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Expected value of a variable given a probability distribution


Normal Distribution Quantiles and Value at RiskLimit of Beta distribution on $[0, A]$ as $Arightarrow infty$ with constant expectation and variancepoisson distribution problem, expected value and variance calculationExpected value from variance?Random increment through a probability distribution functionExpected value of exponential functionIs the maximum of a probability distribution function of a Binomial distribution always the expected value?calculate the probability of normal distribution variable with conditionsGamma distribution and probability less then expected value?What is the expected value in a non-normal distribution?













0












$begingroup$


I have fitted some data with a normal and gamma distribution. But I need to find the expected value of my variable. For example is x is my data (mine is not normal) and fit them into a normal and gamma distribution. My expected value is not the same as the mean? Also for the gamma distribution the mean is alpha/beta which gives me the same as the mean.



x=rnorm(100)
m=mean(x)
v=var(x)
no=dnorm(x,m,sqrt(v))
gama=dgamma(x, ((m^2)/v),m/(v))


PS: But I think what my professor wanted me to do was: I was given a dataset of two variables and I needed to see which distribution fitted better, (it was a gamma), but after doing this the problem asked for the two distributions(Normal and gamma) to find the expected value. But I don't get if it has to be equal to the mean(x) in R. Or if I have to make an integral for this



PS2: I think for a simple way to ask. If I already fitted my data lets say to a normal(4,8) then my expected value isn't equal to 4? The same is for the gamma distribution, given alpha and beta, my mean isn't equal to alpha/beta?










share|cite|improve this question









$endgroup$











  • $begingroup$
    There is no reason why your sample's average will exactly equal the distribution's mean (expected value). Usually it will be close to it, but not exactly the same.
    $endgroup$
    – Minus One-Twelfth
    yesterday











  • $begingroup$
    @MinusOne-Twelfth Exactly, but this is the code that the professor gave us. So i don't know how to extract the expected value if those are the parameters.
    $endgroup$
    – Lexie Walker
    yesterday










  • $begingroup$
    Given only a data set, you have no way of knowing (with certainty) the expected value of the underlying distribution. It sounds like maybe your prof. wants you to fit both normal and gamma distributions, and report the means of the two fit distributions.
    $endgroup$
    – David M.
    yesterday















0












$begingroup$


I have fitted some data with a normal and gamma distribution. But I need to find the expected value of my variable. For example is x is my data (mine is not normal) and fit them into a normal and gamma distribution. My expected value is not the same as the mean? Also for the gamma distribution the mean is alpha/beta which gives me the same as the mean.



x=rnorm(100)
m=mean(x)
v=var(x)
no=dnorm(x,m,sqrt(v))
gama=dgamma(x, ((m^2)/v),m/(v))


PS: But I think what my professor wanted me to do was: I was given a dataset of two variables and I needed to see which distribution fitted better, (it was a gamma), but after doing this the problem asked for the two distributions(Normal and gamma) to find the expected value. But I don't get if it has to be equal to the mean(x) in R. Or if I have to make an integral for this



PS2: I think for a simple way to ask. If I already fitted my data lets say to a normal(4,8) then my expected value isn't equal to 4? The same is for the gamma distribution, given alpha and beta, my mean isn't equal to alpha/beta?










share|cite|improve this question









$endgroup$











  • $begingroup$
    There is no reason why your sample's average will exactly equal the distribution's mean (expected value). Usually it will be close to it, but not exactly the same.
    $endgroup$
    – Minus One-Twelfth
    yesterday











  • $begingroup$
    @MinusOne-Twelfth Exactly, but this is the code that the professor gave us. So i don't know how to extract the expected value if those are the parameters.
    $endgroup$
    – Lexie Walker
    yesterday










  • $begingroup$
    Given only a data set, you have no way of knowing (with certainty) the expected value of the underlying distribution. It sounds like maybe your prof. wants you to fit both normal and gamma distributions, and report the means of the two fit distributions.
    $endgroup$
    – David M.
    yesterday













0












0








0





$begingroup$


I have fitted some data with a normal and gamma distribution. But I need to find the expected value of my variable. For example is x is my data (mine is not normal) and fit them into a normal and gamma distribution. My expected value is not the same as the mean? Also for the gamma distribution the mean is alpha/beta which gives me the same as the mean.



x=rnorm(100)
m=mean(x)
v=var(x)
no=dnorm(x,m,sqrt(v))
gama=dgamma(x, ((m^2)/v),m/(v))


