What are the limit points of $X times mathbbN$?order topology and discrete topologySubspace topology and order topologySubspace topology and order topology (2)Convexity implies the equivalence of order and subspace topologiesOrder topology and subspace topology in $mathbb R$What are the limit points of $A_n=[n,infty)$ in a metric space? Is $A_n$ closed?questions about subspace topology, order topology and convex subsetIs the interval $((a,b), (a,d))$ is open in $mathbbRtimes mathbbR$ which is equipped with the dictionary order topologyMunkres Example 16.3Help me to visualise limit points of $S$.

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What are the limit points of $X times mathbbN$?


order topology and discrete topologySubspace topology and order topologySubspace topology and order topology (2)Convexity implies the equivalence of order and subspace topologiesOrder topology and subspace topology in $mathbb R$What are the limit points of $A_n=[n,infty)$ in a metric space? Is $A_n$ closed?questions about subspace topology, order topology and convex subsetIs the interval $((a,b), (a,d))$ is open in $mathbbRtimes mathbbR$ which is equipped with the dictionary order topologyMunkres Example 16.3Help me to visualise limit points of $S$.













0












$begingroup$


Let $X=0,1,2 $ with natural order topology and give $mathbbN$ its natural order topology. Consider $X times mathbbN$ with the dictionary order topology.



What are the limit points of $X times mathbbN$ ?



Answer:



$X times mathbbN=(0,1), (0,2), cdots, (0, infty), (1,1),(1,2), cdots, (1, infty), (2,1), (2,2), cdots, (2, infty) , cdots $



But how to find the limit point?



help me










share|cite|improve this question









$endgroup$











  • $begingroup$
    Have you tried working with ordinals? Because that would immediately answer this question.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:13










  • $begingroup$
    @DonThousand, Any finite set has all its limits points. But this est $X times mathbbN$ is discrete set, so it is closed and hence all limits points. Is it?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:42










  • $begingroup$
    I wouldn't be so sure about that. Consider $(3,1)$. Any neighborhood around $(3,1)$ must contain an element of the form $(2,n)$ for some $ninmathbb N$. So, $(3,1)$ is a limit point of $Xtimesmathbb N$. Again, thinking about this in terms of ordinals makes this problem a lot easier IMO.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:55











  • $begingroup$
    @DonThousand, what are the open sets look like in $ X times mathbbN$?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:59










  • $begingroup$
    Order topology...google is your best friend.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:59
















0












$begingroup$


Let $X=0,1,2 $ with natural order topology and give $mathbbN$ its natural order topology. Consider $X times mathbbN$ with the dictionary order topology.



What are the limit points of $X times mathbbN$ ?



Answer:



$X times mathbbN=(0,1), (0,2), cdots, (0, infty), (1,1),(1,2), cdots, (1, infty), (2,1), (2,2), cdots, (2, infty) , cdots $



But how to find the limit point?



help me










share|cite|improve this question









$endgroup$











  • $begingroup$
    Have you tried working with ordinals? Because that would immediately answer this question.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:13










  • $begingroup$
    @DonThousand, Any finite set has all its limits points. But this est $X times mathbbN$ is discrete set, so it is closed and hence all limits points. Is it?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:42










  • $begingroup$
    I wouldn't be so sure about that. Consider $(3,1)$. Any neighborhood around $(3,1)$ must contain an element of the form $(2,n)$ for some $ninmathbb N$. So, $(3,1)$ is a limit point of $Xtimesmathbb N$. Again, thinking about this in terms of ordinals makes this problem a lot easier IMO.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:55











  • $begingroup$
    @DonThousand, what are the open sets look like in $ X times mathbbN$?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:59










  • $begingroup$
    Order topology...google is your best friend.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:59














0












0








0





$begingroup$


Let $X=0,1,2 $ with natural order topology and give $mathbbN$ its natural order topology. Consider $X times mathbbN$ with the dictionary order topology.



What are the limit points of $X times mathbbN$ ?



Answer:



$X times mathbbN=(0,1), (0,2), cdots, (0, infty), (1,1),(1,2), cdots, (1, infty), (2,1), (2,2), cdots, (2, infty) , cdots $



But how to find the limit point?



help me










share|cite|improve this question









$endgroup$




Let $X=0,1,2 $ with natural order topology and give $mathbbN$ its natural order topology. Consider $X times mathbbN$ with the dictionary order topology.



