Jacobi Elliptic Functions Special CaseCan this integral $int_0^2pi fracdtheta(a^2 cos^2 theta +b^2sin^2theta)^3/2$ be written in the form of a elliptic integralIntegral involving Complete Elliptic Integral of the First Kind K(k)How to compute elliptic integrals in MATLABDoes $int_0^2 pi sqrt1-(a+b sinphi)^2 dphi $ have a closed form in terms of elliptic integrals?Elliptic IntegralsAn elliptic integral?Curious integrals for Jacobi Theta Functions $int_0^1 vartheta_n(0,q)dq$Jacobian Elliptic FunctionsCan $int_0^inftyfracdxsqrt[leftroot-1uproot1n]x(x+a^n)(x+1)^n-1$ be expressed with an elliptic integral?How does one express the length of curves in terms of the elliptic integral

Why "Having chlorophyll without photosynthesis is actually very dangerous" and "like living with a bomb"?

How old can references or sources in a thesis be?

Smoothness of finite-dimensional functional calculus

Show that if two triangles built on parallel lines, with equal bases have the same perimeter only if they are congruent.

Why are electrically insulating heatsinks so rare? Is it just cost?

Problem of parity - Can we draw a closed path made up of 20 line segments...

What's the point of deactivating Num Lock on login screens?

Why Is Death Allowed In the Matrix?

Service Entrance Breakers Rain Shield

What does it mean to describe someone as a butt steak?

How to test if a transaction is standard without spending real money?

Email Account under attack (really) - anything I can do?

LaTeX closing $ signs makes cursor jump

How do we improve the relationship with a client software team that performs poorly and is becoming less collaborative?

How is it possible to have an ability score that is less than 3?

Can divisibility rules for digits be generalized to sum of digits

Have astronauts in space suits ever taken selfies? If so, how?

How does one intimidate enemies without having the capacity for violence?

Is it legal for company to use my work email to pretend I still work there?

Today is the Center

The Two and the One

Prove that NP is closed under karp reduction?

Theorems that impeded progress

"You are your self first supporter", a more proper way to say it



Jacobi Elliptic Functions Special Case


Can this integral $int_0^2pi fracdtheta(a^2 cos^2 theta +b^2sin^2theta)^3/2$ be written in the form of a elliptic integralIntegral involving Complete Elliptic Integral of the First Kind K(k)How to compute elliptic integrals in MATLABDoes $int_0^2 pi sqrt1-(a+b sinphi)^2 dphi $ have a closed form in terms of elliptic integrals?Elliptic IntegralsAn elliptic integral?Curious integrals for Jacobi Theta Functions $int_0^1 vartheta_n(0,q)dq$Jacobian Elliptic FunctionsCan $int_0^inftyfracdxsqrt[leftroot-1uproot1n]x(x+a^n)(x+1)^n-1$ be expressed with an elliptic integral?How does one express the length of curves in terms of the elliptic integral













3












$begingroup$


I have spent some time analysing the pendulum problem, and hence the Jacobi elliptic functions recently, and have come across what seems to me to be a slight inconsitency.
I define my $mathrmam(t|k)$ as the inverse to the integral
$$int_0^t (1-k^2 sin^2x)^-1/2 , mathrmdx = mathrmam^-1(t|k) $$
And I'm interested in the special case of $k^2 = 2$



I understand the Jacobi elliptic functions to be defined as parametrising the ellipse
$$x^2 + fracy^2b^2 = 1$$
and $k^2 = 1-b^-2$. Then parametrise the ellipse by $x = mathrmcn(t|k)$, $y = b ,mathrmsn(t|k)$. In the special case of $k = 0$ it's simple to show that the ellipse becomes a circle, and these functions reduce to standard trig functions, and for $k = 1$ that the ellipse becomes two parallel lines, and that the elliptic functions reduce to $tanh$ and $mathrmsech$.



Now let $b = i beta$, and the ellipse becomes a hyperbola. $k^2 = 1 + beta^2$, and the special case of $beta = 1$ is the rectangular hyperbola
$$x^2 - y^2 = 1$$



This corresponds to $k^2 = 2$, so my claim is that it should be possible to solve the integrals for the elliptic functions in this case to give
$$ mathrmsn(t|sqrt2) = sinh(t)$$
$$ mathrmcn(t|sqrt2) = cosh(t)$$
Which would then agree with the parametrisation of the original ellipse equation, with $b = i$



However the defining integral reduces to
$$int_0^t sqrtsec(2x) , mathrmdx = mathrmam^-1(t|sqrt2) $$
Which I don't believe to be integrable in terms of non-special functions. (I have spent quite a long time trying different substitutions and trig rearrangements on this integral and not had much luck).



