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Higher cup-1 product of coboundaries is also a coboundary?
The 2019 Stack Overflow Developer Survey Results Are InPontrjagin square (Mosher and Tangora Question)The complement of a Cartesian product for characterizing the closed sets of a product spaceGroup cohomology: cup product for cyclic groupsCohomology ring of a direct sum via Poincare dualityDoes the cup product on de Rham cohomology induce a nondegenerate bilinear form?Reference Request: Equivariant cup product in singular cohomologyNotational issues with group cohomologyLinking number and cup productDoes $H^bullet(G, mathbbZ)$ have a coalgebra structure?singular cohomology and Poincaré duality
$begingroup$
In the cohomology or the group cohomology theory, suppose $mu_1$ and $mu_2$ are coboundaries of arbitrary dimensions,
$$
mu_1=delta eta_1
$$
$$
mu_2=delta eta_2
$$
where $eta_1$ and $eta_2$ are their lower dimensional split cochains.
Could we prove that the higher cup 1 product is also a coboundary?
$$
mu_1 cup_1 mu_2=(delta eta_1)cup_1 (delta eta_2)=delta(beta)?
$$
If so, how do we write this $beta$ explicitly?
Is a Higher cup-1 product of coboundaries also a coboundary?
general-topology algebraic-topology homology-cohomology group-cohomology simplicial-complex
$endgroup$
add a comment |
$begingroup$
In the cohomology or the group cohomology theory, suppose $mu_1$ and $mu_2$ are coboundaries of arbitrary dimensions,
$$
mu_1=delta eta_1
$$
$$
mu_2=delta eta_2
$$
where $eta_1$ and $eta_2$ are their lower dimensional split cochains.
Could we prove that the higher cup 1 product is also a coboundary?
$$
mu_1 cup_1 mu_2=(delta eta_1)cup_1 (delta eta_2)=delta(beta)?
$$
If so, how do we write this $beta$ explicitly?
Is a Higher cup-1 product of coboundaries also a coboundary?
general-topology algebraic-topology homology-cohomology group-cohomology simplicial-complex
$endgroup$
$begingroup$
See this post for higher cup product mathoverflow.net/questions/268181/…
$endgroup$
– annie heart
Mar 23 at 16:05
$begingroup$
I also ask a related question: mathoverflow.net/q/326155/106497 in Use of Steenrod's Higher Cup product and the graded-commutativity
$endgroup$
– annie heart
Mar 23 at 16:44
add a comment |
$begingroup$
In the cohomology or the group cohomology theory, suppose $mu_1$ and $mu_2$ are coboundaries of arbitrary dimensions,
$$
mu_1=delta eta_1
$$
$$
mu_2=delta eta_2
$$
where $eta_1$ and $eta_2$ are their lower dimensional split cochains.
Could we prove that the higher cup 1 product is also a coboundary?
$$
mu_1 cup_1 mu_2=(delta eta_1)cup_1 (delta eta_2)=delta(beta)?
$$
If so, how do we write this $beta$ explicitly?
Is a Higher cup-1 product of coboundaries also a coboundary?
general-topology algebraic-topology homology-cohomology group-cohomology simplicial-complex
$endgroup$
In the cohomology or the group cohomology theory, suppose $mu_1$ and $mu_2$ are coboundaries of arbitrary dimensions,
$$
mu_1=delta eta_1
$$
$$
mu_2=delta eta_2
$$
where $eta_1$ and $eta_2$ are their lower dimensional split cochains.
Could we prove that the higher cup 1 product is also a coboundary?
$$
mu_1 cup_1 mu_2=(delta eta_1)cup_1 (delta eta_2)=delta(beta)?
$$
If so, how do we write this $beta$ explicitly?
Is a Higher cup-1 product of coboundaries also a coboundary?
general-topology algebraic-topology homology-cohomology group-cohomology simplicial-complex
general-topology algebraic-topology homology-cohomology group-cohomology simplicial-complex
asked Mar 23 at 15:55
annie heartannie heart
673721
673721
$begingroup$
See this post for higher cup product mathoverflow.net/questions/268181/…
$endgroup$
– annie heart
Mar 23 at 16:05
$begingroup$
I also ask a related question: mathoverflow.net/q/326155/106497 in Use of Steenrod's Higher Cup product and the graded-commutativity
$endgroup$
– annie heart
Mar 23 at 16:44
add a comment |
$begingroup$
See this post for higher cup product mathoverflow.net/questions/268181/…
$endgroup$
– annie heart
Mar 23 at 16:05
$begingroup$
I also ask a related question: mathoverflow.net/q/326155/106497 in Use of Steenrod's Higher Cup product and the graded-commutativity
$endgroup$
– annie heart
Mar 23 at 16:44
$begingroup$
See this post for higher cup product mathoverflow.net/questions/268181/…
$endgroup$
– annie heart
Mar 23 at 16:05
$begingroup$
See this post for higher cup product mathoverflow.net/questions/268181/…
$endgroup$
– annie heart
Mar 23 at 16:05
$begingroup$
I also ask a related question: mathoverflow.net/q/326155/106497 in Use of Steenrod's Higher Cup product and the graded-commutativity
$endgroup$
– annie heart
Mar 23 at 16:44
$begingroup$
I also ask a related question: mathoverflow.net/q/326155/106497 in Use of Steenrod's Higher Cup product and the graded-commutativity
$endgroup$
– annie heart
Mar 23 at 16:44
add a comment |
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$begingroup$
See this post for higher cup product mathoverflow.net/questions/268181/…
$endgroup$
– annie heart
Mar 23 at 16:05
$begingroup$
I also ask a related question: mathoverflow.net/q/326155/106497 in Use of Steenrod's Higher Cup product and the graded-commutativity
$endgroup$
– annie heart
Mar 23 at 16:44