Using linearization to calculate the thickness of a layer of paint on a spherical ballCalculate the fraction of volume of a rectilinear grid cell within some radius of the originVolume of a sphere “corner”What is the volume of the sphere in hyperbolic space?How to write the volume element for a spherical shell?How to calculate the volume of intersection of sphere and cylinderVolume of part (not necessary the half) of spherical capcomputing volume of unit ball in n-dimensions using polar coordinatesWhat will the volume of the ball bearing be?Calculus related rates snowball radius problemWidth of layer formed from sphere $r = n$ fitted inside sphere $r = 4n$

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Using linearization to calculate the thickness of a layer of paint on a spherical ball


Calculate the fraction of volume of a rectilinear grid cell within some radius of the originVolume of a sphere “corner”What is the volume of the sphere in hyperbolic space?How to write the volume element for a spherical shell?How to calculate the volume of intersection of sphere and cylinderVolume of part (not necessary the half) of spherical capcomputing volume of unit ball in n-dimensions using polar coordinatesWhat will the volume of the ball bearing be?Calculus related rates snowball radius problemWidth of layer formed from sphere $r = n$ fitted inside sphere $r = 4n$













0












$begingroup$


The volume of a sphere with radius $r$ is given by the formula $V(r) = frac4 pi3 r^3$.



a) If $a$ is a given fixed value for $r$, write the formula for the linearization of the volume function $V(r)$ at $a$.



b) Use this linearization to calculate the thickness $Delta r$ (in $cm$) of a layer of paint on the surface of a spherical ball with radius $r=52cm$ if the total volume of paint used is $340cm^3$.



The first part is easy to calculate, but I don't know exactly how to get the second part?










share|cite|improve this question









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bumped to the homepage by Community yesterday


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    0












    $begingroup$


    The volume of a sphere with radius $r$ is given by the formula $V(r) = frac4 pi3 r^3$.



    a) If $a$ is a given fixed value for $r$, write the formula for the linearization of the volume function $V(r)$ at $a$.



    b) Use this linearization to calculate the thickness $Delta r$ (in $cm$) of a layer of paint on the surface of a spherical ball with radius $r=52cm$ if the total volume of paint used is $340cm^3$.



    The first part is easy to calculate, but I don't know exactly how to get the second part?










    share|cite|improve this question









    $endgroup$




    bumped to the homepage by Community yesterday


    This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.

















      0












      0








      0





      $begingroup$


      The volume of a sphere with radius $r$ is given by the formula $V(r) = frac4 pi3 r^3$.



      a) If $a$ is a given fixed value for $r$, write the formula for the linearization of the volume function $V(r)$ at $a$.



      b) Use this linearization to calculate the thickness $Delta r$ (in $cm$) of a layer of paint on the surface of a spherical ball with radius $r=52cm$ if the total volume of paint used is $340cm^3$.



      The first part is easy to calculate, but I don't know exactly how to get the second part?










      share|cite|improve this question









      $endgroup$




      The volume of a sphere with radius $r$ is given by the formula $V(r) = frac4 pi3 r^3$.



      a) If $a$ is a given fixed value for $r$, write the formula for the linearization of the volume function $V(r)$ at $a$.



      b) Use this linearization to calculate the thickness $Delta r$ (in $cm$) of a layer of paint on the surface of a spherical ball with radius $r=52cm$ if the total volume of paint used is $340cm^3$.



      The first part is easy to calculate, but I don't know exactly how to get the second part?







      derivatives volume linear-approximation






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Dec 11 '15 at 15:41









      Essi A.Essi A.

      61




      61





      bumped to the homepage by Community yesterday


      This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.







      bumped to the homepage by Community yesterday


      This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.






















          1 Answer
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          0












          $begingroup$

          The volume $Delta V$ of paint is approximatively given by
          $$Delta V=V(a+Delta r)-V(a)doteq V'(a)>Delta r=4pi a^2>Delta r .tag1$$
          In your problem the unknown is the thickness $Delta r$ of the paint layer. From $(1)$ we immediately get
          $$Delta rdoteqDelta Vover 4pi>a^2 .$$






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            thanks a lot for the quick reply
            $endgroup$
            – Essi A.
            Dec 12 '15 at 4:14










          Your Answer





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          1 Answer
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          1 Answer
          1






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          active

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          active

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          0












          $begingroup$

          The volume $Delta V$ of paint is approximatively given by
          $$Delta V=V(a+Delta r)-V(a)doteq V'(a)>Delta r=4pi a^2>Delta r .tag1$$
          In your problem the unknown is the thickness $Delta r$ of the paint layer. From $(1)$ we immediately get
          $$Delta rdoteqDelta Vover 4pi>a^2 .$$






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            thanks a lot for the quick reply
            $endgroup$
            – Essi A.
            Dec 12 '15 at 4:14















          0












          $begingroup$

          The volume $Delta V$ of paint is approximatively given by
          $$Delta V=V(a+Delta r)-V(a)doteq V'(a)>Delta r=4pi a^2>Delta r .tag1$$
          In your problem the unknown is the thickness $Delta r$ of the paint layer. From $(1)$ we immediately get
          $$Delta rdoteqDelta Vover 4pi>a^2 .$$






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            thanks a lot for the quick reply
            $endgroup$
            – Essi A.
            Dec 12 '15 at 4:14













          0












          0








          0





          $begingroup$

          The volume $Delta V$ of paint is approximatively given by
          $$Delta V=V(a+Delta r)-V(a)doteq V'(a)>Delta r=4pi a^2>Delta r .tag1$$
          In your problem the unknown is the thickness $Delta r$ of the paint layer. From $(1)$ we immediately get
          $$Delta rdoteqDelta Vover 4pi>a^2 .$$






          share|cite|improve this answer









          $endgroup$



          The volume $Delta V$ of paint is approximatively given by
          $$Delta V=V(a+Delta r)-V(a)doteq V'(a)>Delta r=4pi a^2>Delta r .tag1$$
          In your problem the unknown is the thickness $Delta r$ of the paint layer. From $(1)$ we immediately get
          $$Delta rdoteqDelta Vover 4pi>a^2 .$$







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 11 '15 at 21:21









          Christian BlatterChristian Blatter

          175k8115327




          175k8115327











          • $begingroup$
            thanks a lot for the quick reply
            $endgroup$
            – Essi A.
            Dec 12 '15 at 4:14
















          • $begingroup$
            thanks a lot for the quick reply
            $endgroup$
            – Essi A.
            Dec 12 '15 at 4:14















          $begingroup$
          thanks a lot for the quick reply
          $endgroup$
          – Essi A.
          Dec 12 '15 at 4:14




          $begingroup$
          thanks a lot for the quick reply
          $endgroup$
          – Essi A.
          Dec 12 '15 at 4:14

















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