Does anyone have any thoughts on this?










share|cite|improve this question











$endgroup$
















    3












    $begingroup$


    I have spent some time analysing the pendulum problem, and hence the Jacobi elliptic functions recently, and have come across what seems to me to be a slight inconsitency.
    I define my $mathrmam(t|k)$ as the inverse to the integral
    $$int_0^t (1-k^2 sin^2x)^-1/2 , mathrmdx = mathrmam^-1(t|k) $$
    And I'm interested in the special case of $k^2 = 2$



    I understand the Jacobi elliptic functions to be defined as parametrising the ellipse
    $$x^2 + fracy^2b^2 = 1$$
    and $k^2 = 1-b^-2$. Then parametrise the ellipse by $x = mathrmcn(t|k)$, $y = b ,mathrmsn(t|k)$. In the special case of $k = 0$ it's simple to show that the ellipse becomes a circle, and these functions reduce to standard trig functions, and for $k = 1$ that the ellipse becomes two parallel lines, and that the elliptic functions reduce to $tanh$ and $mathrmsech$.



    Now let $b = i beta$, and the ellipse becomes a hyperbola. $k^2 = 1 + beta^2$, and the special case of $beta = 1$ is the rectangular hyperbola
    $$x^2 - y^2 = 1$$



    This corresponds to $k^2 = 2$, so my claim is that it should be possible to solve the integrals for the elliptic functions in this case to give
    $$ mathrmsn(t|sqrt2) = sinh(t)$$
    $$ mathrmcn(t|sqrt2) = cosh(t)$$
    Which would then agree with the parametrisation of the original ellipse equation, with $b = i$



    However the defining integral reduces to
    $$int_0^t sqrtsec(2x) , mathrmdx = mathrmam^-1(t|sqrt2) $$
    Which I don't believe to be integrable in terms of non-special functions. (I have spent quite a long time trying different substitutions and trig rearrangements on this integral and not had much luck).



    Does anyone have any thoughts on this?










    share|cite|improve this question











    $endgroup$














      3












      3








      3





      $begingroup$


      I have spent some time analysing the pendulum problem, and hence the Jacobi elliptic functions recently, and have come across what seems to me to be a slight inconsitency.
      I define my $mathrmam(t|k)$ as the inverse to the integral
      $$int_0^t (1-k^2 sin^2x)^-1/2 , mathrmdx = mathrmam^-1(t|k) $$
      And I'm interested in the special case of $k^2 = 2$



      I understand the Jacobi elliptic functions to be defined as parametrising the ellipse
      $$x^2 + fracy^2b^2 = 1$$
      and $k^2 = 1-b^-2$. Then parametrise the ellipse by $x = mathrmcn(t|k)$, $y = b ,mathrmsn(t|k)$. In the special case of $k = 0$ it's simple to show that the ellipse becomes a circle, and these functions reduce to standard trig functions, and for $k = 1$ that the ellipse becomes two parallel lines, and that the elliptic functions reduce to $tanh$ and $mathrmsech$.



      Now let $b = i beta$, and the ellipse becomes a hyperbola. $k^2 = 1 + beta^2$, and the special case of $beta = 1$ is the rectangular hyperbola
      $$x^2 - y^2 = 1$$



      This corresponds to $k^2 = 2$, so my claim is that it should be possible to solve the integrals for the elliptic functions in this case to give
      $$ mathrmsn(t|sqrt2) = sinh(t)$$
      $$ mathrmcn(t|sqrt2) = cosh(t)$$
      Which would then agree with the parametrisation of the original ellipse equation, with $b = i$



      However the defining integral reduces to
      $$int_0^t sqrtsec(2x) , mathrmdx = mathrmam^-1(t|sqrt2) $$
      Which I don't believe to be integrable in terms of non-special functions. (I have spent quite a long time trying different substitutions and trig rearrangements on this integral and not had much luck).



