Cluster points of a sequence $a_n$ The 2019 Stack Overflow Developer Survey Results Are InCluster Point TheoremFinding all limit points of the sequence $a_n=(-n)^(-n)^n$Interior, Closure, Cluster Points, and Boundary Points QuestionFind $limsup$ and $liminf$ of a sequence and prove $liminf a_n leq limsup a_n$.Find all cluster points of the following sequenceShowing set of all cluster points of sequence in extended $mathbb R $ is closed.Sequence is union of convergent subsequences. Are the limits of the subsequences the only cluster points the sequence have?find the the limit points of this sequence..How to find the cluster point of this sequence?cluster and convergence points
How to save as into a customized destination on macOS?
Is an up-to-date browser secure on an out-of-date OS?
What is the meaning of the verb "bear" in this context?
Multiply Two Integer Polynomials
How to type this arrow in math mode?
What do the Banks children have against barley water?
Is a "Democratic" Oligarchy-Style System Possible?
How technical should a Scrum Master be to effectively remove impediments?
What could be the right powersource for 15 seconds lifespan disposable giant chainsaw?
Can we generate random numbers using irrational numbers like π and e?
If a Druid sees an animal’s corpse, can they wild shape into that animal?
Why isn't the circumferential light around the M87 black hole's event horizon symmetric?
Right tool to dig six foot holes?
What are the motivations for publishing new editions of an existing textbook, beyond new discoveries in a field?
How to support a colleague who finds meetings extremely tiring?
What is the accessibility of a package's `Private` context variables?
Output the Arecibo Message
Why do UK politicians seemingly ignore opinion polls on Brexit?
Am I thawing this London Broil safely?
What does Linus Torvalds mean when he says that Git "never ever" tracks a file?
Did Section 31 appear in Star Trek: The Next Generation?
Why was M87 targetted for the Event Horizon Telescope instead of Sagittarius A*?
What do hard-Brexiteers want with respect to the Irish border?
Why hard-Brexiteers don't insist on a hard border to prevent illegal immigration after Brexit?
Cluster points of a sequence $a_n$
The 2019 Stack Overflow Developer Survey Results Are InCluster Point TheoremFinding all limit points of the sequence $a_n=(-n)^(-n)^n$Interior, Closure, Cluster Points, and Boundary Points QuestionFind $limsup$ and $liminf$ of a sequence and prove $liminf a_n leq limsup a_n$.Find all cluster points of the following sequenceShowing set of all cluster points of sequence in extended $mathbb R $ is closed.Sequence is union of convergent subsequences. Are the limits of the subsequences the only cluster points the sequence have?find the the limit points of this sequence..How to find the cluster point of this sequence?cluster and convergence points
$begingroup$
Suppose that there is a sequence $a_n$ with the below subsequnces:
a) $a_n = fracn+2+1n^2 + n + 1$ when $n$ is odd.
b) $a_n = fracsinnn$ when $n$ is mulptiple of $4$
c) $a_n = frac1n - 1$ when $n$ is even but not multiple of $4$
Which are the cluster points?
The solution is $A=-1,0,1$ but I don't understand why.
My solution:
a) $a_n = fracn+2+1n^2+n+1 = frac1 + frac2n + frac1nn+1+frac1n rightarrow 0$
b) $ frac-1n leq fracsinnn leq frac1n ... rightarrow 0$
c) $ a_n = frac1n - 1 rightarrow -1$
So, $A = -1,0 $
How did they find the cluster point $1$ ?
real-analysis
$endgroup$
|
show 2 more comments
$begingroup$
Suppose that there is a sequence $a_n$ with the below subsequnces:
a) $a_n = fracn+2+1n^2 + n + 1$ when $n$ is odd.
b) $a_n = fracsinnn$ when $n$ is mulptiple of $4$
c) $a_n = frac1n - 1$ when $n$ is even but not multiple of $4$
Which are the cluster points?
The solution is $A=-1,0,1$ but I don't understand why.
My solution:
a) $a_n = fracn+2+1n^2+n+1 = frac1 + frac2n + frac1nn+1+frac1n rightarrow 0$
b) $ frac-1n leq fracsinnn leq frac1n ... rightarrow 0$
c) $ a_n = frac1n - 1 rightarrow -1$
So, $A = -1,0 $
How did they find the cluster point $1$ ?
real-analysis
$endgroup$
$begingroup$
The subsequence c is $a_n = 1/n - n$ or $a_n = 1/n - 1$ like in your solution?
$endgroup$
– The Student
Mar 23 at 16:29
$begingroup$
I edited it. Thank you
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:30
$begingroup$
The subsequence c converges to -1. So, why -1 isn't a cluster point ?
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:41
$begingroup$
Sorry, is 1 instead of -1
$endgroup$
– The Student
Mar 23 at 16:42
$begingroup$
Ohh ok !! I have the same opinion about this. It is an exercise of a book that gives this solution. I mean $A = -1,0,1 $
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:43
|
show 2 more comments
$begingroup$
Suppose that there is a sequence $a_n$ with the below subsequnces:
a) $a_n = fracn+2+1n^2 + n + 1$ when $n$ is odd.
b) $a_n = fracsinnn$ when $n$ is mulptiple of $4$
c) $a_n = frac1n - 1$ when $n$ is even but not multiple of $4$
Which are the cluster points?
