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Use matplotlib to plot the functions $y = x^3 + 3x^2 - x + 0.3 $ and $y = sin x$ [closed]

0

0

$begingroup$

I'm new to Python coding and wondered if someone could give me the coding to plot these two graphs on the same program.

This is what I have so far, exactly as typed on Python, however I know that parts are incorrect.

from matplotlib import pyplot as plt

x = [float(i)/100 for i in range(0,101)]
y = [sin(x)]

plt.plot(x,y)

graphing-functions math-software python

share|cite|improve this question

edited Mar 24 at 3:05

Lee David Chung Lin

4,47841242

asked Mar 23 at 18:55

BrookeBrooke

63

$endgroup$

closed as unclear what you're asking by Somos, Javi, Leucippus, YiFan, Alex Provost Mar 24 at 14:15

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

0

0

$begingroup$

I'm new to Python coding and wondered if someone could give me the coding to plot these two graphs on the same program.

This is what I have so far, exactly as typed on Python, however I know that parts are incorrect.

from matplotlib import pyplot as plt

x = [float(i)/100 for i in range(0,101)]
y = [sin(x)]

plt.plot(x,y)

graphing-functions math-software python

share|cite|improve this question

edited Mar 24 at 3:05

Lee David Chung Lin

4,47841242

asked Mar 23 at 18:55

BrookeBrooke

63

$endgroup$

closed as unclear what you're asking by Somos, Javi, Leucippus, YiFan, Alex Provost Mar 24 at 14:15

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

add a comment | 

$begingroup$

I'm new to Python coding and wondered if someone could give me the coding to plot these two graphs on the same program.

This is what I have so far, exactly as typed on Python, however I know that parts are incorrect.

from matplotlib import pyplot as plt

x = [float(i)/100 for i in range(0,101)]
y = [sin(x)]

plt.plot(x,y)

graphing-functions math-software python

share|cite|improve this question

edited Mar 24 at 3:05

Lee David Chung Lin

4,47841242

asked Mar 23 at 18:55

BrookeBrooke

63

$endgroup$

from matplotlib import pyplot as plt

x = [float(i)/100 for i in range(0,101)]
y = [sin(x)]

plt.plot(x,y)

share|cite|improve this question

edited Mar 24 at 3:05

Lee David Chung Lin

4,47841242

asked Mar 23 at 18:55

BrookeBrooke

63

share|cite|improve this question

edited Mar 24 at 3:05

Lee David Chung Lin

4,47841242

asked Mar 23 at 18:55

BrookeBrooke

63

edited Mar 24 at 3:05

Lee David Chung Lin

4,47841242

edited Mar 24 at 3:05

Lee David Chung Lin

4,47841242

asked Mar 23 at 18:55

BrookeBrooke

63

asked Mar 23 at 18:55

BrookeBrooke

63

1 Answer
1

active

oldest

votes

1

$begingroup$

First, you need a larger range for $x$ to see a nice sinusoid, say from $0$ to $2pi$.
Second, specify $y$ as a list comprehension, too:

from matplotlib import pyplot as plt
import math

x = [float(i)/100 for i in range(0, 628)]
y = [math.sin(z) for z in x]

plt.plot(x,y)

---

If you want to plot both graphs one over the other (what isn't generally a good idea because those 2 function are so different, that in the default settings the sine function will appear as to coincide with the x-axis), the code may be as follows (I extended the range for $x$, and set limits for $y$-axes):

from matplotlib import pyplot as plt
import math

BOUND = 1000

x = [float(i)/100 for i in range(-BOUND, +BOUND)]
y = [math.sin(z) for z in x]
w = [z**3 + 3*z**2 - z + 0.3 for z in x]


plt.ylim(-7,+7)
plt.plot(x, y)
plt.plot(x, w)

share|cite|improve this answer

edited Mar 23 at 21:22

answered Mar 23 at 19:15

MarianDMarianD

2,2611618

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Ah I see, so how would I add the second y graph onto this?
  $endgroup$
  – Brooke
  Mar 23 at 19:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Do you mean to overlay this graph, or to create other one (in the other window)?
  $endgroup$
  – MarianD
  Mar 23 at 19:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  They will both be on the same axis so it will over lay it and show both
  $endgroup$
  – Brooke
  Mar 23 at 19:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It's not a good idea, because there is such difference between the 2 functions that the sine function will appear to coincident with x axis. See: $sin(5pi /2) = 1$, while $x^3 + 3x^2 - x + 0.3$ will be for the same $x =5pi /2$ approximately $662$.
  $endgroup$
  – MarianD
  Mar 23 at 20:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  That what the assignment question is asking me to do as I am to find the real solutions of the graphs.
  $endgroup$
  – Brooke
  Mar 23 at 20:10
  

  
  
  
  

 | 
show 2 more comments

1

$begingroup$

First, you need a larger range for $x$ to see a nice sinusoid, say from $0$ to $2pi$.
Second, specify $y$ as a list comprehension, too:

from matplotlib import pyplot as plt
import math

x = [float(i)/100 for i in range(0, 628)]
y = [math.sin(z) for z in x]

plt.plot(x,y)

