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Alternating series, $sum_n=1^infty n^2 a_n^2$ conv. $implies$ $sum_n=1^infty (-1)^n a_n$ conv.


Leibniz's alternating series testConvergence of an alternating series (from exam Q)If $sum|a_n|<infty$ and $sum |b_n|<infty$, is the sum $sum_k=0^infty sum_n=0^infty |a_n||b_n+k|<infty$?If $sum_n_0^infty a_n$ diverges prove that $sum_n_0^infty fraca_na_1+a_2+…+a_n = +infty $Do the following series converge if $a_n>0$ and $ sum_n=1^inftya_n$ diverges?$sum_n= 0^inftya_n$ converges, what other series must then also converge?Contradictions between the Alternating Series Test & Divergence Test?If $sum_n=0^infty a_n$ converges absolutely, so does $sum_n=0^infty fraca_n^22-a_n^2$Counterexample to Leibniz criterion for alternating seriesExample of series such that every $sum_i=1^infty b_n_i$ converges but $sum_n=1^infty |b_n|$ diverges













0












$begingroup$


Suppose that $ sum_n=1^infty n^2 a_n^2 $ converges. Does this imply $ sum_n=1^infty (-1)^n a_n $ converges?



I guess it converges, but I couldn't prove it.



I have tried writing $b_n = na_n$ but it seems that the alternating series test did not work.



Any help would be greatly appreciated.










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    Cauchy Schwarz$ $
    $endgroup$
    – reuns
    Mar 15 at 3:06
















0












$begingroup$


Suppose that $ sum_n=1^infty n^2 a_n^2 $ converges. Does this imply $ sum_n=1^infty (-1)^n a_n $ converges?



I guess it converges, but I couldn't prove it.



I have tried writing $b_n = na_n$ but it seems that the alternating series test did not work.



Any help would be greatly appreciated.










share|cite|improve this question









$endgroup$







  • 1




    $begingroup$
    Cauchy Schwarz$ $
    $endgroup$
    – reuns
    Mar 15 at 3:06














0












0








0





$begingroup$


Suppose that $ sum_n=1^infty n^2 a_n^2 $ converges. Does this imply $ sum_n=1^infty (-1)^n a_n $ converges?



I guess it converges, but I couldn't prove it.



I have tried writing $b_n = na_n$ but it seems that the alternating series test did not work.



Any help would be greatly appreciated.










share|cite|improve this question









$endgroup$




Suppose that $ sum_n=1^infty n^2 a_n^2 $ converges. Does this imply $ sum_n=1^infty (-1)^n a_n $ converges?



I guess it converges, but I couldn't prove it.



I have tried writing $b_n = na_n$ but it seems that the alternating series test did not work.



Any help would be greatly appreciated.







real-analysis sequences-and-series






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 15 at 2:59









FuroCharuFuroCharu

2715




2715







  • 1




    $begingroup$
    Cauchy Schwarz$ $
    $endgroup$
    – reuns
    Mar 15 at 3:06













  • 1




    $begingroup$
    Cauchy Schwarz$ $
    $endgroup$
    – reuns
    Mar 15 at 3:06








1




1




$begingroup$
Cauchy Schwarz$ $
$endgroup$
– reuns
Mar 15 at 3:06





$begingroup$
Cauchy Schwarz$ $
$endgroup$
– reuns
Mar 15 at 3:06











1 Answer
1






active

oldest

votes


















4












$begingroup$

Hint:
beginalign
left|sum_n=K^N (-1)^na_nright| leq left(sum^N_n=K frac1n^2right)^1/2 left(sum^N_n=K n^2a_n^2 right)^1/2
endalign






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Thanks, I feel so dumb now I forgot to try using cauchy schwarz.
    $endgroup$
    – FuroCharu
    Mar 15 at 3:09











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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









4












$begingroup$

Hint:
beginalign
left|sum_n=K^N (-1)^na_nright| leq left(sum^N_n=K frac1n^2right)^1/2 left(sum^N_n=K n^2a_n^2 right)^1/2
endalign






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Thanks, I feel so dumb now I forgot to try using cauchy schwarz.
    $endgroup$
    – FuroCharu
    Mar 15 at 3:09
















4












$begingroup$

Hint:
beginalign
left|sum_n=K^N (-1)^na_nright| leq left(sum^N_n=K frac1n^2right)^1/2 left(sum^N_n=K n^2a_n^2 right)^1/2
endalign






share|cite|improve this answer









$endgroup$












  • $begingroup$
    Thanks, I feel so dumb now I forgot to try using cauchy schwarz.
    $endgroup$
    – FuroCharu
    Mar 15 at 3:09














4












4








4





$begingroup$

Hint:
beginalign
left|sum_n=K^N (-1)^na_nright| leq left(sum^N_n=K frac1n^2right)^1/2 left(sum^N_n=K n^2a_n^2 right)^1/2
endalign






share|cite|improve this answer









$endgroup$



Hint:
beginalign
left|sum_n=K^N (-1)^na_nright| leq left(sum^N_n=K frac1n^2right)^1/2 left(sum^N_n=K n^2a_n^2 right)^1/2
endalign







share|cite|improve this answer












share|cite|improve this answer



share|cite|improve this answer










answered Mar 15 at 3:07









Jacky ChongJacky Chong

19.4k21129




19.4k21129











  • $begingroup$
    Thanks, I feel so dumb now I forgot to try using cauchy schwarz.
    $endgroup$
    – FuroCharu
    Mar 15 at 3:09

















  • $begingroup$
    Thanks, I feel so dumb now I forgot to try using cauchy schwarz.
    $endgroup$
    – FuroCharu
    Mar 15 at 3:09
















$begingroup$
Thanks, I feel so dumb now I forgot to try using cauchy schwarz.
$endgroup$
– FuroCharu
Mar 15 at 3:09





$begingroup$
Thanks, I feel so dumb now I forgot to try using cauchy schwarz.
$endgroup$
– FuroCharu
Mar 15 at 3:09


















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