Compute $iint_S xz^2dydz+yz^2dzdx+z^3dxdy$Outward Flux of a Divergenceless Vector Field on an EllipsoidSurface integral over an inconvenient surfaceWhat does $iint_S (hatmathbfn times nabla psi) ; dS$ mean?Surface integral problem $displaystyleiint_Sx^2dS$Evaluating the surface integral side of a divergence theorem problemChange of Variable vs ParametrizationHow to calculate the integral on surface which cannot be expressed in functions easily?Heat flow surface integral problemsurface integral of angle between fixed vector and the unit normalSurface integral with cylinder-form surface.

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Compute $iint_S xz^2dydz+yz^2dzdx+z^3dxdy$


Outward Flux of a Divergenceless Vector Field on an EllipsoidSurface integral over an inconvenient surfaceWhat does $iint_S (hatmathbfn times nabla psi) ; dS$ mean?Surface integral problem $displaystyleiint_Sx^2dS$Evaluating the surface integral side of a divergence theorem problemChange of Variable vs ParametrizationHow to calculate the integral on surface which cannot be expressed in functions easily?Heat flow surface integral problemsurface integral of angle between fixed vector and the unit normalSurface integral with cylinder-form surface.













1












$begingroup$


Problem



Compute
$$displaystyle iint_S xz^2dydz+yz^2dzdx+z^3dxdy$$
where $S$ denotes the outside surface of the common part $Omega$ of $x^2+y^2+z^2leq R^2$ and $x^2+y^2+z^2 leq 2Rx$.



Comment



It would be fair to say this could be solved by Gauss's Formula, but how to make the transformation? Anyone can do me a favour?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    but the notation is not wrong.
    $endgroup$
    – mengdie1982
    Jan 21 at 5:18










  • $begingroup$
    @DavidG.Stork: The OP's notation is absolutely fine, and you're completely wrong. Please study the subject yourself before claiming something invalid. See, for example here and here.
    $endgroup$
    – zipirovich
    Jan 21 at 6:17















1












$begingroup$


Problem



Compute
$$displaystyle iint_S xz^2dydz+yz^2dzdx+z^3dxdy$$
where $S$ denotes the outside surface of the common part $Omega$ of $x^2+y^2+z^2leq R^2$ and $x^2+y^2+z^2 leq 2Rx$.



Comment



It would be fair to say this could be solved by Gauss's Formula, but how to make the transformation? Anyone can do me a favour?










share|cite|improve this question











$endgroup$







  • 1




    $begingroup$
    but the notation is not wrong.
    $endgroup$
    – mengdie1982
    Jan 21 at 5:18










  • $begingroup$
    @DavidG.Stork: The OP's notation is absolutely fine, and you're completely wrong. Please study the subject yourself before claiming something invalid. See, for example here and here.
    $endgroup$
    – zipirovich
    Jan 21 at 6:17













1












1








1





$begingroup$


Problem



Compute
$$displaystyle iint_S xz^2dydz+yz^2dzdx+z^3dxdy$$
where $S$ denotes the outside surface of the common part $Omega$ of $x^2+y^2+z^2leq R^2$ and $x^2+y^2+z^2 leq 2Rx$.



Comment



It would be fair to say this could be solved by Gauss's Formula, but how to make the transformation? Anyone can do me a favour?










share|cite|improve this question











$endgroup$




Problem



Compute
$$displaystyle iint_S xz^2dydz+yz^2dzdx+z^3dxdy$$
where $S$ denotes the outside surface of the common part $Omega$ of $x^2+y^2+z^2leq R^2$ and $x^2+y^2+z^2 leq 2Rx$.



Comment



It would be fair to say this could be solved by Gauss's Formula, but how to make the transformation? Anyone can do me a favour?







integration multivariable-calculus surface-integrals






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Feb 1 at 13:48









Martin Sleziak

44.8k10119273




44.8k10119273










asked Jan 21 at 5:12









mengdie1982mengdie1982

4,932618




4,932618







  • 1




    $begingroup$
    but the notation is not wrong.
    $endgroup$
    – mengdie1982
    Jan 21 at 5:18










  • $begingroup$
    @DavidG.Stork: The OP's notation is absolutely fine, and you're completely wrong. Please study the subject yourself before claiming something invalid. See, for example here and here.
    $endgroup$
    – zipirovich
    Jan 21 at 6:17












  • 1




    $begingroup$
    but the notation is not wrong.
    $endgroup$
    – mengdie1982
    Jan 21 at 5:18










  • $begingroup$
    @DavidG.Stork: The OP's notation is absolutely fine, and you're completely wrong. Please study the subject yourself before claiming something invalid. See, for example here and here.
    $endgroup$
    – zipirovich
    Jan 21 at 6:17







1




1




$begingroup$
but the notation is not wrong.
$endgroup$
– mengdie1982
Jan 21 at 5:18




$begingroup$
but the notation is not wrong.
$endgroup$
– mengdie1982
Jan 21 at 5:18












$begingroup$
@DavidG.Stork: The OP's notation is absolutely fine, and you're completely wrong. Please study the subject yourself before claiming something invalid. See, for example here and here.
$endgroup$
– zipirovich
Jan 21 at 6:17




$begingroup$
@DavidG.Stork: The OP's notation is absolutely fine, and you're completely wrong. Please study the subject yourself before claiming something invalid. See, for example here and here.
$endgroup$
– zipirovich
Jan 21 at 6:17










1 Answer
1






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0












$begingroup$

Note that $x^2+y^2+z^2 leq 2Rx$.



is actually :
$(x-R)^2+y^2+z^2 leq R^2$.






share|cite|improve this answer











$endgroup$












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    1 Answer
    1






    active

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    active

    oldest

    votes






    active

    oldest

    votes









    0












    $begingroup$

    Note that $x^2+y^2+z^2 leq 2Rx$.



    is actually :
    $(x-R)^2+y^2+z^2 leq R^2$.






    share|cite|improve this answer











    $endgroup$

















      0












      $begingroup$

      Note that $x^2+y^2+z^2 leq 2Rx$.



      is actually :
      $(x-R)^2+y^2+z^2 leq R^2$.






      share|cite|improve this answer











      $endgroup$















        0












        0








        0





        $begingroup$

        Note that $x^2+y^2+z^2 leq 2Rx$.



        is actually :
        $(x-R)^2+y^2+z^2 leq R^2$.






        share|cite|improve this answer











        $endgroup$



        Note that $x^2+y^2+z^2 leq 2Rx$.



        is actually :
        $(x-R)^2+y^2+z^2 leq R^2$.







        share|cite|improve this answer














        share|cite|improve this answer



        share|cite|improve this answer








        edited yesterday

























        answered yesterday









        Mather Mather

        4108




        4108



























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