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Is the value of directional derivative of a scalar function independent of the coordinate system?


Vector fields on smooth manifolds and Lie algebrasWhy does a figure look the same in every coordinate system?What exactly are n-forms and how are they related to dual vectors?Vector fields on manifoldsMultivariable Calculus or Differential Geometry (Analysis on Manifolds) after single variable calculusExterior derivative of a coordinate functionCoordinate independent definition of Fisher metric on statistical manifoldsChain rule with normal directional derivative and radial derivative of a scalar fieldA couple of questions about the directional derivativeQuestion Regarding the Coordinate Independent Form of the Exterior Derivative













0












$begingroup$


I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.



The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.



So are the values in spherical polar and cartesian same?










share|cite|improve this question











$endgroup$
















    0












    $begingroup$


    I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.



    The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.



    So are the values in spherical polar and cartesian same?










    share|cite|improve this question











    $endgroup$














      0












      0








      0





      $begingroup$


      I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.



      The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.



      So are the values in spherical polar and cartesian same?










      share|cite|improve this question











      $endgroup$




      I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.



      The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.



      So are the values in spherical polar and cartesian same?







      multivariable-calculus differential-geometry






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited yesterday









      Ted Shifrin

      64.2k44692




      64.2k44692










      asked yesterday









      Chetan WaghelaChetan Waghela

      688




      688




















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