get stuck for hours. However, once someone points out which concept to use, it will suddenly become so obviously. Any tips to be so clear about Markov chain? btw, I like your profile pic, it's a Markov chain, isn't it?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
Yes, I got the picture from Wikipedia :)
$endgroup$
– Math1000
yesterday
add a comment |
$begingroup$
Consider the following example:
Given a random variable $X_n$ is $Markov(pi,P)$, where $P$ is irreducible and has an stationary distribution $pi$.
Then I can show that the time reversal of $X_n$, $Y_n=X_N-n$ is also a Markov chain. with transition probability $$P(Y_n+1=j|Y_n=i)=hatp_ij=fracpi_jp_jipi_i$$
However, is the Markov chain for $Y_n$ also irreducible?
My reasoningss:
From definition, In order to prove irreducibility I need to show that
$$P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$$ for some $n>0$
The only thing I can think of now is
beginalign
P(Y_n=j | Y_0=i)&=hatp_ik_1hatp_k_1k_2hatp_k_2k_3...hatp_k_n-1j\& = fracpi_k_1p_k_1ipi_ifracpi_k_2p_k_2k_1pi_k_1fracpi_k_3p_k_3k_2pi_k_2...fracpi_jp_jk_n-1pi_k_n-1\
&=fracpi_jp^(n)_jipi_iendalign
Since the Markov chain for $X_n$ is irreducible, we know that $p^(n)_ji>0$ for some $n$. However, I cannot argue $pi_i$ and $pi_j$ are always greater than $0$, so we are not 100% sure that $P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$, since it is possible that $pi_i=0$ or $pi_j=0$ for some $i$ and $j$.
So, how do we show that a Markov chain is irreducible in general? What am I missing here?
proof-verification proof-writing stochastic-processes markov-chains
$endgroup$
Consider the following example:
Given a random variable $X_n$ is $Markov(pi,P)$, where $P$ is irreducible and has an stationary distribution $pi$.
Then I can show that the time reversal of $X_n$, $Y_n=X_N-n$ is also a Markov chain. with transition probability $$P(Y_n+1=j|Y_n=i)=hatp_ij=fracpi_jp_jipi_i$$
However, is the Markov chain for $Y_n$ also irreducible?
My reasoningss:
From definition, In order to prove irreducibility I need to show that
$$P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$$ for some $n>0$
The only thing I can think of now is
beginalign
P(Y_n=j | Y_0=i)&=hatp_ik_1hatp_k_1k_2hatp_k_2k_3...hatp_k_n-1j\& = fracpi_k_1p_k_1ipi_ifracpi_k_2p_k_2k_1pi_k_1fracpi_k_3p_k_3k_2pi_k_2...fracpi_jp_jk_n-1pi_k_n-1\
&=fracpi_jp^(n)_jipi_iendalign
Since the Markov chain for $X_n$ is irreducible, we know that $p^(n)_ji>0$ for some $n$. However, I cannot argue $pi_i$ and $pi_j$ are always greater than $0$, so we are not 100% sure that $P(Y_n=j | Y_0=i)=hatp^(n)_ij>0$, since it is possible that $pi_i=0$ or $pi_j=0$ for some $i$ and $j$.
So, how do we show that a Markov chain is irreducible in general? What am I missing here?
proof-verification proof-writing stochastic-processes markov-chains
proof-verification proof-writing stochastic-processes markov-chains
edited yesterday
Raven Cheuk
asked yesterday
Raven CheukRaven Cheuk
1186
1186
1
$begingroup$
"However, I cannot argue $π_i$ and $π_j$ are always greater than $0$" - actually you can, because $X_n$ is irreducible. If $pi$ is an stationary distribution, then a state $i$ is transient if and only if $pi_i=0$. An irreducible Markov chain either has all recurrent states or all transient states.
$endgroup$
– Math1000
yesterday
$begingroup$
Just to double confirm your last statement. Since "if the chain is irreducible, then either all states are recurrent or all are transient." If all states are transient, then the stationary distribution wouldn't exist. So, it should be an irreducible stationary Markov chain has no transient states, am I right?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
You are correct.
