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Intuition underlying a linear algebra result


Linear algebra question involving principal submatriceslinear algebra linear transformation eigenvector and eigenvalueslinear map questionlinear algebra : matrix decompositionLinear Algebra True/FlaseLinear Algebra Proof for matricesLinear Algebra basis. What does it mean?Linear Algebra Tensor ProofTrue or False Linear Algebra Matrix UnderstandingLinear Algebra Ordered Basis













0












$begingroup$


RESULT



For any $mtimes n$ matrix $textbfA$ and $mtimes p$ matrix $textbfB$, $mathcalC(B)subsetmathcalC(A)$ if and only if there exists an $ntimes p$ matrix $textbfF$ such that $textbfB = textbfAtextbfF$, where $mathcalC(X)$ represents the column space of $textbfX$.



MY QUESTION



I would like to know if someone could provide me an intuition underlying this matrix analysis result. Any help is appreciated. Thanks in advance.










share|cite|improve this question









$endgroup$
















    0












    $begingroup$


    RESULT



    For any $mtimes n$ matrix $textbfA$ and $mtimes p$ matrix $textbfB$, $mathcalC(B)subsetmathcalC(A)$ if and only if there exists an $ntimes p$ matrix $textbfF$ such that $textbfB = textbfAtextbfF$, where $mathcalC(X)$ represents the column space of $textbfX$.



    MY QUESTION



    I would like to know if someone could provide me an intuition underlying this matrix analysis result. Any help is appreciated. Thanks in advance.










    share|cite|improve this question









    $endgroup$














      0












      0








      0





      $begingroup$


      RESULT



      For any $mtimes n$ matrix $textbfA$ and $mtimes p$ matrix $textbfB$, $mathcalC(B)subsetmathcalC(A)$ if and only if there exists an $ntimes p$ matrix $textbfF$ such that $textbfB = textbfAtextbfF$, where $mathcalC(X)$ represents the column space of $textbfX$.



      MY QUESTION



      I would like to know if someone could provide me an intuition underlying this matrix analysis result. Any help is appreciated. Thanks in advance.










      share|cite|improve this question









      $endgroup$




      RESULT



      For any $mtimes n$ matrix $textbfA$ and $mtimes p$ matrix $textbfB$, $mathcalC(B)subsetmathcalC(A)$ if and only if there exists an $ntimes p$ matrix $textbfF$ such that $textbfB = textbfAtextbfF$, where $mathcalC(X)$ represents the column space of $textbfX$.



      MY QUESTION



      I would like to know if someone could provide me an intuition underlying this matrix analysis result. Any help is appreciated. Thanks in advance.







      linear-algebra matrices






      share|cite|improve this question













      share|cite|improve this question











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      share|cite|improve this question










      asked Mar 21 at 23:26









      user1337user1337

      47210




      47210




















          1 Answer
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          $begingroup$

          The condition $cal C(B)subset cal B(A)$ means that every column of $B$ is a linear combination of columns of $A$. How many scalars do you need for each column of $B$? Well, as many as $A$'s column. More succinctly,
          $B=AF$
          for some $ntimes p$ matrix $F$. Why $p$ columns? That's because $B$ has $p$ columns.






          share|cite|improve this answer









          $endgroup$













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            $begingroup$

            The condition $cal C(B)subset cal B(A)$ means that every column of $B$ is a linear combination of columns of $A$. How many scalars do you need for each column of $B$? Well, as many as $A$'s column. More succinctly,
            $B=AF$
            for some $ntimes p$ matrix $F$. Why $p$ columns? That's because $B$ has $p$ columns.






            share|cite|improve this answer









            $endgroup$

















              2












              $begingroup$

              The condition $cal C(B)subset cal B(A)$ means that every column of $B$ is a linear combination of columns of $A$. How many scalars do you need for each column of $B$? Well, as many as $A$'s column. More succinctly,
              $B=AF$
              for some $ntimes p$ matrix $F$. Why $p$ columns? That's because $B$ has $p$ columns.






              share|cite|improve this answer









              $endgroup$















                2












                2








                2





                $begingroup$

                The condition $cal C(B)subset cal B(A)$ means that every column of $B$ is a linear combination of columns of $A$. How many scalars do you need for each column of $B$? Well, as many as $A$'s column. More succinctly,
                $B=AF$
                for some $ntimes p$ matrix $F$. Why $p$ columns? That's because $B$ has $p$ columns.






                share|cite|improve this answer









                $endgroup$



                The condition $cal C(B)subset cal B(A)$ means that every column of $B$ is a linear combination of columns of $A$. How many scalars do you need for each column of $B$? Well, as many as $A$'s column. More succinctly,
                $B=AF$
                for some $ntimes p$ matrix $F$. Why $p$ columns? That's because $B$ has $p$ columns.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 21 at 23:32









                chhrochhro

                1,442311




                1,442311



























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