      Does anyone have any thoughts on this?










      share|cite|improve this question











      $endgroup$




      I have spent some time analysing the pendulum problem, and hence the Jacobi elliptic functions recently, and have come across what seems to me to be a slight inconsitency.
      I define my $mathrmam(t|k)$ as the inverse to the integral
      $$int_0^t (1-k^2 sin^2x)^-1/2 , mathrmdx = mathrmam^-1(t|k) $$
      And I'm interested in the special case of $k^2 = 2$



      I understand the Jacobi elliptic functions to be defined as parametrising the ellipse
      $$x^2 + fracy^2b^2 = 1$$
      and $k^2 = 1-b^-2$. Then parametrise the ellipse by $x = mathrmcn(t|k)$, $y = b ,mathrmsn(t|k)$. In the special case of $k = 0$ it's simple to show that the ellipse becomes a circle, and these functions reduce to standard trig functions, and for $k = 1$ that the ellipse becomes two parallel lines, and that the elliptic functions reduce to $tanh$ and $mathrmsech$.



      Now let $b = i beta$, and the ellipse becomes a hyperbola. $k^2 = 1 + beta^2$, and the special case of $beta = 1$ is the rectangular hyperbola
      $$x^2 - y^2 = 1$$



      This corresponds to $k^2 = 2$, so my claim is that it should be possible to solve the integrals for the elliptic functions in this case to give
      $$ mathrmsn(t|sqrt2) = sinh(t)$$
      $$ mathrmcn(t|sqrt2) = cosh(t)$$
      Which would then agree with the parametrisation of the original ellipse equation, with $b = i$



      However the defining integral reduces to
      $$int_0^t sqrtsec(2x) , mathrmdx = mathrmam^-1(t|sqrt2) $$
      Which I don't believe to be integrable in terms of non-special functions. (I have spent quite a long time trying different substitutions and trig rearrangements on this integral and not had much luck).



      Does anyone have any thoughts on this?







      integration geometry functions






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited Mar 22 at 3:50









      clathratus

      5,0991439




      5,0991439










      asked Dec 17 '14 at 15:38









      JoeJoe

      1456




      1456




















          1 Answer
          1






          active

          oldest

          votes


















          2












          $begingroup$

          Hmm, something's wrong here... The function $f(z)=operatornamesn(z,sqrt2)$ is definitely not equal to $sinh z$. There's a transformation formula which gives $f(z)=operatornamesn(zsqrt2,1/sqrt2)/sqrt2$, and this is a Jacobi sn function with $0<k<1$, which (as you probably know) implies that it is periodic on the real axis and also doubly periodic in the complex plane (unlike $sinh z$).



          I haven't thought about what exactly goes wrong in your reasoning, but
          I think that maybe you are putting too much emphasis on the formula $x^2 + fracy^2b^2=1$. That formula alone isn't enough to define the elliptic functions, since for example $(x,y)=(cos t,b sin t)$ is another perfectly good parametrization of the ellipse, with good old trig functions.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Yes I think I can see that it can't be equal to $sinh$, I had been looking at that transformation formula, and also if the Jacobi functions were equal to the hyperbolic functions, they couldn't satisfy $sn^2 + cn^2 = 1$ either. But I still feel like the ellipse equation reducing to a rectangular hyperbola for $k^2 = 2$ is enough to signify that there should be a simplification for Jacobi functions though
            $endgroup$
            – Joe
            Dec 18 '14 at 21:59











          • $begingroup$
            Well, the Jacobi sn and cn functions parametrize the unit circle for any $k$, but this doesn't imply that they can be simplified to elementary functions...
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 11:11










          • $begingroup$
            No most definitely not, but the fact that the same parametrization that they use for the ellipse reduces to the circle for $k = 0$ does imply that they can be simplified to elementary functions in this case, and to me this is analagous to the hyperbola becoming a rectangular hyperbola for $k^2 = 2$
            $endgroup$
            – Joe
            Dec 19 '14 at 21:38










          • $begingroup$
            Well, to be honest I don't understand your argument at all. The fact that sn and cn reduce to trig functions for $k=0$ does not follow merely from the fact that they happen to parametrize the circle in that case, you need to look at their definitions. After all, they parametrize the circle for every $k$, but for $k neq 0$ (or $1$) they don't simplify.
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 22:17











