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What is this equation with zeta from a T-Shirt in a video?


Numerical Integration over 2D Regions with Discontinuous FunctionsHow to integrate $int_-1^1frac1a + bx dx$, where $a,bin mathbbC$ without using branch cuts.A rigorous meaning of “induced measure”?Probability density of constructed variableWhy does the boundary of a region $D$ have enough information to dictate the value of an integral over $D$?How do I prove the following equation involving $int_0^+inftyleft(fracsin(x)xright)^ndx$Are there parts of Integral Calculus that just *have* to be memorized?Cavalieri's, Mamikon's and Peano's methods for areas/volumes: how are they related?Calculate Integral using residue theoremWhat is the idea to integrate this equation from G&R?













3












$begingroup$


There's an equation on a T-shirt in the music video by Remy Zero for "Gramarye". There's not a completely clear shot of it, but it's something along the lines of:



$$?^???(z) = fracn !2 pi ? int_C fracf(zeta)(zeta - z)^n+1 dzeta ,$$



Can anyone fill in the blanks and identify what that is? Searched around a bit on line integrals and zeta functions and didn't find anything



Gramarye T-shirt










share|cite|improve this question









$endgroup$







  • 4




    $begingroup$
    en.wikipedia.org/wiki/Cauchy's_integral_formula
    $endgroup$
    – Brad
    Jul 22 '14 at 3:39










  • $begingroup$
    Cauchy's integral formula. Not Riemann zeta at all
    $endgroup$
    – Will Jagy
    Jul 22 '14 at 3:39











  • $begingroup$
    It's $f^(n)(z)$. See Cauchy's generalized integral formula. Now I really want that shirt.
    $endgroup$
    – Cameron Williams
    Jul 22 '14 at 3:39











  • $begingroup$
    That's not a zeta function. Zeta there is just a dummy variable.
    $endgroup$
    – mweiss
    Jul 22 '14 at 3:39















3












$begingroup$


There's an equation on a T-shirt in the music video by Remy Zero for "Gramarye". There's not a completely clear shot of it, but it's something along the lines of:



$$?^???(z) = fracn !2 pi ? int_C fracf(zeta)(zeta - z)^n+1 dzeta ,$$



Can anyone fill in the blanks and identify what that is? Searched around a bit on line integrals and zeta functions and didn't find anything



Gramarye T-shirt










share|cite|improve this question









$endgroup$







  • 4




    $begingroup$
    en.wikipedia.org/wiki/Cauchy's_integral_formula
    $endgroup$
    – Brad
    Jul 22 '14 at 3:39










  • $begingroup$
    Cauchy's integral formula. Not Riemann zeta at all
    $endgroup$
    – Will Jagy
    Jul 22 '14 at 3:39











  • $begingroup$
    It's $f^(n)(z)$. See Cauchy's generalized integral formula. Now I really want that shirt.
    $endgroup$
    – Cameron Williams
    Jul 22 '14 at 3:39











  • $begingroup$
    That's not a zeta function. Zeta there is just a dummy variable.
    $endgroup$
    – mweiss
    Jul 22 '14 at 3:39













3












3








3





$begingroup$


There's an equation on a T-shirt in the music video by Remy Zero for "Gramarye". There's not a completely clear shot of it, but it's something along the lines of:



$$?^???(z) = fracn !2 pi ? int_C fracf(zeta)(zeta - z)^n+1 dzeta ,$$



Can anyone fill in the blanks and identify what that is? Searched around a bit on line integrals and zeta functions and didn't find anything



Gramarye T-shirt










share|cite|improve this question









$endgroup$




There's an equation on a T-shirt in the music video by Remy Zero for "Gramarye". There's not a completely clear shot of it, but it's something along the lines of:



$$?^???(z) = fracn !2 pi ? int_C fracf(zeta)(zeta - z)^n+1 dzeta ,$$



Can anyone fill in the blanks and identify what that is? Searched around a bit on line integrals and zeta functions and didn't find anything



Gramarye T-shirt







integration






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Jul 22 '14 at 3:37









HostileForkHostileFork

1687




1687







  • 4




    $begingroup$
    en.wikipedia.org/wiki/Cauchy's_integral_formula
    $endgroup$
    – Brad
    Jul 22 '14 at 3:39










  • $begingroup$
    Cauchy's integral formula. Not Riemann zeta at all
    $endgroup$
    – Will Jagy
    Jul 22 '14 at 3:39











  • $begingroup$
    It's $f^(n)(z)$. See Cauchy's generalized integral formula. Now I really want that shirt.
    $endgroup$
    – Cameron Williams
    Jul 22 '14 at 3:39











  • $begingroup$
    That's not a zeta function. Zeta there is just a dummy variable.
    $endgroup$
    – mweiss
    Jul 22 '14 at 3:39












  • 4




    $begingroup$
    en.wikipedia.org/wiki/Cauchy's_integral_formula
    $endgroup$
    – Brad
    Jul 22 '14 at 3:39










  • $begingroup$
    Cauchy's integral formula. Not Riemann zeta at all
    $endgroup$
    – Will Jagy
    Jul 22 '14 at 3:39











  • $begingroup$
    It's $f^(n)(z)$. See Cauchy's generalized integral formula. Now I really want that shirt.
    $endgroup$
    – Cameron Williams
    Jul 22 '14 at 3:39











