Hyperbolic “Fourier” type infinite series for $log(sinh x)$ and $log(cosh x)$ The 2019 Stack Overflow Developer Survey Results Are InOn the zero of $f(x)=int_0^x ln(sinh(z))dz$Making use of Fourier series to evaluate an infinite sumCompute the fourier coefficients, and series for $log(sin(x))$Computing the series of log and sineProving $pi coth pi a= frac1a+ sum_n=1^inftyfrac2an^2+a^2$ using the Fourier series for $cosh ax$Fourier series, infinite seriesFourier series of: $[log(sin x)]^2$Fourier series for $cosh(x)$fourier series of $cosh(ax)$Find Fourier series of $cosh(ax)$Finding Fourier series by evaluating sum of infinite series

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Hyperbolic “Fourier” type infinite series for $log(sinh x)$ and $log(cosh x)$



The 2019 Stack Overflow Developer Survey Results Are InOn the zero of $f(x)=int_0^x ln(sinh(z))dz$Making use of Fourier series to evaluate an infinite sumCompute the fourier coefficients, and series for $log(sin(x))$Computing the series of log and sineProving $pi coth pi a= frac1a+ sum_n=1^inftyfrac2an^2+a^2$ using the Fourier series for $cosh ax$Fourier series, infinite seriesFourier series of: $[log(sin x)]^2$Fourier series for $cosh(x)$fourier series of $cosh(ax)$Find Fourier series of $cosh(ax)$Finding Fourier series by evaluating sum of infinite series










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Hyperbolic Fourier type infinite series for $log(sinh x)$ and $log(cosh x)$ analogous to Fourier $cos$ series for $log(sin x)$ and $log(cos x)$



$$log(sinh(x))=-frac12 (i pi )-log (2)-sum _k=1^infty fraccosh (2 k x)k tag1$$



$$log(cosh(x))=-log (2)-sum _k=1^infty frac(-1)^k cosh (2 k x)k tag2$$



These analogous formula were found using Mathematica, but I am not sure about the proof. Do I convert $cosh(2kx)$ into its exponential form and proceed that way?










share|cite|improve this question











$endgroup$
















    3












    $begingroup$


    Hyperbolic Fourier type infinite series for $log(sinh x)$ and $log(cosh x)$ analogous to Fourier $cos$ series for $log(sin x)$ and $log(cos x)$



    $$log(sinh(x))=-frac12 (i pi )-log (2)-sum _k=1^infty fraccosh (2 k x)k tag1$$



    $$log(cosh(x))=-log (2)-sum _k=1^infty frac(-1)^k cosh (2 k x)k tag2$$



    These analogous formula were found using Mathematica, but I am not sure about the proof. Do I convert $cosh(2kx)$ into its exponential form and proceed that way?










    share|cite|improve this question











    $endgroup$














      3












      3








      3





      $begingroup$


      Hyperbolic Fourier type infinite series for $log(sinh x)$ and $log(cosh x)$ analogous to Fourier $cos$ series for $log(sin x)$ and $log(cos x)$



      $$log(sinh(x))=-frac12 (i pi )-log (2)-sum _k=1^infty fraccosh (2 k x)k tag1$$



      $$log(cosh(x))=-log (2)-sum _k=1^infty frac(-1)^k cosh (2 k x)k tag2$$



      These analogous formula were found using Mathematica, but I am not sure about the proof. Do I convert $cosh(2kx)$ into its exponential form and proceed that way?










      share|cite|improve this question











      $endgroup$




      Hyperbolic Fourier type infinite series for $log(sinh x)$ and $log(cosh x)$ analogous to Fourier $cos$ series for $log(sin x)$ and $log(cos x)$



      $$log(sinh(x))=-frac12 (i pi )-log (2)-sum _k=1^infty fraccosh (2 k x)k tag1$$



      $$log(cosh(x))=-log (2)-sum _k=1^infty frac(-1)^k cosh (2 k x)k tag2$$



      These analogous formula were found using Mathematica, but I am not sure about the proof. Do I convert $cosh(2kx)$ into its exponential form and proceed that way?







      sequences-and-series fourier-series






      share|cite|improve this question















      share|cite|improve this question













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      share|cite|improve this question








      edited Jan 24 at 22:35







      James Arathoon

















      asked Jan 24 at 22:21









      James ArathoonJames Arathoon

      1,608423




      1,608423




















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          $begingroup$

          Hint:



          $$sin(ix)=isinh(x)$$
          and $$cos(ix)=cosh(x)$$






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            active

            oldest

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            0












            $begingroup$

            Hint:



            $$sin(ix)=isinh(x)$$
            and $$cos(ix)=cosh(x)$$






            share|cite|improve this answer









            $endgroup$

















              0












              $begingroup$

              Hint:



              $$sin(ix)=isinh(x)$$
              and $$cos(ix)=cosh(x)$$






              share|cite|improve this answer









              $endgroup$















                0












                0








                0





                $begingroup$

                Hint:



                $$sin(ix)=isinh(x)$$
                and $$cos(ix)=cosh(x)$$






                share|cite|improve this answer









                $endgroup$



                Hint:



                $$sin(ix)=isinh(x)$$
                and $$cos(ix)=cosh(x)$$







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 23 at 16:14









                clathratusclathratus

                5,1141439




                5,1141439



























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