          • $begingroup$
            Ah, I think in previous comment, 'suggests' would have been a better word than 'implies', (although I think it might be an implication). I am defining the Jacobi Elliptic functions in terms of properties on the ellipse. I define the elliptic angular measure, $am(phi|k)$, which is like an extension of the radian to `elliptical angular units'. Then you take $sin$ and $cos$ (and the $dn$ function) of it to give the elliptic functions. Then as $k->0$ we recover the circle, and $am(phi|0) = phi$.
            $endgroup$
            – Joe
            Dec 20 '14 at 1:05












          Your Answer





          StackExchange.ifUsing("editor", function ()
          return StackExchange.using("mathjaxEditing", function ()
          StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
          StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
          );
          );
          , "mathjax-editing");

          StackExchange.ready(function()
          var channelOptions =
          tags: "".split(" "),
          id: "69"
          ;
          initTagRenderer("".split(" "), "".split(" "), channelOptions);

          StackExchange.using("externalEditor", function()
          // Have to fire editor after snippets, if snippets enabled
          if (StackExchange.settings.snippets.snippetsEnabled)
          StackExchange.using("snippets", function()
          createEditor();
          );

          else
          createEditor();

          );

          function createEditor()
          StackExchange.prepareEditor(
          heartbeatType: 'answer',
          autoActivateHeartbeat: false,
          convertImagesToLinks: true,
          noModals: true,
          showLowRepImageUploadWarning: true,
          reputationToPostImages: 10,
          bindNavPrevention: true,
          postfix: "",
          imageUploader:
          brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
          contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
          allowUrls: true
          ,
          noCode: true, onDemand: true,
          discardSelector: ".discard-answer"
          ,immediatelyShowMarkdownHelp:true
          );



          );













          draft saved

          draft discarded


















          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1072098%2fjacobi-elliptic-functions-special-case%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown

























          1 Answer
          1






          active

          oldest

          votes








          1 Answer
          1






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          2












          $begingroup$

          Hmm, something's wrong here... The function $f(z)=operatornamesn(z,sqrt2)$ is definitely not equal to $sinh z$. There's a transformation formula which gives $f(z)=operatornamesn(zsqrt2,1/sqrt2)/sqrt2$, and this is a Jacobi sn function with $0<k<1$, which (as you probably know) implies that it is periodic on the real axis and also doubly periodic in the complex plane (unlike $sinh z$).



          I haven't thought about what exactly goes wrong in your reasoning, but
          I think that maybe you are putting too much emphasis on the formula $x^2 + fracy^2b^2=1$. That formula alone isn't enough to define the elliptic functions, since for example $(x,y)=(cos t,b sin t)$ is another perfectly good parametrization of the ellipse, with good old trig functions.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Yes I think I can see that it can't be equal to $sinh$, I had been looking at that transformation formula, and also if the Jacobi functions were equal to the hyperbolic functions, they couldn't satisfy $sn^2 + cn^2 = 1$ either. But I still feel like the ellipse equation reducing to a rectangular hyperbola for $k^2 = 2$ is enough to signify that there should be a simplification for Jacobi functions though
            $endgroup$
            – Joe
            Dec 18 '14 at 21:59











          • $begingroup$
            Well, the Jacobi sn and cn functions parametrize the unit circle for any $k$, but this doesn't imply that they can be simplified to elementary functions...
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 11:11










          • $begingroup$
            No most definitely not, but the fact that the same parametrization that they use for the ellipse reduces to the circle for $k = 0$ does imply that they can be simplified to elementary functions in this case, and to me this is analagous to the hyperbola becoming a rectangular hyperbola for $k^2 = 2$
            $endgroup$
            – Joe
            Dec 19 '14 at 21:38










          • $begingroup$
            Well, to be honest I don't understand your argument at all. The fact that sn and cn reduce to trig functions for $k=0$ does not follow merely from the fact that they happen to parametrize the circle in that case, you need to look at their definitions. After all, they parametrize the circle for every $k$, but for $k neq 0$ (or $1$) they don't simplify.
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 22:17