$endgroup$
– Math1000
yesterday
1
$begingroup$
There's so many concepts in Markov chain. If I don't know which concept to use, I can get stuck for hours. However, once someone points out which concept to use, it will suddenly become so obviously. Any tips to be so clear about Markov chain? btw, I like your profile pic, it's a Markov chain, isn't it?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
Yes, I got the picture from Wikipedia :)
$endgroup$
– Math1000
yesterday
add a comment |
1
$begingroup$
"However, I cannot argue $π_i$ and $π_j$ are always greater than $0$" - actually you can, because $X_n$ is irreducible. If $pi$ is an stationary distribution, then a state $i$ is transient if and only if $pi_i=0$. An irreducible Markov chain either has all recurrent states or all transient states.
$endgroup$
– Math1000
yesterday
$begingroup$
Just to double confirm your last statement. Since "if the chain is irreducible, then either all states are recurrent or all are transient." If all states are transient, then the stationary distribution wouldn't exist. So, it should be an irreducible stationary Markov chain has no transient states, am I right?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
You are correct.
$endgroup$
– Math1000
yesterday
1
$begingroup$
There's so many concepts in Markov chain. If I don't know which concept to use, I can get stuck for hours. However, once someone points out which concept to use, it will suddenly become so obviously. Any tips to be so clear about Markov chain? btw, I like your profile pic, it's a Markov chain, isn't it?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
Yes, I got the picture from Wikipedia :)
$endgroup$
– Math1000
yesterday
1
1
$begingroup$
"However, I cannot argue $π_i$ and $π_j$ are always greater than $0$" - actually you can, because $X_n$ is irreducible. If $pi$ is an stationary distribution, then a state $i$ is transient if and only if $pi_i=0$. An irreducible Markov chain either has all recurrent states or all transient states.
$endgroup$
– Math1000
yesterday
$begingroup$
"However, I cannot argue $π_i$ and $π_j$ are always greater than $0$" - actually you can, because $X_n$ is irreducible. If $pi$ is an stationary distribution, then a state $i$ is transient if and only if $pi_i=0$. An irreducible Markov chain either has all recurrent states or all transient states.
$endgroup$
– Math1000
yesterday
$begingroup$
Just to double confirm your last statement. Since "if the chain is irreducible, then either all states are recurrent or all are transient." If all states are transient, then the stationary distribution wouldn't exist. So, it should be an irreducible stationary Markov chain has no transient states, am I right?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
Just to double confirm your last statement. Since "if the chain is irreducible, then either all states are recurrent or all are transient." If all states are transient, then the stationary distribution wouldn't exist. So, it should be an irreducible stationary Markov chain has no transient states, am I right?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
You are correct.
$endgroup$
– Math1000
yesterday
$begingroup$
You are correct.
$endgroup$
– Math1000
yesterday
1
1
$begingroup$
There's so many concepts in Markov chain. If I don't know which concept to use, I can get stuck for hours. However, once someone points out which concept to use, it will suddenly become so obviously. Any tips to be so clear about Markov chain? btw, I like your profile pic, it's a Markov chain, isn't it?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
There's so many concepts in Markov chain. If I don't know which concept to use, I can get stuck for hours. However, once someone points out which concept to use, it will suddenly become so obviously. Any tips to be so clear about Markov chain? btw, I like your profile pic, it's a Markov chain, isn't it?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
Yes, I got the picture from Wikipedia :)
$endgroup$
– Math1000
yesterday
$begingroup$
Yes, I got the picture from Wikipedia :)
$endgroup$
– Math1000
yesterday
add a comment |
0
active
oldest
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$begingroup$
"However, I cannot argue $π_i$ and $π_j$ are always greater than $0$" - actually you can, because $X_n$ is irreducible. If $pi$ is an stationary distribution, then a state $i$ is transient if and only if $pi_i=0$. An irreducible Markov chain either has all recurrent states or all transient states.
$endgroup$
– Math1000
yesterday
$begingroup$
Just to double confirm your last statement. Since "if the chain is irreducible, then either all states are recurrent or all are transient." If all states are transient, then the stationary distribution wouldn't exist. So, it should be an irreducible stationary Markov chain has no transient states, am I right?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
You are correct.
$endgroup$
– Math1000
yesterday
1
$begingroup$
There's so many concepts in Markov chain. If I don't know which concept to use, I can get stuck for hours. However, once someone points out which concept to use, it will suddenly become so obviously. Any tips to be so clear about Markov chain? btw, I like your profile pic, it's a Markov chain, isn't it?
$endgroup$
– Raven Cheuk
yesterday
$begingroup$
Yes, I got the picture from Wikipedia :)
$endgroup$
– Math1000
yesterday