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If one of the Dini derivatives is bounded, then f is Lipschitz
Is this condition sufficient to ensure monotonicity of a function?Calculating the Dini Derivatives of a specific function $f$ (that $f'$ IS NOT lebesgue integrable).Why continuity at a point one of Dini derivatives implies the continuity at this point others Dini derivatives?Prove that if $f$ is monotone, then the four Dini derivatives of $F$ are measureableHow to show that the Dini Derivatives of a measurable function is measurable?Need help please about Dini derivativesHow to show that the Dini derivatives of a continuous function is measurable?Existence of one-sided derivatives for a Lipschitz functionDini DerivativesProving an Inequality for Upper Right-Hand Dini Derivatives
$begingroup$
If one of its Dini derivatives (say $D^+$) is bounded show that a function $f$ satisfies a Lipschitz condition,
Definition of the upper right Dini derivative: $$D^+f(x) =
limsup_hto 0^+ fracf(x+h) - f(x)h$$
This is a question appearing in Royden's Real Analysis textbook. (Edition 3)
[Edited: The poster evidently posted this because he could not answer it [it's false], did not find a counterexample [it's easy] and did not know what the correct version of the problem should have been had Royden had a more careful editor. The problem is interesting for these reasons.]
real-analysis measure-theory derivatives
$endgroup$
add a comment |
$begingroup$
If one of its Dini derivatives (say $D^+$) is bounded show that a function $f$ satisfies a Lipschitz condition,
Definition of the upper right Dini derivative: $$D^+f(x) =
limsup_hto 0^+ fracf(x+h) - f(x)h$$
This is a question appearing in Royden's Real Analysis textbook. (Edition 3)
[Edited: The poster evidently posted this because he could not answer it [it's false], did not find a counterexample [it's easy] and did not know what the correct version of the problem should have been had Royden had a more careful editor. The problem is interesting for these reasons.]
real-analysis measure-theory derivatives
$endgroup$
add a comment |
$begingroup$
If one of its Dini derivatives (say $D^+$) is bounded show that a function $f$ satisfies a Lipschitz condition,
Definition of the upper right Dini derivative: $$D^+f(x) =
limsup_hto 0^+ fracf(x+h) - f(x)h$$
This is a question appearing in Royden's Real Analysis textbook. (Edition 3)
[Edited: The poster evidently posted this because he could not answer it [it's false], did not find a counterexample [it's easy] and did not know what the correct version of the problem should have been had Royden had a more careful editor. The problem is interesting for these reasons.]
real-analysis measure-theory derivatives
$endgroup$
If one of its Dini derivatives (say $D^+$) is bounded show that a function $f$ satisfies a Lipschitz condition,
Definition of the upper right Dini derivative: $$D^+f(x) =
limsup_hto 0^+ fracf(x+h) - f(x)h$$
This is a question appearing in Royden's Real Analysis textbook. (Edition 3)
[Edited: The poster evidently posted this because he could not answer it [it's false], did not find a counterexample [it's easy] and did not know what the correct version of the problem should have been had Royden had a more careful editor. The problem is interesting for these reasons.]
real-analysis measure-theory derivatives
real-analysis measure-theory derivatives
edited Nov 1 '15 at 6:35
Guest_000
asked Oct 30 '15 at 6:46
Guest_000Guest_000
291212
291212
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$begingroup$
I knew somebody would find a reason to distrust Royden--his text has survived way too long and none of us later textbook writers have been able to knock it out.
Take the function $f(x)=x$ for $-infty < x < 0$ and $f(x)=1+x$ for $0leq x < infty$. Then $D^+f(x) =1 $ at every point but no Lipschitz condition and not even continuous.
The result that Royden was going for was a theorem of Dini's from 1878.
U. Dini, Fondamenti per la teoretica delle funzione di variabli
reali, Pisa 1878.
But Dini assumed that $f$ is continuous!
There is a full account in S. Saks, Theory of the Integral (1937) p.~204.
P.S. Royden's first edition was from 1963. The third edition, which is the only one I have, is from 1988 and the mistake survives in that edition. Does anyone have a later edition where the problem was corrected?
$endgroup$
add a comment |
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$begingroup$
I knew somebody would find a reason to distrust Royden--his text has survived way too long and none of us later textbook writers have been able to knock it out.
Take the function $f(x)=x$ for $-infty < x < 0$ and $f(x)=1+x$ for $0leq x < infty$. Then $D^+f(x) =1 $ at every point but no Lipschitz condition and not even continuous.
The result that Royden was going for was a theorem of Dini's from 1878.
U. Dini, Fondamenti per la teoretica delle funzione di variabli
reali, Pisa 1878.
But Dini assumed that $f$ is continuous!
There is a full account in S. Saks, Theory of the Integral (1937) p.~204.
P.S. Royden's first edition was from 1963. The third edition, which is the only one I have, is from 1988 and the mistake survives in that edition. Does anyone have a later edition where the problem was corrected?
$endgroup$
add a comment |
$begingroup$
I knew somebody would find a reason to distrust Royden--his text has survived way too long and none of us later textbook writers have been able to knock it out.
Take the function $f(x)=x$ for $-infty < x < 0$ and $f(x)=1+x$ for $0leq x < infty$. Then $D^+f(x) =1 $ at every point but no Lipschitz condition and not even continuous.
The result that Royden was going for was a theorem of Dini's from 1878.
U. Dini, Fondamenti per la teoretica delle funzione di variabli
reali, Pisa 1878.
But Dini assumed that $f$ is continuous!
There is a full account in S. Saks, Theory of the Integral (1937) p.~204.
P.S. Royden's first edition was from 1963. The third edition, which is the only one I have, is from 1988 and the mistake survives in that edition. Does anyone have a later edition where the problem was corrected?
$endgroup$
add a comment |
$begingroup$
I knew somebody would find a reason to distrust Royden--his text has survived way too long and none of us later textbook writers have been able to knock it out.
Take the function $f(x)=x$ for $-infty < x < 0$ and $f(x)=1+x$ for $0leq x < infty$. Then $D^+f(x) =1 $ at every point but no Lipschitz condition and not even continuous.
The result that Royden was going for was a theorem of Dini's from 1878.
U. Dini, Fondamenti per la teoretica delle funzione di variabli
reali, Pisa 1878.
But Dini assumed that $f$ is continuous!
There is a full account in S. Saks, Theory of the Integral (1937) p.~204.
P.S. Royden's first edition was from 1963. The third edition, which is the only one I have, is from 1988 and the mistake survives in that edition. Does anyone have a later edition where the problem was corrected?
$endgroup$
I knew somebody would find a reason to distrust Royden--his text has survived way too long and none of us later textbook writers have been able to knock it out.
Take the function $f(x)=x$ for $-infty < x < 0$ and $f(x)=1+x$ for $0leq x < infty$. Then $D^+f(x) =1 $ at every point but no Lipschitz condition and not even continuous.
The result that Royden was going for was a theorem of Dini's from 1878.
U. Dini, Fondamenti per la teoretica delle funzione di variabli
reali, Pisa 1878.
But Dini assumed that $f$ is continuous!
There is a full account in S. Saks, Theory of the Integral (1937) p.~204.
P.S. Royden's first edition was from 1963. The third edition, which is the only one I have, is from 1988 and the mistake survives in that edition. Does anyone have a later edition where the problem was corrected?
edited Oct 30 '15 at 16:38
answered Oct 30 '15 at 15:53
B. S. ThomsonB. S. Thomson
2,9351517
2,9351517
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