          • $begingroup$
            Ah, I think in previous comment, 'suggests' would have been a better word than 'implies', (although I think it might be an implication). I am defining the Jacobi Elliptic functions in terms of properties on the ellipse. I define the elliptic angular measure, $am(phi|k)$, which is like an extension of the radian to `elliptical angular units'. Then you take $sin$ and $cos$ (and the $dn$ function) of it to give the elliptic functions. Then as $k->0$ we recover the circle, and $am(phi|0) = phi$.
            $endgroup$
            – Joe
            Dec 20 '14 at 1:05
















          2












          $begingroup$

          Hmm, something's wrong here... The function $f(z)=operatornamesn(z,sqrt2)$ is definitely not equal to $sinh z$. There's a transformation formula which gives $f(z)=operatornamesn(zsqrt2,1/sqrt2)/sqrt2$, and this is a Jacobi sn function with $0<k<1$, which (as you probably know) implies that it is periodic on the real axis and also doubly periodic in the complex plane (unlike $sinh z$).



          I haven't thought about what exactly goes wrong in your reasoning, but
          I think that maybe you are putting too much emphasis on the formula $x^2 + fracy^2b^2=1$. That formula alone isn't enough to define the elliptic functions, since for example $(x,y)=(cos t,b sin t)$ is another perfectly good parametrization of the ellipse, with good old trig functions.






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Yes I think I can see that it can't be equal to $sinh$, I had been looking at that transformation formula, and also if the Jacobi functions were equal to the hyperbolic functions, they couldn't satisfy $sn^2 + cn^2 = 1$ either. But I still feel like the ellipse equation reducing to a rectangular hyperbola for $k^2 = 2$ is enough to signify that there should be a simplification for Jacobi functions though
            $endgroup$
            – Joe
            Dec 18 '14 at 21:59











          • $begingroup$
            Well, the Jacobi sn and cn functions parametrize the unit circle for any $k$, but this doesn't imply that they can be simplified to elementary functions...
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 11:11










          • $begingroup$
            No most definitely not, but the fact that the same parametrization that they use for the ellipse reduces to the circle for $k = 0$ does imply that they can be simplified to elementary functions in this case, and to me this is analagous to the hyperbola becoming a rectangular hyperbola for $k^2 = 2$
            $endgroup$
            – Joe
            Dec 19 '14 at 21:38










          • $begingroup$
            Well, to be honest I don't understand your argument at all. The fact that sn and cn reduce to trig functions for $k=0$ does not follow merely from the fact that they happen to parametrize the circle in that case, you need to look at their definitions. After all, they parametrize the circle for every $k$, but for $k neq 0$ (or $1$) they don't simplify.
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 22:17











          • $begingroup$
            Ah, I think in previous comment, 'suggests' would have been a better word than 'implies', (although I think it might be an implication). I am defining the Jacobi Elliptic functions in terms of properties on the ellipse. I define the elliptic angular measure, $am(phi|k)$, which is like an extension of the radian to `elliptical angular units'. Then you take $sin$ and $cos$ (and the $dn$ function) of it to give the elliptic functions. Then as $k->0$ we recover the circle, and $am(phi|0) = phi$.
            $endgroup$
            – Joe
            Dec 20 '14 at 1:05














          2












          2








          2





          $begingroup$

          Hmm, something's wrong here... The function $f(z)=operatornamesn(z,sqrt2)$ is definitely not equal to $sinh z$. There's a transformation formula which gives $f(z)=operatornamesn(zsqrt2,1/sqrt2)/sqrt2$, and this is a Jacobi sn function with $0<k<1$, which (as you probably know) implies that it is periodic on the real axis and also doubly periodic in the complex plane (unlike $sinh z$).



          I haven't thought about what exactly goes wrong in your reasoning, but
          I think that maybe you are putting too much emphasis on the formula $x^2 + fracy^2b^2=1$. That formula alone isn't enough to define the elliptic functions, since for example $(x,y)=(cos t,b sin t)$ is another perfectly good parametrization of the ellipse, with good old trig functions.






          share|cite|improve this answer









          $endgroup$



          Hmm, something's wrong here... The function $f(z)=operatornamesn(z,sqrt2)$ is definitely not equal to $sinh z$. There's a transformation formula which gives $f(z)=operatornamesn(zsqrt2,1/sqrt2)/sqrt2$, and this is a Jacobi sn function with $0<k<1$, which (as you probably know) implies that it is periodic on the real axis and also doubly periodic in the complex plane (unlike $sinh z$).