  • $begingroup$
    That's not a zeta function. Zeta there is just a dummy variable.
    $endgroup$
    – mweiss
    Jul 22 '14 at 3:39







4




4




$begingroup$
en.wikipedia.org/wiki/Cauchy's_integral_formula
$endgroup$
– Brad
Jul 22 '14 at 3:39




$begingroup$
en.wikipedia.org/wiki/Cauchy's_integral_formula
$endgroup$
– Brad
Jul 22 '14 at 3:39












$begingroup$
Cauchy's integral formula. Not Riemann zeta at all
$endgroup$
– Will Jagy
Jul 22 '14 at 3:39





$begingroup$
Cauchy's integral formula. Not Riemann zeta at all
$endgroup$
– Will Jagy
Jul 22 '14 at 3:39













$begingroup$
It's $f^(n)(z)$. See Cauchy's generalized integral formula. Now I really want that shirt.
$endgroup$
– Cameron Williams
Jul 22 '14 at 3:39





$begingroup$
It's $f^(n)(z)$. See Cauchy's generalized integral formula. Now I really want that shirt.
$endgroup$
– Cameron Williams
Jul 22 '14 at 3:39













$begingroup$
That's not a zeta function. Zeta there is just a dummy variable.
$endgroup$
– mweiss
Jul 22 '14 at 3:39




$begingroup$
That's not a zeta function. Zeta there is just a dummy variable.
$endgroup$
– mweiss
Jul 22 '14 at 3:39










1 Answer
1






active

oldest

votes


















3












$begingroup$

Turning comment into an answer.



That is Cauchy's integral formula. The full formula is given by



$$f^(n)(z) = fracn !2 pi i int_C! fracf(zeta)(zeta - z)^n+1 mathrmdzeta $$






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Is it so worthy to be on a t-shirt?
    $endgroup$
    – MonK
    Jul 22 '14 at 4:37










  • $begingroup$
    @Sid It doesn't take much to make it onto a shirt in the first place... so I'd imagine it's as good as anything. :-)
    $endgroup$
    – HostileFork
    Jul 22 '14 at 7:10










Your Answer





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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









3












$begingroup$

Turning comment into an answer.



That is Cauchy's integral formula. The full formula is given by



$$f^(n)(z) = fracn !2 pi i int_C! fracf(zeta)(zeta - z)^n+1 mathrmdzeta $$






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Is it so worthy to be on a t-shirt?
    $endgroup$
    – MonK
    Jul 22 '14 at 4:37










  • $begingroup$
    @Sid It doesn't take much to make it onto a shirt in the first place... so I'd imagine it's as good as anything. :-)
    $endgroup$
    – HostileFork
    Jul 22 '14 at 7:10















3












$begingroup$

Turning comment into an answer.



That is Cauchy's integral formula. The full formula is given by



$$f^(n)(z) = fracn !2 pi i int_C! fracf(zeta)(zeta - z)^n+1 mathrmdzeta $$






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Is it so worthy to be on a t-shirt?
    $endgroup$
    – MonK
    Jul 22 '14 at 4:37










  • $begingroup$
    @Sid It doesn't take much to make it onto a shirt in the first place... so I'd imagine it's as good as anything. :-)
    $endgroup$
    – HostileFork
    Jul 22 '14 at 7:10













3












3








3





$begingroup$

Turning comment into an answer.



That is Cauchy's integral formula. The full formula is given by



$$f^(n)(z) = fracn !2 pi i int_C! fracf(zeta)(zeta - z)^n+1 mathrmdzeta $$






share|cite|improve this answer









$endgroup$



Turning comment into an answer.



That is Cauchy's integral formula. The full formula is given by



$$f^(n)(z) = fracn !2 pi i int_C! fracf(zeta)(zeta - z)^n+1 mathrmdzeta $$







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Jul 22 '14 at 4:07









BradBrad

4,29021448




4,29021448











  • $begingroup$
    Is it so worthy to be on a t-shirt?
    $endgroup$
    – MonK
    Jul 22 '14 at 4:37










  • $begingroup$
    @Sid It doesn't take much to make it onto a shirt in the first place... so I'd imagine it's as good as anything. :-)
    $endgroup$
    – HostileFork
    Jul 22 '14 at 7:10
















  • $begingroup$
    Is it so worthy to be on a t-shirt?
    $endgroup$
    – MonK
    Jul 22 '14 at 4:37










  • $begingroup$
    @Sid It doesn't take much to make it onto a shirt in the first place... so I'd imagine it's as good as anything. :-)
    $endgroup$
    – HostileFork
    Jul 22 '14 at 7:10















$begingroup$
Is it so worthy to be on a t-shirt?
$endgroup$
– MonK
Jul 22 '14 at 4:37




$begingroup$
Is it so worthy to be on a t-shirt?
$endgroup$
– MonK
Jul 22 '14 at 4:37












$begingroup$
@Sid It doesn't take much to make it onto a shirt in the first place... so I'd imagine it's as good as anything. :-)
$endgroup$
– HostileFork
Jul 22 '14 at 7:10




$begingroup$
@Sid It doesn't take much to make it onto a shirt in the first place... so I'd imagine it's as good as anything. :-)
$endgroup$
– HostileFork
Jul 22 '14 at 7:10

















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