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Closest string attempted algorithm.


Confusion related to the definition of NP problemsFinding the closest point in a set to another point in n-dimensional space: efficientlyBasic encoding with math formulaFind points on $n$-dimensional grid within hypersphereequal hamming distance (or scalar product) between all pairsA communication complexity problem for finding near matchesA practical algorithm for finding distances of a set of strings?Proof of Validity of My Polynomial Time Algorithm for $co-NP$ Complete ProblemAttempted algorithm to find which shortest permutation of a string out of “hard.”Finding the numerical listed string to the center algorithm.













1












$begingroup$



In theoretical computer science, the closest string is an NP-hard
computational problem, which tries to find the geometrical center
of a set of input strings.



To understand the word "center", it is necessary to define a distance
between two strings. Usually, this problem is studied with the Hamming
distance in mind.-From wikipedia




From what I read there is some similarity between the one center problem and the closest string problem.



I've been studying the math behind the closest string and attempted an algorithm.




The algorithm takes input for a string's length for L, and the number
of strings altogether for X. The hamming distance is for input D.
Input Z calculates the exact amount of all possible characters in the
string besides the permutations for input D.



We get a set of Z amount of characters. We divide Z by D which is S.
We get B possible permutations of characters that can be generated in
a list of X strings. In other words, Z divided by Y groupings of the
same X should uniquely have B possible permutations within the Z
characters. (For the center numerical listed string based on hamming?)



If the algorithm is, correct (or I've misled). The center of Z is at
the S string which should be the B permutation.




The concept is to visualize our strings as a number line.



 Z = X * X * 1 * L + X * D * D * D + 1

S = Z / D

B = S / D

Y = S / B

CL = D * A ≤ X ≤ B * Y

P=B*Y


Here is the checks for the aforementioned.




S = S * D / D



D = Z / S




The algorithm continues if I want to find the 2nd closest, 3rd closest and so on within the S amount that was permutated within hamming distance.



NQ = S / RT

P = RT * NQ


Check to see if P=NQ. If P=NQ then the algorithm should be correct.



Closest String Wiki










share|cite|improve this question











$endgroup$
















    1












    $begingroup$



    In theoretical computer science, the closest string is an NP-hard
    computational problem, which tries to find the geometrical center
    of a set of input strings.



    To understand the word "center", it is necessary to define a distance
    between two strings. Usually, this problem is studied with the Hamming
    distance in mind.-From wikipedia




    From what I read there is some similarity between the one center problem and the closest string problem.



    I've been studying the math behind the closest string and attempted an algorithm.




    The algorithm takes input for a string's length for L, and the number
    of strings altogether for X. The hamming distance is for input D.
    Input Z calculates the exact amount of all possible characters in the
    string besides the permutations for input D.



    We get a set of Z amount of characters. We divide Z by D which is S.
    We get B possible permutations of characters that can be generated in
    a list of X strings. In other words, Z divided by Y groupings of the
    same X should uniquely have B possible permutations within the Z
    characters. (For the center numerical listed string based on hamming?)



    If the algorithm is, correct (or I've misled). The center of Z is at
    the S string which should be the B permutation.




    The concept is to visualize our strings as a number line.



     Z = X * X * 1 * L + X * D * D * D + 1

    S = Z / D

    B = S / D

    Y = S / B

    CL = D * A ≤ X ≤ B * Y

    P=B*Y


    Here is the checks for the aforementioned.




    S = S * D / D



    D = Z / S




    The algorithm continues if I want to find the 2nd closest, 3rd closest and so on within the S amount that was permutated within hamming distance.



    NQ = S / RT

    P = RT * NQ


    Check to see if P=NQ. If P=NQ then the algorithm should be correct.



    Closest String Wiki










    share|cite|improve this question











    $endgroup$














      1












      1








      1





      $begingroup$



      In theoretical computer science, the closest string is an NP-hard
      computational problem, which tries to find the geometrical center
      of a set of input strings.



      To understand the word "center", it is necessary to define a distance
      between two strings. Usually, this problem is studied with the Hamming
      distance in mind.-From wikipedia




      From what I read there is some similarity between the one center problem and the closest string problem.



      I've been studying the math behind the closest string and attempted an algorithm.




      The algorithm takes input for a string's length for L, and the number
      of strings altogether for X. The hamming distance is for input D.
      Input Z calculates the exact amount of all possible characters in the
      string besides the permutations for input D.



      We get a set of Z amount of characters. We divide Z by D which is S.
      We get B possible permutations of characters that can be generated in
      a list of X strings. In other words, Z divided by Y groupings of the
      same X should uniquely have B possible permutations within the Z
      characters. (For the center numerical listed string based on hamming?)



      If the algorithm is, correct (or I've misled). The center of Z is at
      the S string which should be the B permutation.




      The concept is to visualize our strings as a number line.



       Z = X * X * 1 * L + X * D * D * D + 1

      S = Z / D

      B = S / D

      Y = S / B

      CL = D * A ≤ X ≤ B * Y

      P=B*Y


      Here is the checks for the aforementioned.




      S = S * D / D



      D = Z / S




      The algorithm continues if I want to find the 2nd closest, 3rd closest and so on within the S amount that was permutated within hamming distance.



      NQ = S / RT

      P = RT * NQ


      Check to see if P=NQ. If P=NQ then the algorithm should be correct.



      Closest String Wiki










      share|cite|improve this question











      $endgroup$





      In theoretical computer science, the closest string is an NP-hard
      computational problem, which tries to find the geometrical center
      of a set of input strings.



      To understand the word "center", it is necessary to define a distance
      between two strings. Usually, this problem is studied with the Hamming
      distance in mind.-From wikipedia




      From what I read there is some similarity between the one center problem and the closest string problem.



      I've been studying the math behind the closest string and attempted an algorithm.




      The algorithm takes input for a string's length for L, and the number
      of strings altogether for X. The hamming distance is for input D.
      Input Z calculates the exact amount of all possible characters in the
      string besides the permutations for input D.



      We get a set of Z amount of characters. We divide Z by D which is S.
      We get B possible permutations of characters that can be generated in
      a list of X strings. In other words, Z divided by Y groupings of the
      same X should uniquely have B possible permutations within the Z
      characters. (For the center numerical listed string based on hamming?)



      If the algorithm is, correct (or I've misled). The center of Z is at
      the S string which should be the B permutation.




      The concept is to visualize our strings as a number line.



       Z = X * X * 1 * L + X * D * D * D + 1

      S = Z / D

      B = S / D

      Y = S / B

      CL = D * A ≤ X ≤ B * Y

      P=B*Y


      Here is the checks for the aforementioned.




      S = S * D / D



      D = Z / S




      The algorithm continues if I want to find the 2nd closest, 3rd closest and so on within the S amount that was permutated within hamming distance.



      NQ = S / RT

      P = RT * NQ


      Check to see if P=NQ. If P=NQ then the algorithm should be correct.



      Closest String Wiki







      linear-algebra computational-complexity np-complete






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 22 at 21:59







      Travis Wells

















      asked Mar 22 at 0:47









      Travis WellsTravis Wells

      196




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