PS: But I think what my professor wanted me to do was: I was given a dataset of two variables and I needed to see which distribution fitted better, (it was a gamma), but after doing this the problem asked for the two distributions(Normal and gamma) to find the expected value. But I don't get if it has to be equal to the mean(x) in R. Or if I have to make an integral for this



PS2: I think for a simple way to ask. If I already fitted my data lets say to a normal(4,8) then my expected value isn't equal to 4? The same is for the gamma distribution, given alpha and beta, my mean isn't equal to alpha/beta?










share|cite|improve this question









$endgroup$




I have fitted some data with a normal and gamma distribution. But I need to find the expected value of my variable. For example is x is my data (mine is not normal) and fit them into a normal and gamma distribution. My expected value is not the same as the mean? Also for the gamma distribution the mean is alpha/beta which gives me the same as the mean.



x=rnorm(100)
m=mean(x)
v=var(x)
no=dnorm(x,m,sqrt(v))
gama=dgamma(x, ((m^2)/v),m/(v))


PS: But I think what my professor wanted me to do was: I was given a dataset of two variables and I needed to see which distribution fitted better, (it was a gamma), but after doing this the problem asked for the two distributions(Normal and gamma) to find the expected value. But I don't get if it has to be equal to the mean(x) in R. Or if I have to make an integral for this



PS2: I think for a simple way to ask. If I already fitted my data lets say to a normal(4,8) then my expected value isn't equal to 4? The same is for the gamma distribution, given alpha and beta, my mean isn't equal to alpha/beta?







probability






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked yesterday









Lexie WalkerLexie Walker

1597




1597











  • $begingroup$
    There is no reason why your sample's average will exactly equal the distribution's mean (expected value). Usually it will be close to it, but not exactly the same.
    $endgroup$
    – Minus One-Twelfth
    yesterday











  • $begingroup$
    @MinusOne-Twelfth Exactly, but this is the code that the professor gave us. So i don't know how to extract the expected value if those are the parameters.
    $endgroup$
    – Lexie Walker
    yesterday










  • $begingroup$
    Given only a data set, you have no way of knowing (with certainty) the expected value of the underlying distribution. It sounds like maybe your prof. wants you to fit both normal and gamma distributions, and report the means of the two fit distributions.
    $endgroup$
    – David M.
    yesterday
















  • $begingroup$
    There is no reason why your sample's average will exactly equal the distribution's mean (expected value). Usually it will be close to it, but not exactly the same.
    $endgroup$
    – Minus One-Twelfth
    yesterday











  • $begingroup$
    @MinusOne-Twelfth Exactly, but this is the code that the professor gave us. So i don't know how to extract the expected value if those are the parameters.
    $endgroup$
    – Lexie Walker
    yesterday










  • $begingroup$
    Given only a data set, you have no way of knowing (with certainty) the expected value of the underlying distribution. It sounds like maybe your prof. wants you to fit both normal and gamma distributions, and report the means of the two fit distributions.
    $endgroup$
    – David M.
    yesterday















$begingroup$
There is no reason why your sample's average will exactly equal the distribution's mean (expected value). Usually it will be close to it, but not exactly the same.
$endgroup$
– Minus One-Twelfth
yesterday





$begingroup$
There is no reason why your sample's average will exactly equal the distribution's mean (expected value). Usually it will be close to it, but not exactly the same.
$endgroup$
– Minus One-Twelfth
yesterday













$begingroup$
@MinusOne-Twelfth Exactly, but this is the code that the professor gave us. So i don't know how to extract the expected value if those are the parameters.
$endgroup$
– Lexie Walker
yesterday




$begingroup$
@MinusOne-Twelfth Exactly, but this is the code that the professor gave us. So i don't know how to extract the expected value if those are the parameters.
$endgroup$
– Lexie Walker
yesterday












$begingroup$
Given only a data set, you have no way of knowing (with certainty) the expected value of the underlying distribution. It sounds like maybe your prof. wants you to fit both normal and gamma distributions, and report the means of the two fit distributions.
$endgroup$
– David M.
yesterday




$begingroup$
Given only a data set, you have no way of knowing (with certainty) the expected value of the underlying distribution. It sounds like maybe your prof. wants you to fit both normal and gamma distributions, and report the means of the two fit distributions.
$endgroup$
– David M.
yesterday










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