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Modified Pascal's triangle


Pyramid of numbers: repriseNumber triangleHow many ways can I express $X$ as a sum unique natural numbers to the power of $N$Successive ratios of a sequence, is this limit true?How to check if a number say 'k' can be formed by adding any number of elements in set/array A?For $ fracn(n-1)2<i leq frac n(n+1)2 $, why is $textround(sqrt2i)=n$The sum of the perimeter of regular polygons inscribed inside of regular polygonsDetermining the number of ways a number can be written as sum of three squaresFinding largest prime factor for checking if a number is squarefreeSums of descending squares













0












$begingroup$


In Pascal's triangle, each number is the sum of the two numbers directly above it. I experimented with a modified Pascal's triangle. First a n-tuple of natural numbers is put to the nth row of the triangle so that the first element of the n-tuple is put to the first item in the nth row of the triangle, second element of the tuple to the second item in the nth row of the triangle all the way to the nth item. Then the items of the n+1th row are calculated as the sum of the square-free part of the left number above and square-free part of the right number above (instead of a direct sum) the item. The next rows are calculated similarly ad infinitum.



I played with the modified triangle with the computer and numerical evidence suggests that for any n-tuple, there exists a natural m such that all entries in the modified triangle are less than m. In my experimentations, the slowest part was to compute the square-free part of a number and my tests were limited by this. I computed the square free part and primality by brute force.



The largest value in the triangle may grow quite fast as the number of elements and the elements themselves in the initial tuple grows. For instance with the tuple (7) the largest value seems to be 2352, with (2,3) 36576 and with (5,9,7) 127039544.



I wonder if there is something non-trivial going on. Is there a way to prove or disprove the conjecture or to improve the numerics from the brute force?



$$begineqnarray7\7,7\7,14,7\ 7,21,21,7\7,28,42,28,7\7,14,49,49,14,7\7,21,15,2,15,21,7\7,28,36,17,17,36,28,7endeqnarray$$










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$endgroup$







  • 2




    $begingroup$
    it will help if you provided a picture of your triangle or the first say 5 rows.
    $endgroup$
    – user25406
    yesterday










  • $begingroup$
    Attempted to add a triangle.
    $endgroup$
    – Roddy MacPhee
    yesterday















0












$begingroup$


In Pascal's triangle, each number is the sum of the two numbers directly above it. I experimented with a modified Pascal's triangle. First a n-tuple of natural numbers is put to the nth row of the triangle so that the first element of the n-tuple is put to the first item in the nth row of the triangle, second element of the tuple to the second item in the nth row of the triangle all the way to the nth item. Then the items of the n+1th row are calculated as the sum of the square-free part of the left number above and square-free part of the right number above (instead of a direct sum) the item. The next rows are calculated similarly ad infinitum.



I played with the modified triangle with the computer and numerical evidence suggests that for any n-tuple, there exists a natural m such that all entries in the modified triangle are less than m. In my experimentations, the slowest part was to compute the square-free part of a number and my tests were limited by this. I computed the square free part and primality by brute force.



The largest value in the triangle may grow quite fast as the number of elements and the elements themselves in the initial tuple grows. For instance with the tuple (7) the largest value seems to be 2352, with (2,3) 36576 and with (5,9,7) 127039544.



I wonder if there is something non-trivial going on. Is there a way to prove or disprove the conjecture or to improve the numerics from the brute force?



$$begineqnarray7\7,7\7,14,7\ 7,21,21,7\7,28,42,28,7\7,14,49,49,14,7\7,21,15,2,15,21,7\7,28,36,17,17,36,28,7endeqnarray$$










share|cite|improve this question









New contributor




We Pretty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 2




    $begingroup$
    it will help if you provided a picture of your triangle or the first say 5 rows.
    $endgroup$
    – user25406
    yesterday










  • $begingroup$
    Attempted to add a triangle.
    $endgroup$
    – Roddy MacPhee
    yesterday













0












0








0





$begingroup$


In Pascal's triangle, each number is the sum of the two numbers directly above it. I experimented with a modified Pascal's triangle. First a n-tuple of natural numbers is put to the nth row of the triangle so that the first element of the n-tuple is put to the first item in the nth row of the triangle, second element of the tuple to the second item in the nth row of the triangle all the way to the nth item. Then the items of the n+1th row are calculated as the sum of the square-free part of the left number above and square-free part of the right number above (instead of a direct sum) the item. The next rows are calculated similarly ad infinitum.



I played with the modified triangle with the computer and numerical evidence suggests that for any n-tuple, there exists a natural m such that all entries in the modified triangle are less than m. In my experimentations, the slowest part was to compute the square-free part of a number and my tests were limited by this. I computed the square free part and primality by brute force.



The largest value in the triangle may grow quite fast as the number of elements and the elements themselves in the initial tuple grows. For instance with the tuple (7) the largest value seems to be 2352, with (2,3) 36576 and with (5,9,7) 127039544.



I wonder if there is something non-trivial going on. Is there a way to prove or disprove the conjecture or to improve the numerics from the brute force?



$$begineqnarray7\7,7\7,14,7\ 7,21,21,7\7,28,42,28,7\7,14,49,49,14,7\7,21,15,2,15,21,7\7,28,36,17,17,36,28,7endeqnarray$$










share|cite|improve this question









New contributor




We Pretty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




In Pascal's triangle, each number is the sum of the two numbers directly above it. I experimented with a modified Pascal's triangle. First a n-tuple of natural numbers is put to the nth row of the triangle so that the first element of the n-tuple is put to the first item in the nth row of the triangle, second element of the tuple to the second item in the nth row of the triangle all the way to the nth item. Then the items of the n+1th row are calculated as the sum of the square-free part of the left number above and square-free part of the right number above (instead of a direct sum) the item. The next rows are calculated similarly ad infinitum.



I played with the modified triangle with the computer and numerical evidence suggests that for any n-tuple, there exists a natural m such that all entries in the modified triangle are less than m. In my experimentations, the slowest part was to compute the square-free part of a number and my tests were limited by this. I computed the square free part and primality by brute force.



The largest value in the triangle may grow quite fast as the number of elements and the elements themselves in the initial tuple grows. For instance with the tuple (7) the largest value seems to be 2352, with (2,3) 36576 and with (5,9,7) 127039544.



I wonder if there is something non-trivial going on. Is there a way to prove or disprove the conjecture or to improve the numerics from the brute force?



$$begineqnarray7\7,7\7,14,7\ 7,21,21,7\7,28,42,28,7\7,14,49,49,14,7\7,21,15,2,15,21,7\7,28,36,17,17,36,28,7endeqnarray$$







number-theory experimental-mathematics






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  • 2




    $begingroup$
    it will help if you provided a picture of your triangle or the first say 5 rows.
    $endgroup$
    – user25406
    yesterday










  • $begingroup$
    Attempted to add a triangle.
    $endgroup$
    – Roddy MacPhee
    yesterday












  • 2




    $begingroup$
    it will help if you provided a picture of your triangle or the first say 5 rows.
    $endgroup$
    – user25406
    yesterday










  • $begingroup$
    Attempted to add a triangle.
    $endgroup$
    – Roddy MacPhee
    yesterday







2




2




$begingroup$
it will help if you provided a picture of your triangle or the first say 5 rows.
$endgroup$
– user25406
yesterday




$begingroup$
it will help if you provided a picture of your triangle or the first say 5 rows.
$endgroup$
– user25406
yesterday












$begingroup$
Attempted to add a triangle.
$endgroup$
– Roddy MacPhee
yesterday




$begingroup$
Attempted to add a triangle.
$endgroup$
– Roddy MacPhee
yesterday










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