Supply and Demand Functions with TaxEconomics supply and demand questionMarket optimization problemeconomics: two fully substitutable products - demand curves?!Microeconomics: Calculating Tax Revenue and Tax incidenceMaximizing total tax revenue with function $Q_s=-8+P$ and $Q_d=frac803-frac13P$Calculus in EconomicsQuestion on economics (monopolist) (will involve simple calculus)Which firm has the greater market power?Profit maximization questionCalculating Percentage of Tax Revenue

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Supply and Demand Functions with Tax


Economics supply and demand questionMarket optimization problemeconomics: two fully substitutable products - demand curves?!Microeconomics: Calculating Tax Revenue and Tax incidenceMaximizing total tax revenue with function $Q_s=-8+P$ and $Q_d=frac803-frac13P$Calculus in EconomicsQuestion on economics (monopolist) (will involve simple calculus)Which firm has the greater market power?Profit maximization questionCalculating Percentage of Tax Revenue













0












$begingroup$


I've been given the below supply and demand functions:



$q^s(p)=50p~~~~~~q^d(p)=100(frac12p-1)$



I've answered the first few questions, which include finding the equilibrium etc, and inverting the above:



$p^s(q)=fracq50~~~~~~p^d(q)=frac1200q+100-1$



Now it says the price is 1/unit and the government introduces a tax on the production of t per unit. It also says "after these changes, the demand function
remains the same, but the new inverse supply function is $p^s(q)= 1+t$



The part I'm stuck on is where it asks for a function of the total tax collected $T$, in terms of $t$. I assume that $~T=q^d*t$, so do I just sub $p=1+t$ into my original demand equation for $q^d$ then multiply that by $t$ for the answer?



$q^d(1+t)=100(frac121+t-1)=frac100(11-t)1+t$



$T=q^d*t=frac100t(11-t)1+t$










share|cite|improve this question









$endgroup$











  • $begingroup$
    $p^d(q)$ should be $frac1200q+100$
    $endgroup$
    – Akash Patel
    Mar 22 at 0:04










  • $begingroup$
    Thanks, not sure how that made its way in there
    $endgroup$
    – tom982
    Mar 25 at 19:37















0












$begingroup$


I've been given the below supply and demand functions:



$q^s(p)=50p~~~~~~q^d(p)=100(frac12p-1)$



I've answered the first few questions, which include finding the equilibrium etc, and inverting the above:



$p^s(q)=fracq50~~~~~~p^d(q)=frac1200q+100-1$



Now it says the price is 1/unit and the government introduces a tax on the production of t per unit. It also says "after these changes, the demand function
remains the same, but the new inverse supply function is $p^s(q)= 1+t$



The part I'm stuck on is where it asks for a function of the total tax collected $T$, in terms of $t$. I assume that $~T=q^d*t$, so do I just sub $p=1+t$ into my original demand equation for $q^d$ then multiply that by $t$ for the answer?



$q^d(1+t)=100(frac121+t-1)=frac100(11-t)1+t$



$T=q^d*t=frac100t(11-t)1+t$










share|cite|improve this question









$endgroup$











  • $begingroup$
    $p^d(q)$ should be $frac1200q+100$
    $endgroup$
    – Akash Patel
    Mar 22 at 0:04










  • $begingroup$
    Thanks, not sure how that made its way in there
    $endgroup$
    – tom982
    Mar 25 at 19:37













0












0








0





$begingroup$


I've been given the below supply and demand functions:



$q^s(p)=50p~~~~~~q^d(p)=100(frac12p-1)$



I've answered the first few questions, which include finding the equilibrium etc, and inverting the above:



$p^s(q)=fracq50~~~~~~p^d(q)=frac1200q+100-1$



Now it says the price is 1/unit and the government introduces a tax on the production of t per unit. It also says "after these changes, the demand function
remains the same, but the new inverse supply function is $p^s(q)= 1+t$



The part I'm stuck on is where it asks for a function of the total tax collected $T$, in terms of $t$. I assume that $~T=q^d*t$, so do I just sub $p=1+t$ into my original demand equation for $q^d$ then multiply that by $t$ for the answer?



$q^d(1+t)=100(frac121+t-1)=frac100(11-t)1+t$



$T=q^d*t=frac100t(11-t)1+t$










share|cite|improve this question









$endgroup$




I've been given the below supply and demand functions:



$q^s(p)=50p~~~~~~q^d(p)=100(frac12p-1)$



I've answered the first few questions, which include finding the equilibrium etc, and inverting the above:



$p^s(q)=fracq50~~~~~~p^d(q)=frac1200q+100-1$



Now it says the price is 1/unit and the government introduces a tax on the production of t per unit. It also says "after these changes, the demand function
remains the same, but the new inverse supply function is $p^s(q)= 1+t$



The part I'm stuck on is where it asks for a function of the total tax collected $T$, in terms of $t$. I assume that $~T=q^d*t$, so do I just sub $p=1+t$ into my original demand equation for $q^d$ then multiply that by $t$ for the answer?



$q^d(1+t)=100(frac121+t-1)=frac100(11-t)1+t$



$T=q^d*t=frac100t(11-t)1+t$







parametric economics






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 21 at 23:25









tom982tom982

2416




2416











  • $begingroup$
    $p^d(q)$ should be $frac1200q+100$
    $endgroup$
    – Akash Patel
    Mar 22 at 0:04










  • $begingroup$
    Thanks, not sure how that made its way in there
    $endgroup$
    – tom982
    Mar 25 at 19:37
















  • $begingroup$
    $p^d(q)$ should be $frac1200q+100$
    $endgroup$
    – Akash Patel
    Mar 22 at 0:04










  • $begingroup$
    Thanks, not sure how that made its way in there
    $endgroup$
    – tom982
    Mar 25 at 19:37















$begingroup$
$p^d(q)$ should be $frac1200q+100$
$endgroup$
– Akash Patel
Mar 22 at 0:04




$begingroup$
$p^d(q)$ should be $frac1200q+100$
$endgroup$
– Akash Patel
Mar 22 at 0:04












$begingroup$
Thanks, not sure how that made its way in there
$endgroup$
– tom982
Mar 25 at 19:37




$begingroup$
Thanks, not sure how that made its way in there
$endgroup$
– tom982
Mar 25 at 19:37










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