The solution is $A=-1,0,1$ but I don't understand why.
My solution:
a) $a_n = fracn+2+1n^2+n+1 = frac1 + frac2n + frac1nn+1+frac1n rightarrow 0$
b) $ frac-1n leq fracsinnn leq frac1n ... rightarrow 0$
c) $ a_n = frac1n - 1 rightarrow -1$
So, $A = -1,0 $
How did they find the cluster point $1$ ?
real-analysis
$endgroup$
Suppose that there is a sequence $a_n$ with the below subsequnces:
a) $a_n = fracn+2+1n^2 + n + 1$ when $n$ is odd.
b) $a_n = fracsinnn$ when $n$ is mulptiple of $4$
c) $a_n = frac1n - 1$ when $n$ is even but not multiple of $4$
Which are the cluster points?
The solution is $A=-1,0,1$ but I don't understand why.
My solution:
a) $a_n = fracn+2+1n^2+n+1 = frac1 + frac2n + frac1nn+1+frac1n rightarrow 0$
b) $ frac-1n leq fracsinnn leq frac1n ... rightarrow 0$
c) $ a_n = frac1n - 1 rightarrow -1$
So, $A = -1,0 $
How did they find the cluster point $1$ ?
real-analysis
real-analysis
edited Mar 23 at 16:30
Dimitris Dimitriadis
asked Mar 23 at 16:18
Dimitris DimitriadisDimitris Dimitriadis
568
568
$begingroup$
The subsequence c is $a_n = 1/n - n$ or $a_n = 1/n - 1$ like in your solution?
$endgroup$
– The Student
Mar 23 at 16:29
$begingroup$
I edited it. Thank you
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:30
$begingroup$
The subsequence c converges to -1. So, why -1 isn't a cluster point ?
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:41
$begingroup$
Sorry, is 1 instead of -1
$endgroup$
– The Student
Mar 23 at 16:42
$begingroup$
Ohh ok !! I have the same opinion about this. It is an exercise of a book that gives this solution. I mean $A = -1,0,1 $
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:43
|
show 2 more comments
$begingroup$
The subsequence c is $a_n = 1/n - n$ or $a_n = 1/n - 1$ like in your solution?
$endgroup$
– The Student
Mar 23 at 16:29
$begingroup$
I edited it. Thank you
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:30
$begingroup$
The subsequence c converges to -1. So, why -1 isn't a cluster point ?
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:41
$begingroup$
Sorry, is 1 instead of -1
$endgroup$
– The Student
Mar 23 at 16:42
$begingroup$
Ohh ok !! I have the same opinion about this. It is an exercise of a book that gives this solution. I mean $A = -1,0,1 $
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:43
$begingroup$
The subsequence c is $a_n = 1/n - n$ or $a_n = 1/n - 1$ like in your solution?
$endgroup$
– The Student
Mar 23 at 16:29
$begingroup$
The subsequence c is $a_n = 1/n - n$ or $a_n = 1/n - 1$ like in your solution?
$endgroup$
– The Student
Mar 23 at 16:29
$begingroup$
I edited it. Thank you
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:30
$begingroup$
I edited it. Thank you
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:30
$begingroup$
The subsequence c converges to -1. So, why -1 isn't a cluster point ?
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:41
$begingroup$
The subsequence c converges to -1. So, why -1 isn't a cluster point ?
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:41
$begingroup$
Sorry, is 1 instead of -1
$endgroup$
– The Student
Mar 23 at 16:42
$begingroup$
Sorry, is 1 instead of -1
$endgroup$
– The Student
Mar 23 at 16:42
$begingroup$
Ohh ok !! I have the same opinion about this. It is an exercise of a book that gives this solution. I mean $A = -1,0,1 $
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:43
$begingroup$
Ohh ok !! I have the same opinion about this. It is an exercise of a book that gives this solution. I mean $A = -1,0,1 $
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:43
|
show 2 more comments
0
active
oldest
votes
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3159506%2fcluster-points-of-a-sequence-a-n%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3159506%2fcluster-points-of-a-sequence-a-n%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
The subsequence c is $a_n = 1/n - n$ or $a_n = 1/n - 1$ like in your solution?
$endgroup$
– The Student
Mar 23 at 16:29
$begingroup$
I edited it. Thank you
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:30
$begingroup$
The subsequence c converges to -1. So, why -1 isn't a cluster point ?
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:41
$begingroup$
Sorry, is 1 instead of -1
$endgroup$
– The Student
Mar 23 at 16:42
$begingroup$
Ohh ok !! I have the same opinion about this. It is an exercise of a book that gives this solution. I mean $A = -1,0,1 $
$endgroup$
– Dimitris Dimitriadis
Mar 23 at 16:43