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How do I notate a polynomial with Stirling coefficients and what properties do I need to prove it?


Stirling Binomial PolynomialWhat distribution do the rows of the Stirling numbers of the second kind approach?Why do nth roots (radicals) have closed forms whilst other polynomial roots do not?Properties of polynomials that are polynomial conditions on the coefficientsAn integral involving the Gamma functionStirling numbers of the second kind, general formulaFind the polynomial of the fifth degree with real coefficients such that…Second degree polynomials in one variable (with integer coefficients) and limiting behavior of the number of prime values they takeHow to solve for the roots of a 4th degree polynomial with complex coefficients?Partial sum Stirling number of the first kind with factorial and exponential













1












$begingroup$


I have a group of polynomials where each term increases in degree and has coefficients that appear as Stirling numbers of the second kind:



$1: 1 \
2: 1+x \
3: 1+3x+x^2 \
4: 1+7x+6x^2+x^3 \
5: 1+15x+25x^2+10x^3+x^4 ...\$



How can I represent consecutive polynomials in closed form and what properties of Stirling numbers and/or polynomials do I need to prove the nth polynomial with induction?










share|cite|improve this question









$endgroup$
















    1












    $begingroup$


    I have a group of polynomials where each term increases in degree and has coefficients that appear as Stirling numbers of the second kind:



    $1: 1 \
    2: 1+x \
    3: 1+3x+x^2 \
    4: 1+7x+6x^2+x^3 \
    5: 1+15x+25x^2+10x^3+x^4 ...\$



    How can I represent consecutive polynomials in closed form and what properties of Stirling numbers and/or polynomials do I need to prove the nth polynomial with induction?










    share|cite|improve this question









    $endgroup$














      1












      1








      1


      0



      $begingroup$


      I have a group of polynomials where each term increases in degree and has coefficients that appear as Stirling numbers of the second kind:



      $1: 1 \
      2: 1+x \
      3: 1+3x+x^2 \
      4: 1+7x+6x^2+x^3 \
      5: 1+15x+25x^2+10x^3+x^4 ...\$



      How can I represent consecutive polynomials in closed form and what properties of Stirling numbers and/or polynomials do I need to prove the nth polynomial with induction?










      share|cite|improve this question









      $endgroup$




      I have a group of polynomials where each term increases in degree and has coefficients that appear as Stirling numbers of the second kind:



      $1: 1 \
      2: 1+x \
      3: 1+3x+x^2 \
      4: 1+7x+6x^2+x^3 \
      5: 1+15x+25x^2+10x^3+x^4 ...\$



      How can I represent consecutive polynomials in closed form and what properties of Stirling numbers and/or polynomials do I need to prove the nth polynomial with induction?







      sequences-and-series polynomials stirling-numbers






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked yesterday









      Vane VoeVane Voe

      246




      246




















          1 Answer
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          active

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          1












          $begingroup$


          Hint: These polynomials are called Touchard polynomials
          beginalign*
          T_n(x)=sum_k=0n brace kx^kqquad ngeq 0
          endalign*

          and you might want to use
          beginalign*
          T_n+1(x)=xsum_k=0^nbinomnkT_k(x)
          endalign*

          for induction.







          share|cite|improve this answer









          $endgroup$












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            1












            $begingroup$


            Hint: These polynomials are called Touchard polynomials
            beginalign*
            T_n(x)=sum_k=0n brace kx^kqquad ngeq 0
            endalign*

            and you might want to use
            beginalign*
            T_n+1(x)=xsum_k=0^nbinomnkT_k(x)
            endalign*

            for induction.







            share|cite|improve this answer









            $endgroup$

















              1












              $begingroup$


              Hint: These polynomials are called Touchard polynomials
              beginalign*
              T_n(x)=sum_k=0n brace kx^kqquad ngeq 0
              endalign*

              and you might want to use
              beginalign*
              T_n+1(x)=xsum_k=0^nbinomnkT_k(x)
              endalign*

              for induction.







              share|cite|improve this answer









              $endgroup$















                1












                1








                1





                $begingroup$


                Hint: These polynomials are called Touchard polynomials
                beginalign*
                T_n(x)=sum_k=0n brace kx^kqquad ngeq 0
                endalign*

                and you might want to use
                beginalign*
                T_n+1(x)=xsum_k=0^nbinomnkT_k(x)
                endalign*

                for induction.







                share|cite|improve this answer









                $endgroup$




                Hint: These polynomials are called Touchard polynomials
                beginalign*
                T_n(x)=sum_k=0n brace kx^kqquad ngeq 0
                endalign*

                and you might want to use
                beginalign*
                T_n+1(x)=xsum_k=0^nbinomnkT_k(x)
                endalign*

                for induction.








                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered yesterday









                Markus ScheuerMarkus Scheuer

                62.5k459149




                62.5k459149



























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