What are the limit points of $X times mathbbN$ ?



Answer:



$X times mathbbN=(0,1), (0,2), cdots, (0, infty), (1,1),(1,2), cdots, (1, infty), (2,1), (2,2), cdots, (2, infty) , cdots $



But how to find the limit point?



help me







limits order-topology






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 21 at 7:01









M. A. SARKARM. A. SARKAR

2,4621820




2,4621820











  • $begingroup$
    Have you tried working with ordinals? Because that would immediately answer this question.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:13










  • $begingroup$
    @DonThousand, Any finite set has all its limits points. But this est $X times mathbbN$ is discrete set, so it is closed and hence all limits points. Is it?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:42










  • $begingroup$
    I wouldn't be so sure about that. Consider $(3,1)$. Any neighborhood around $(3,1)$ must contain an element of the form $(2,n)$ for some $ninmathbb N$. So, $(3,1)$ is a limit point of $Xtimesmathbb N$. Again, thinking about this in terms of ordinals makes this problem a lot easier IMO.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:55











  • $begingroup$
    @DonThousand, what are the open sets look like in $ X times mathbbN$?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:59










  • $begingroup$
    Order topology...google is your best friend.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:59

















  • $begingroup$
    Have you tried working with ordinals? Because that would immediately answer this question.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:13










  • $begingroup$
    @DonThousand, Any finite set has all its limits points. But this est $X times mathbbN$ is discrete set, so it is closed and hence all limits points. Is it?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:42










  • $begingroup$
    I wouldn't be so sure about that. Consider $(3,1)$. Any neighborhood around $(3,1)$ must contain an element of the form $(2,n)$ for some $ninmathbb N$. So, $(3,1)$ is a limit point of $Xtimesmathbb N$. Again, thinking about this in terms of ordinals makes this problem a lot easier IMO.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:55











  • $begingroup$
    @DonThousand, what are the open sets look like in $ X times mathbbN$?
    $endgroup$
    – M. A. SARKAR
    Mar 21 at 7:59










  • $begingroup$
    Order topology...google is your best friend.
    $endgroup$
    – Don Thousand
    Mar 21 at 7:59
















$begingroup$
Have you tried working with ordinals? Because that would immediately answer this question.
$endgroup$
– Don Thousand
Mar 21 at 7:13




$begingroup$
Have you tried working with ordinals? Because that would immediately answer this question.
$endgroup$
– Don Thousand
Mar 21 at 7:13












$begingroup$
@DonThousand, Any finite set has all its limits points. But this est $X times mathbbN$ is discrete set, so it is closed and hence all limits points. Is it?
$endgroup$
– M. A. SARKAR
Mar 21 at 7:42




$begingroup$
@DonThousand, Any finite set has all its limits points. But this est $X times mathbbN$ is discrete set, so it is closed and hence all limits points. Is it?
$endgroup$
– M. A. SARKAR
Mar 21 at 7:42












$begingroup$
I wouldn't be so sure about that. Consider $(3,1)$. Any neighborhood around $(3,1)$ must contain an element of the form $(2,n)$ for some $ninmathbb N$. So, $(3,1)$ is a limit point of $Xtimesmathbb N$. Again, thinking about this in terms of ordinals makes this problem a lot easier IMO.
$endgroup$
– Don Thousand
Mar 21 at 7:55





$begingroup$
I wouldn't be so sure about that. Consider $(3,1)$. Any neighborhood around $(3,1)$ must contain an element of the form $(2,n)$ for some $ninmathbb N$. So, $(3,1)$ is a limit point of $Xtimesmathbb N$. Again, thinking about this in terms of ordinals makes this problem a lot easier IMO.
$endgroup$
– Don Thousand
Mar 21 at 7:55













$begingroup$
@DonThousand, what are the open sets look like in $ X times mathbbN$?
$endgroup$
– M. A. SARKAR
Mar 21 at 7:59




$begingroup$
@DonThousand, what are the open sets look like in $ X times mathbbN$?
$endgroup$
– M. A. SARKAR
Mar 21 at 7:59












$begingroup$
Order topology...google is your best friend.
$endgroup$
– Don Thousand
Mar 21 at 7:59





$begingroup$
Order topology...google is your best friend.
$endgroup$
– Don Thousand
Mar 21 at 7:59











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