Calculus integration by parts? [closed] The 2019 Stack Overflow Developer Survey Results Are InConstants of integration in integration by partsIntegration by parts alternative formNeed help on integrating a trigonometric functionHow to integrate $int e^-t^2 space dt $ using introductory calculus methodsSolve $int 3xcos(2x)dx$ with integration by partsIndefinite integration: $int x^x^2+1(2ln x+1)dx$How do I evaluate $int_-infty^infty(1-x^2)e^-x^2mathrmdx$ using simple calculus?Evaluate the integral $int_0^inftyfracixe^-ix((x-3i)(x+3i))^2textdx$Solve $int frac1cos^2(x)+cos(x)+1dx$Why doesn't integration by parts work here?

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Calculus integration by parts? [closed]



The 2019 Stack Overflow Developer Survey Results Are InConstants of integration in integration by partsIntegration by parts alternative formNeed help on integrating a trigonometric functionHow to integrate $int e^-t^2 space dt $ using introductory calculus methodsSolve $int 3xcos(2x)dx$ with integration by partsIndefinite integration: $int x^x^2+1(2ln x+1)dx$How do I evaluate $int_-infty^infty(1-x^2)e^-x^2mathrmdx$ using simple calculus?Evaluate the integral $int_0^inftyfracixe^-ix((x-3i)(x+3i))^2textdx$Solve $int frac1cos^2(x)+cos(x)+1dx$Why doesn't integration by parts work here?










-4












$begingroup$


$int e^x^2dx$



Can someone tell me if there is a way of doing this integral without the imaginary error function that wolfram alpha keeps putting out. Thank you! I would like to know if this is possible using normal calculus.










share|cite|improve this question











$endgroup$



closed as unclear what you're asking by Mark Viola, James, abiessu, RRL, Javi Mar 24 at 0:32


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.













  • 1




    $begingroup$
    There is a trick that can be used for some definite versions of this integral, and you could take the integral of the series form, but there is no elementary expression of this integral.
    $endgroup$
    – abiessu
    Mar 23 at 18:17










  • $begingroup$
    It is well known and accepted that there is no elementary antiderivative to this function
    $endgroup$
    – Henry Lee
    Mar 23 at 18:39















-4












$begingroup$


$int e^x^2dx$



Can someone tell me if there is a way of doing this integral without the imaginary error function that wolfram alpha keeps putting out. Thank you! I would like to know if this is possible using normal calculus.










share|cite|improve this question











$endgroup$



closed as unclear what you're asking by Mark Viola, James, abiessu, RRL, Javi Mar 24 at 0:32


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.













  • 1




    $begingroup$
    There is a trick that can be used for some definite versions of this integral, and you could take the integral of the series form, but there is no elementary expression of this integral.
    $endgroup$
    – abiessu
    Mar 23 at 18:17










  • $begingroup$
    It is well known and accepted that there is no elementary antiderivative to this function
    $endgroup$
    – Henry Lee
    Mar 23 at 18:39













-4












-4








-4





$begingroup$


$int e^x^2dx$



Can someone tell me if there is a way of doing this integral without the imaginary error function that wolfram alpha keeps putting out. Thank you! I would like to know if this is possible using normal calculus.










share|cite|improve this question











$endgroup$




$int e^x^2dx$



Can someone tell me if there is a way of doing this integral without the imaginary error function that wolfram alpha keeps putting out. Thank you! I would like to know if this is possible using normal calculus.







calculus






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 23 at 18:25









Benitok

1174




1174










asked Mar 23 at 18:15









Jeffrey MasseyJeffrey Massey

1




1




closed as unclear what you're asking by Mark Viola, James, abiessu, RRL, Javi Mar 24 at 0:32


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.









closed as unclear what you're asking by Mark Viola, James, abiessu, RRL, Javi Mar 24 at 0:32


Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.









  • 1




    $begingroup$
    There is a trick that can be used for some definite versions of this integral, and you could take the integral of the series form, but there is no elementary expression of this integral.
    $endgroup$
    – abiessu
    Mar 23 at 18:17










  • $begingroup$
    It is well known and accepted that there is no elementary antiderivative to this function
    $endgroup$
    – Henry Lee
    Mar 23 at 18:39












  • 1




    $begingroup$
    There is a trick that can be used for some definite versions of this integral, and you could take the integral of the series form, but there is no elementary expression of this integral.
    $endgroup$
    – abiessu
    Mar 23 at 18:17










  • $begingroup$
    It is well known and accepted that there is no elementary antiderivative to this function
    $endgroup$
    – Henry Lee
    Mar 23 at 18:39







1




1




$begingroup$
There is a trick that can be used for some definite versions of this integral, and you could take the integral of the series form, but there is no elementary expression of this integral.
$endgroup$
– abiessu
Mar 23 at 18:17




$begingroup$
There is a trick that can be used for some definite versions of this integral, and you could take the integral of the series form, but there is no elementary expression of this integral.
$endgroup$
– abiessu
Mar 23 at 18:17












$begingroup$
It is well known and accepted that there is no elementary antiderivative to this function
$endgroup$
– Henry Lee
Mar 23 at 18:39




$begingroup$
It is well known and accepted that there is no elementary antiderivative to this function
$endgroup$
– Henry Lee
Mar 23 at 18:39










1 Answer
1






active

oldest

votes


















1












$begingroup$

If you are after a primitive of $e^x^2$, forget it. Liouville proved in the XIXth century that that function has no elementary primitive.






share|cite|improve this answer









$endgroup$



















    1 Answer
    1






    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1












    $begingroup$

    If you are after a primitive of $e^x^2$, forget it. Liouville proved in the XIXth century that that function has no elementary primitive.






    share|cite|improve this answer









    $endgroup$

















      1












      $begingroup$

      If you are after a primitive of $e^x^2$, forget it. Liouville proved in the XIXth century that that function has no elementary primitive.






      share|cite|improve this answer









      $endgroup$















        1












        1








        1





        $begingroup$

        If you are after a primitive of $e^x^2$, forget it. Liouville proved in the XIXth century that that function has no elementary primitive.






        share|cite|improve this answer









        $endgroup$



        If you are after a primitive of $e^x^2$, forget it. Liouville proved in the XIXth century that that function has no elementary primitive.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered Mar 23 at 18:33









        José Carlos SantosJosé Carlos Santos

        174k23133242




        174k23133242













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