          I haven't thought about what exactly goes wrong in your reasoning, but
          I think that maybe you are putting too much emphasis on the formula $x^2 + fracy^2b^2=1$. That formula alone isn't enough to define the elliptic functions, since for example $(x,y)=(cos t,b sin t)$ is another perfectly good parametrization of the ellipse, with good old trig functions.







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Dec 18 '14 at 15:55









          Hans LundmarkHans Lundmark

          36.1k564115




          36.1k564115











          • $begingroup$
            Yes I think I can see that it can't be equal to $sinh$, I had been looking at that transformation formula, and also if the Jacobi functions were equal to the hyperbolic functions, they couldn't satisfy $sn^2 + cn^2 = 1$ either. But I still feel like the ellipse equation reducing to a rectangular hyperbola for $k^2 = 2$ is enough to signify that there should be a simplification for Jacobi functions though
            $endgroup$
            – Joe
            Dec 18 '14 at 21:59











          • $begingroup$
            Well, the Jacobi sn and cn functions parametrize the unit circle for any $k$, but this doesn't imply that they can be simplified to elementary functions...
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 11:11










          • $begingroup$
            No most definitely not, but the fact that the same parametrization that they use for the ellipse reduces to the circle for $k = 0$ does imply that they can be simplified to elementary functions in this case, and to me this is analagous to the hyperbola becoming a rectangular hyperbola for $k^2 = 2$
            $endgroup$
            – Joe
            Dec 19 '14 at 21:38










          • $begingroup$
            Well, to be honest I don't understand your argument at all. The fact that sn and cn reduce to trig functions for $k=0$ does not follow merely from the fact that they happen to parametrize the circle in that case, you need to look at their definitions. After all, they parametrize the circle for every $k$, but for $k neq 0$ (or $1$) they don't simplify.
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 22:17











          • $begingroup$
            Ah, I think in previous comment, 'suggests' would have been a better word than 'implies', (although I think it might be an implication). I am defining the Jacobi Elliptic functions in terms of properties on the ellipse. I define the elliptic angular measure, $am(phi|k)$, which is like an extension of the radian to `elliptical angular units'. Then you take $sin$ and $cos$ (and the $dn$ function) of it to give the elliptic functions. Then as $k->0$ we recover the circle, and $am(phi|0) = phi$.
            $endgroup$
            – Joe
            Dec 20 '14 at 1:05

















          • $begingroup$
            Yes I think I can see that it can't be equal to $sinh$, I had been looking at that transformation formula, and also if the Jacobi functions were equal to the hyperbolic functions, they couldn't satisfy $sn^2 + cn^2 = 1$ either. But I still feel like the ellipse equation reducing to a rectangular hyperbola for $k^2 = 2$ is enough to signify that there should be a simplification for Jacobi functions though
            $endgroup$
            – Joe
            Dec 18 '14 at 21:59











          • $begingroup$
            Well, the Jacobi sn and cn functions parametrize the unit circle for any $k$, but this doesn't imply that they can be simplified to elementary functions...
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 11:11










          • $begingroup$
            No most definitely not, but the fact that the same parametrization that they use for the ellipse reduces to the circle for $k = 0$ does imply that they can be simplified to elementary functions in this case, and to me this is analagous to the hyperbola becoming a rectangular hyperbola for $k^2 = 2$
            $endgroup$
            – Joe
            Dec 19 '14 at 21:38










          • $begingroup$
            Well, to be honest I don't understand your argument at all. The fact that sn and cn reduce to trig functions for $k=0$ does not follow merely from the fact that they happen to parametrize the circle in that case, you need to look at their definitions. After all, they parametrize the circle for every $k$, but for $k neq 0$ (or $1$) they don't simplify.
            $endgroup$
            – Hans Lundmark
            Dec 19 '14 at 22:17











          • $begingroup$
            Ah, I think in previous comment, 'suggests' would have been a better word than 'implies', (although I think it might be an implication). I am defining the Jacobi Elliptic functions in terms of properties on the ellipse. I define the elliptic angular measure, $am(phi|k)$, which is like an extension of the radian to `elliptical angular units'. Then you take $sin$ and $cos$ (and the $dn$ function) of it to give the elliptic functions. Then as $k->0$ we recover the circle, and $am(phi|0) = phi$.
            $endgroup$
            – Joe
            Dec 20 '14 at 1:05
















