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Is the value of directional derivative of a scalar function independent of the coordinate system?
Vector fields on smooth manifolds and Lie algebrasWhy does a figure look the same in every coordinate system?What exactly are n-forms and how are they related to dual vectors?Vector fields on manifoldsMultivariable Calculus or Differential Geometry (Analysis on Manifolds) after single variable calculusExterior derivative of a coordinate functionCoordinate independent definition of Fisher metric on statistical manifoldsChain rule with normal directional derivative and radial derivative of a scalar fieldA couple of questions about the directional derivativeQuestion Regarding the Coordinate Independent Form of the Exterior Derivative
$begingroup$
I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.
The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.
So are the values in spherical polar and cartesian same?
multivariable-calculus differential-geometry
$endgroup$
add a comment |
$begingroup$
I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.
The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.
So are the values in spherical polar and cartesian same?
multivariable-calculus differential-geometry
$endgroup$
add a comment |
$begingroup$
I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.
The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.
So are the values in spherical polar and cartesian same?
multivariable-calculus differential-geometry
$endgroup$
I am trying to understand Differential Geometry and I am not able to understand why we define vectors in it, a certain way as operators.
The textbooks mention that writing it as directional derivatives gives us a coordinate free way to define the vector.
So are the values in spherical polar and cartesian same?
multivariable-calculus differential-geometry
multivariable-calculus differential-geometry
edited yesterday
Ted Shifrin
64.2k44692
64.2k44692
asked yesterday
Chetan WaghelaChetan Waghela
688
688
add a comment |
add a comment |
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