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nth term of the series containing one 9 then two 9 and so on


Why are multiples of 11 palindromes?Expanding PalindromesSequences of numbers palindromic in 2 consecutive number bases?How to calculate the palindrome of a given amount of characters?The quotient of two palindromesHow to make a palindromic table where each row and column is a palindrome?How many palindromes are there in the range $0000$ to $9999$?$p$ and $6p+1$ both palindrome - primes. Is $(131/787)$ the only example?Even number not the sum of two base $2$ palindromespalindrome number













-3












$begingroup$


nth term of the series 9, 99, 999, 9999.



Is there any formula for it?



9



99



999



9999



.
.
.
.










share|cite|improve this question









$endgroup$











  • $begingroup$
    9...9 with n 9’s equals 10^n - 1.
    $endgroup$
    – Jonas De Schouwer
    yesterday















-3












$begingroup$


nth term of the series 9, 99, 999, 9999.



Is there any formula for it?



9



99



999



9999



.
.
.
.










share|cite|improve this question









$endgroup$











  • $begingroup$
    9...9 with n 9’s equals 10^n - 1.
    $endgroup$
    – Jonas De Schouwer
    yesterday













-3












-3








-3





$begingroup$


nth term of the series 9, 99, 999, 9999.



Is there any formula for it?



9



99



999



9999



.
.
.
.










share|cite|improve this question









$endgroup$




nth term of the series 9, 99, 999, 9999.



Is there any formula for it?



9



99



999



9999



.
.
.
.







palindrome






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked yesterday









sroxsrox

1




1











  • $begingroup$
    9...9 with n 9’s equals 10^n - 1.
    $endgroup$
    – Jonas De Schouwer
    yesterday
















  • $begingroup$
    9...9 with n 9’s equals 10^n - 1.
    $endgroup$
    – Jonas De Schouwer
    yesterday















$begingroup$
9...9 with n 9’s equals 10^n - 1.
$endgroup$
– Jonas De Schouwer
yesterday




$begingroup$
9...9 with n 9’s equals 10^n - 1.
$endgroup$
– Jonas De Schouwer
yesterday










1 Answer
1






active

oldest

votes


















3












$begingroup$

The general formula is
$$10^n-1$$
as each term is one less than a power of $10$.






share|cite|improve this answer









$endgroup$












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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    3












    $begingroup$

    The general formula is
    $$10^n-1$$
    as each term is one less than a power of $10$.






    share|cite|improve this answer









    $endgroup$

















      3












      $begingroup$

      The general formula is
      $$10^n-1$$
      as each term is one less than a power of $10$.






      share|cite|improve this answer









      $endgroup$















        3












        3








        3





        $begingroup$

        The general formula is
        $$10^n-1$$
        as each term is one less than a power of $10$.






        share|cite|improve this answer









        $endgroup$



        The general formula is
        $$10^n-1$$
        as each term is one less than a power of $10$.







        share|cite|improve this answer












        share|cite|improve this answer



        share|cite|improve this answer










        answered yesterday









        Peter ForemanPeter Foreman

        3,2921216




        3,2921216



























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