          $begingroup$
          Yes I think I can see that it can't be equal to $sinh$, I had been looking at that transformation formula, and also if the Jacobi functions were equal to the hyperbolic functions, they couldn't satisfy $sn^2 + cn^2 = 1$ either. But I still feel like the ellipse equation reducing to a rectangular hyperbola for $k^2 = 2$ is enough to signify that there should be a simplification for Jacobi functions though
          $endgroup$
          – Joe
          Dec 18 '14 at 21:59





          $begingroup$
          Yes I think I can see that it can't be equal to $sinh$, I had been looking at that transformation formula, and also if the Jacobi functions were equal to the hyperbolic functions, they couldn't satisfy $sn^2 + cn^2 = 1$ either. But I still feel like the ellipse equation reducing to a rectangular hyperbola for $k^2 = 2$ is enough to signify that there should be a simplification for Jacobi functions though
          $endgroup$
          – Joe
          Dec 18 '14 at 21:59













          $begingroup$
          Well, the Jacobi sn and cn functions parametrize the unit circle for any $k$, but this doesn't imply that they can be simplified to elementary functions...
          $endgroup$
          – Hans Lundmark
          Dec 19 '14 at 11:11




          $begingroup$
          Well, the Jacobi sn and cn functions parametrize the unit circle for any $k$, but this doesn't imply that they can be simplified to elementary functions...
          $endgroup$
          – Hans Lundmark
          Dec 19 '14 at 11:11












          $begingroup$
          No most definitely not, but the fact that the same parametrization that they use for the ellipse reduces to the circle for $k = 0$ does imply that they can be simplified to elementary functions in this case, and to me this is analagous to the hyperbola becoming a rectangular hyperbola for $k^2 = 2$
          $endgroup$
          – Joe
          Dec 19 '14 at 21:38




          $begingroup$
          No most definitely not, but the fact that the same parametrization that they use for the ellipse reduces to the circle for $k = 0$ does imply that they can be simplified to elementary functions in this case, and to me this is analagous to the hyperbola becoming a rectangular hyperbola for $k^2 = 2$
          $endgroup$
          – Joe
          Dec 19 '14 at 21:38












          $begingroup$
          Well, to be honest I don't understand your argument at all. The fact that sn and cn reduce to trig functions for $k=0$ does not follow merely from the fact that they happen to parametrize the circle in that case, you need to look at their definitions. After all, they parametrize the circle for every $k$, but for $k neq 0$ (or $1$) they don't simplify.
          $endgroup$
          – Hans Lundmark
          Dec 19 '14 at 22:17





          $begingroup$
          Well, to be honest I don't understand your argument at all. The fact that sn and cn reduce to trig functions for $k=0$ does not follow merely from the fact that they happen to parametrize the circle in that case, you need to look at their definitions. After all, they parametrize the circle for every $k$, but for $k neq 0$ (or $1$) they don't simplify.
          $endgroup$
          – Hans Lundmark
          Dec 19 '14 at 22:17













          $begingroup$
          Ah, I think in previous comment, 'suggests' would have been a better word than 'implies', (although I think it might be an implication). I am defining the Jacobi Elliptic functions in terms of properties on the ellipse. I define the elliptic angular measure, $am(phi|k)$, which is like an extension of the radian to `elliptical angular units'. Then you take $sin$ and $cos$ (and the $dn$ function) of it to give the elliptic functions. Then as $k->0$ we recover the circle, and $am(phi|0) = phi$.
          $endgroup$
          – Joe
          Dec 20 '14 at 1:05





          $begingroup$
          Ah, I think in previous comment, 'suggests' would have been a better word than 'implies', (although I think it might be an implication). I am defining the Jacobi Elliptic functions in terms of properties on the ellipse. I define the elliptic angular measure, $am(phi|k)$, which is like an extension of the radian to `elliptical angular units'. Then you take $sin$ and $cos$ (and the $dn$ function) of it to give the elliptic functions. Then as $k->0$ we recover the circle, and $am(phi|0) = phi$.
          $endgroup$
          – Joe
          Dec 20 '14 at 1:05


















          draft saved

          draft discarded
















































          Thanks for contributing an answer to Mathematics Stack Exchange!


          • Please be sure to answer the question. Provide details and share your research!

