Solving simultaneous equation for discrete mathDiscrete Math creating functions that map setsHelp with discrete math proof?Help Solving a Simultaneous Equation.When solving a simultaneous equation like this:Discrete math evaluateDiscrete Math Induction Proof Help With QuestionDiscrete Math - bitssimultaneous equation, solve for x & ySolving Simultaneous EquationDiscrete math: Prove this number is an irrational number
What reasons are there for a Capitalist to oppose a 100% inheritance tax?
Why is this clock signal connected to a capacitor to gnd?
Do scales need to be in alphabetical order?
Short story with a alien planet, government officials must wear exploding medallions
Plagiarism or not?
Why is consensus so controversial in Britain?
What does “the session was packed” mean in this context?
What do you call someone who asks many questions?
GFCI outlets - can they be repaired? Are they really needed at the end of a circuit?
Why was the shrinking from 8″ made only to 5.25″ and not smaller (4″ or less)?
ssTTsSTtRrriinInnnnNNNIiinngg
How writing a dominant 7 sus4 chord in RNA ( Vsus7 chord in the 1st inversion)
Assassin's bullet with mercury
Why would the Red Woman birth a shadow if she worshipped the Lord of the Light?
Can a human being not be part of human beings' species?
Why can't we play rap on piano?
How to prevent "they're falling in love" trope
What killed these X2 caps?
Size of subfigure fitting its content (tikzpicture)
Can we compute the area of a quadrilateral with one right angle when we only know the lengths of any three sides?
Extract rows of a table, that include less than x NULLs
Bullying boss launched a smear campaign and made me unemployable
If human space travel is limited by the G force vulnerability, is there a way to counter G forces?
Venezuelan girlfriend wants to travel the USA to be with me. What is the process?
Solving simultaneous equation for discrete math
Discrete Math creating functions that map setsHelp with discrete math proof?Help Solving a Simultaneous Equation.When solving a simultaneous equation like this:Discrete math evaluateDiscrete Math Induction Proof Help With QuestionDiscrete Math - bitssimultaneous equation, solve for x & ySolving Simultaneous EquationDiscrete math: Prove this number is an irrational number
$begingroup$
equation 1: 0 = x + y
equation 2: 1 = xr + ys
Where r = (1 + sqrt(5)) / 2, and s = (1 - sqrt(5)) / 2
my approach is to set equation 2 to 0 = xr + ys - 1 . Then, xr + ys -1 = x + y
Im not sure where to go from here.
discrete-mathematics systems-of-equations
asked Mar 21 at 5:32
Gen TanGen Tan
274
$endgroup$
add a comment |
$begingroup$
equation 1: 0 = x + y
equation 2: 1 = xr + ys
Where r = (1 + sqrt(5)) / 2, and s = (1 - sqrt(5)) / 2
my approach is to set equation 2 to 0 = xr + ys - 1 . Then, xr + ys -1 = x + y
Im not sure where to go from here.
discrete-mathematics systems-of-equations
asked Mar 21 at 5:32
Gen TanGen Tan
274
$endgroup$
2
$begingroup$
How about you use $y=-x$ from equation 1. Then what happens if you put this into equation 2?
$endgroup$
– Minus One-Twelfth
Mar 21 at 5:35
add a comment |
$begingroup$
equation 1: 0 = x + y
equation 2: 1 = xr + ys
Where r = (1 + sqrt(5)) / 2, and s = (1 - sqrt(5)) / 2
my approach is to set equation 2 to 0 = xr + ys - 1 . Then, xr + ys -1 = x + y
Im not sure where to go from here.
discrete-mathematics systems-of-equations
asked Mar 21 at 5:32
Gen TanGen Tan
274
$endgroup$
equation 1: 0 = x + y
equation 2: 1 = xr + ys
Where r = (1 + sqrt(5)) / 2, and s = (1 - sqrt(5)) / 2
my approach is to set equation 2 to 0 = xr + ys - 1 . Then, xr + ys -1 = x + y
Im not sure where to go from here.
discrete-mathematics systems-of-equations
discrete-mathematics systems-of-equations
asked Mar 21 at 5:32
Gen TanGen Tan
274
asked Mar 21 at 5:32
Gen TanGen Tan
274
asked Mar 21 at 5:32
Gen TanGen Tan
274
asked Mar 21 at 5:32
Gen TanGen Tan
274
asked Mar 21 at 5:32
Gen TanGen Tan
274
274
2
$begingroup$
How about you use $y=-x$ from equation 1. Then what happens if you put this into equation 2?
$endgroup$
– Minus One-Twelfth
Mar 21 at 5:35
add a comment |
2
$begingroup$
How about you use $y=-x$ from equation 1. Then what happens if you put this into equation 2?
$endgroup$
– Minus One-Twelfth
Mar 21 at 5:35
2
2
$begingroup$
How about you use $y=-x$ from equation 1. Then what happens if you put this into equation 2?
$endgroup$
– Minus One-Twelfth
Mar 21 at 5:35
$begingroup$
How about you use $y=-x$ from equation 1. Then what happens if you put this into equation 2?
$endgroup$
– Minus One-Twelfth
Mar 21 at 5:35
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
$$begincases x+y=0 \ xr+ys=1endcases$$
$x+y=0implies x=-y$. Substitute this in for $y$ in the second equation. $$xr-xs=1implies x=dfrac1r-s$$
Since $y=-x implies y=dfrac-1r-s$. Hence $left(x,yright)mapstoleft(dfrac1r-s, dfrac-1r-sright)$ is the solution.
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "69"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3156386%2fsolving-simultaneous-equation-for-discrete-math%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
$$begincases x+y=0 \ xr+ys=1endcases$$
$x+y=0implies x=-y$. Substitute this in for $y$ in the second equation. $$xr-xs=1implies x=dfrac1r-s$$
Since $y=-x implies y=dfrac-1r-s$. Hence $left(x,yright)mapstoleft(dfrac1r-s, dfrac-1r-sright)$ is the solution.
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
$endgroup$
add a comment |
$begingroup$
$$begincases x+y=0 \ xr+ys=1endcases$$
$x+y=0implies x=-y$. Substitute this in for $y$ in the second equation. $$xr-xs=1implies x=dfrac1r-s$$
Since $y=-x implies y=dfrac-1r-s$. Hence $left(x,yright)mapstoleft(dfrac1r-s, dfrac-1r-sright)$ is the solution.
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
$endgroup$
add a comment |
$begingroup$
$$begincases x+y=0 \ xr+ys=1endcases$$
$x+y=0implies x=-y$. Substitute this in for $y$ in the second equation. $$xr-xs=1implies x=dfrac1r-s$$
Since $y=-x implies y=dfrac-1r-s$. Hence $left(x,yright)mapstoleft(dfrac1r-s, dfrac-1r-sright)$ is the solution.
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
$endgroup$
$$begincases x+y=0 \ xr+ys=1endcases$$
$x+y=0implies x=-y$. Substitute this in for $y$ in the second equation. $$xr-xs=1implies x=dfrac1r-s$$
Since $y=-x implies y=dfrac-1r-s$. Hence $left(x,yright)mapstoleft(dfrac1r-s, dfrac-1r-sright)$ is the solution.
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
answered Mar 21 at 5:38
Paras KhoslaParas Khosla
2,782423
2,782423
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3156386%2fsolving-simultaneous-equation-for-discrete-math%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
2
$begingroup$
How about you use $y=-x$ from equation 1. Then what happens if you put this into equation 2?
$endgroup$
– Minus One-Twelfth
Mar 21 at 5:35