---

If you want to plot both graphs one over the other (what isn't generally a good idea because those 2 function are so different, that in the default settings the sine function will appear as to coincide with the x-axis), the code may be as follows (I extended the range for $x$, and set limits for $y$-axes):

from matplotlib import pyplot as plt
import math

BOUND = 1000

x = [float(i)/100 for i in range(-BOUND, +BOUND)]
y = [math.sin(z) for z in x]
w = [z**3 + 3*z**2 - z + 0.3 for z in x]


plt.ylim(-7,+7)
plt.plot(x, y)
plt.plot(x, w)

share|cite|improve this answer

edited Mar 23 at 21:22

answered Mar 23 at 19:15

MarianDMarianD

2,2611618

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Ah I see, so how would I add the second y graph onto this?
  $endgroup$
  – Brooke
  Mar 23 at 19:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Do you mean to overlay this graph, or to create other one (in the other window)?
  $endgroup$
  – MarianD
  Mar 23 at 19:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  They will both be on the same axis so it will over lay it and show both
  $endgroup$
  – Brooke
  Mar 23 at 19:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It's not a good idea, because there is such difference between the 2 functions that the sine function will appear to coincident with x axis. See: $sin(5pi /2) = 1$, while $x^3 + 3x^2 - x + 0.3$ will be for the same $x =5pi /2$ approximately $662$.
  $endgroup$
  – MarianD
  Mar 23 at 20:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  That what the assignment question is asking me to do as I am to find the real solutions of the graphs.
  $endgroup$
  – Brooke
  Mar 23 at 20:10
  

  
  
  
  

 | 
show 2 more comments

1

$begingroup$

First, you need a larger range for $x$ to see a nice sinusoid, say from $0$ to $2pi$.
Second, specify $y$ as a list comprehension, too:

from matplotlib import pyplot as plt
import math

x = [float(i)/100 for i in range(0, 628)]
y = [math.sin(z) for z in x]

plt.plot(x,y)

---

If you want to plot both graphs one over the other (what isn't generally a good idea because those 2 function are so different, that in the default settings the sine function will appear as to coincide with the x-axis), the code may be as follows (I extended the range for $x$, and set limits for $y$-axes):

from matplotlib import pyplot as plt
import math

BOUND = 1000

x = [float(i)/100 for i in range(-BOUND, +BOUND)]
y = [math.sin(z) for z in x]
w = [z**3 + 3*z**2 - z + 0.3 for z in x]


plt.ylim(-7,+7)
plt.plot(x, y)
plt.plot(x, w)

share|cite|improve this answer

edited Mar 23 at 21:22

answered Mar 23 at 19:15

MarianDMarianD

2,2611618

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Ah I see, so how would I add the second y graph onto this?
  $endgroup$
  – Brooke
  Mar 23 at 19:16
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Do you mean to overlay this graph, or to create other one (in the other window)?
  $endgroup$
  – MarianD
  Mar 23 at 19:30
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  They will both be on the same axis so it will over lay it and show both
  $endgroup$
  – Brooke
  Mar 23 at 19:38
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  It's not a good idea, because there is such difference between the 2 functions that the sine function will appear to coincident with x axis. See: $sin(5pi /2) = 1$, while $x^3 + 3x^2 - x + 0.3$ will be for the same $x =5pi /2$ approximately $662$.
  $endgroup$
  – MarianD
  Mar 23 at 20:01
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  That what the assignment question is asking me to do as I am to find the real solutions of the graphs.
  $endgroup$
  – Brooke
  Mar 23 at 20:10
  

  
  
  
  

 | 
show 2 more comments

$begingroup$

First, you need a larger range for $x$ to see a nice sinusoid, say from $0$ to $2pi$.
Second, specify $y$ as a list comprehension, too:

from matplotlib import pyplot as plt
import math

x = [float(i)/100 for i in range(0, 628)]
y = [math.sin(z) for z in x]

plt.plot(x,y)

---

If you want to plot both graphs one over the other (what isn't generally a good idea because those 2 function are so different, that in the default settings the sine function will appear as to coincide with the x-axis), the code may be as follows (I extended the range for $x$, and set limits for $y$-axes):

from matplotlib import pyplot as plt
import math

BOUND = 1000

x = [float(i)/100 for i in range(-BOUND, +BOUND)]
y = [math.sin(z) for z in x]
w = [z**3 + 3*z**2 - z + 0.3 for z in x]


plt.ylim(-7,+7)
plt.plot(x, y)
plt.plot(x, w)

share|cite|improve this answer

edited Mar 23 at 21:22

answered Mar 23 at 19:15

MarianDMarianD

2,2611618

$endgroup$

from matplotlib import pyplot as plt
import math

x = [float(i)/100 for i in range(0, 628)]
y = [math.sin(z) for z in x]

plt.plot(x,y)

from matplotlib import pyplot as plt
import math

BOUND = 1000

x = [float(i)/100 for i in range(-BOUND, +BOUND)]
y = [math.sin(z) for z in x]
w = [z**3 + 3*z**2 - z + 0.3 for z in x]


plt.ylim(-7,+7)
plt.plot(x, y)
plt.plot(x, w)

share|cite|improve this answer

edited Mar 23 at 21:22

answered Mar 23 at 19:15

MarianDMarianD

2,2611618

answered Mar 23 at 19:15

MarianDMarianD

2,2611618

answered Mar 23 at 19:15

MarianDMarianD

2,2611618