          But avoid


          • Asking for help, clarification, or responding to other answers.

          • Making statements based on opinion; back them up with references or personal experience.

          Use MathJax to format equations. MathJax reference.


          To learn more, see our tips on writing great answers.




          draft saved


          draft discarded














          StackExchange.ready(
          function ()
          StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f1072098%2fjacobi-elliptic-functions-special-case%23new-answer', 'question_page');

          );

          Post as a guest















          Required, but never shown





















































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown

































          Required, but never shown














          Required, but never shown












          Required, but never shown







          Required, but never shown







          Popular posts from this blog

          Solar Wings Breeze Design and development Specifications (Breeze) References Navigation menu1368-485X"Hang glider: Breeze (Solar Wings)"e

          Kathakali Contents Etymology and nomenclature History Repertoire Songs and musical instruments Traditional plays Styles: Sampradayam Training centers and awards Relationship to other dance forms See also Notes References External links Navigation menueThe Illustrated Encyclopedia of Hinduism: A-MSouth Asian Folklore: An EncyclopediaRoutledge International Encyclopedia of Women: Global Women's Issues and KnowledgeKathakali Dance-drama: Where Gods and Demons Come to PlayKathakali Dance-drama: Where Gods and Demons Come to PlayKathakali Dance-drama: Where Gods and Demons Come to Play10.1353/atj.2005.0004The Illustrated Encyclopedia of Hinduism: A-MEncyclopedia of HinduismKathakali Dance-drama: Where Gods and Demons Come to PlaySonic Liturgy: Ritual and Music in Hindu Tradition"The Mirror of Gesture"Kathakali Dance-drama: Where Gods and Demons Come to Play"Kathakali"Indian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceMedieval Indian Literature: An AnthologyThe Oxford Companion to Indian TheatreSouth Asian Folklore: An Encyclopedia : Afghanistan, Bangladesh, India, Nepal, Pakistan, Sri LankaThe Rise of Performance Studies: Rethinking Richard Schechner's Broad SpectrumIndian Theatre: Traditions of PerformanceModern Asian Theatre and Performance 1900-2000Critical Theory and PerformanceBetween Theater and AnthropologyKathakali603847011Indian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceIndian Theatre: Traditions of PerformanceBetween Theater and AnthropologyBetween Theater and AnthropologyNambeesan Smaraka AwardsArchivedThe Cambridge Guide to TheatreRoutledge International Encyclopedia of Women: Global Women's Issues and KnowledgeThe Garland Encyclopedia of World Music: South Asia : the Indian subcontinentThe Ethos of Noh: Actors and Their Art10.2307/1145740By Means of Performance: Intercultural Studies of Theatre and Ritual10.1017/s204912550000100xReconceiving the Renaissance: A Critical ReaderPerformance TheoryListening to Theatre: The Aural Dimension of Beijing Opera10.2307/1146013Kathakali: The Art of the Non-WorldlyOn KathakaliKathakali, the dance theatreThe Kathakali Complex: Performance & StructureKathakali Dance-Drama: Where Gods and Demons Come to Play10.1093/obo/9780195399318-0071Drama and Ritual of Early Hinduism"In the Shadow of Hollywood Orientalism: Authentic East Indian Dancing"10.1080/08949460490274013Sanskrit Play Production in Ancient IndiaIndian Music: History and StructureBharata, the Nāṭyaśāstra233639306Table of Contents2238067286469807Dance In Indian Painting10.2307/32047833204783Kathakali Dance-Theatre: A Visual Narrative of Sacred Indian MimeIndian Classical Dance: The Renaissance and BeyondKathakali: an indigenous art-form of Keralaeee

          Method to test if a number is a perfect power? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)Detecting perfect squares faster than by extracting square rooteffective way to get the integer sequence A181392 from oeisA rarely mentioned fact about perfect powersHow many numbers such $n$ are there that $n<100,lfloorsqrtn rfloor mid n$Check perfect squareness by modulo division against multiple basesFor what pair of integers $(a,b)$ is $3^a + 7^b$ a perfect square.Do there exist any positive integers $n$ such that $lfloore^nrfloor$ is a perfect power? What is the probability that one exists?finding perfect power factors of an integerProve that the sequence contains a perfect square for any natural number $m $ in the domain of $f$ .Counting Perfect Powers