let c be a k cube, prove that there exists no k+1 chain b such that $partial b = c$Proof and counter-example that a chain $c_R, n ne partial c$. Where is the error?Integrating differential form questionproperty of sum of coefs of a chainProblem from spivak's calculus singular cubessingular $1$ cube - Boundary of $2$ chainProof that exact form are path independent seems to imply the same for merely closed formsQuestion about Lee's Introduction to Smooth Manifolds (2 ed.) problem 18-1Show that $mathbbS^d$ is homeomorphic to the the boundary of the cube $partial I^d+1$.Trying to prove $partial^2=0$ on $k$-cellsQuestion on the proof of Stokes' Theorem in Spivak

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let c be a k cube, prove that there exists no k+1 chain b such that $partial b = c$


Proof and counter-example that a chain $c_R, n ne partial c$. Where is the error?Integrating differential form questionproperty of sum of coefs of a chainProblem from spivak's calculus singular cubessingular $1$ cube - Boundary of $2$ chainProof that exact form are path independent seems to imply the same for merely closed formsQuestion about Lee's Introduction to Smooth Manifolds (2 ed.) problem 18-1Show that $mathbbS^d$ is homeomorphic to the the boundary of the cube $partial I^d+1$.Trying to prove $partial^2=0$ on $k$-cellsQuestion on the proof of Stokes' Theorem in Spivak













1












$begingroup$


There is a former question says we can define the boundary of b as a certain linear combination of k-cubes, $partial b = sum_i a_i c_i$, prove $sum_i a_i = 0$, where $c_i$ are k-cubes, if I can show this, then it follows that $partial b$ cannot be a cube, but I have no idea how to show $sum_i a_i = 0$.
And I know the boundary of boundary is 0, so if $partial b = c$, then $partial c = 0$, which means $int_c da = int_partial c a = 0$ for any k-1 form a, and how can I make a contradiction from here. Thank you for any help.










share|cite|improve this question









$endgroup$











  • $begingroup$
    It would really help to give a link to this earlier question....
    $endgroup$
    – Lord Shark the Unknown
    Mar 15 at 4:58










  • $begingroup$
    @Lord Shark the Unknown Emm, the earlier question is also in the book Manifolds and Differential Forms together with this question and not on the website, sorry for my inaccurate expression
    $endgroup$
    – Ziqin He
    Mar 15 at 5:39















1












$begingroup$


There is a former question says we can define the boundary of b as a certain linear combination of k-cubes, $partial b = sum_i a_i c_i$, prove $sum_i a_i = 0$, where $c_i$ are k-cubes, if I can show this, then it follows that $partial b$ cannot be a cube, but I have no idea how to show $sum_i a_i = 0$.
And I know the boundary of boundary is 0, so if $partial b = c$, then $partial c = 0$, which means $int_c da = int_partial c a = 0$ for any k-1 form a, and how can I make a contradiction from here. Thank you for any help.










share|cite|improve this question









$endgroup$











  • $begingroup$
    It would really help to give a link to this earlier question....
    $endgroup$
    – Lord Shark the Unknown
    Mar 15 at 4:58










  • $begingroup$
    @Lord Shark the Unknown Emm, the earlier question is also in the book Manifolds and Differential Forms together with this question and not on the website, sorry for my inaccurate expression
    $endgroup$
    – Ziqin He
    Mar 15 at 5:39













1












1








1





$begingroup$


There is a former question says we can define the boundary of b as a certain linear combination of k-cubes, $partial b = sum_i a_i c_i$, prove $sum_i a_i = 0$, where $c_i$ are k-cubes, if I can show this, then it follows that $partial b$ cannot be a cube, but I have no idea how to show $sum_i a_i = 0$.
And I know the boundary of boundary is 0, so if $partial b = c$, then $partial c = 0$, which means $int_c da = int_partial c a = 0$ for any k-1 form a, and how can I make a contradiction from here. Thank you for any help.










share|cite|improve this question









$endgroup$




There is a former question says we can define the boundary of b as a certain linear combination of k-cubes, $partial b = sum_i a_i c_i$, prove $sum_i a_i = 0$, where $c_i$ are k-cubes, if I can show this, then it follows that $partial b$ cannot be a cube, but I have no idea how to show $sum_i a_i = 0$.
And I know the boundary of boundary is 0, so if $partial b = c$, then $partial c = 0$, which means $int_c da = int_partial c a = 0$ for any k-1 form a, and how can I make a contradiction from here. Thank you for any help.







multivariable-calculus differential-geometry






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 15 at 4:06









Ziqin HeZiqin He

232




232











  • $begingroup$
    It would really help to give a link to this earlier question....
    $endgroup$
    – Lord Shark the Unknown
    Mar 15 at 4:58










  • $begingroup$
    @Lord Shark the Unknown Emm, the earlier question is also in the book Manifolds and Differential Forms together with this question and not on the website, sorry for my inaccurate expression
    $endgroup$
    – Ziqin He
    Mar 15 at 5:39
















  • $begingroup$
    It would really help to give a link to this earlier question....
    $endgroup$
    – Lord Shark the Unknown
    Mar 15 at 4:58










  • $begingroup$
    @Lord Shark the Unknown Emm, the earlier question is also in the book Manifolds and Differential Forms together with this question and not on the website, sorry for my inaccurate expression
    $endgroup$
    – Ziqin He
    Mar 15 at 5:39















$begingroup$
It would really help to give a link to this earlier question....
$endgroup$
– Lord Shark the Unknown
Mar 15 at 4:58




$begingroup$
It would really help to give a link to this earlier question....
$endgroup$
– Lord Shark the Unknown
Mar 15 at 4:58












$begingroup$
@Lord Shark the Unknown Emm, the earlier question is also in the book Manifolds and Differential Forms together with this question and not on the website, sorry for my inaccurate expression
$endgroup$
– Ziqin He
Mar 15 at 5:39




$begingroup$
@Lord Shark the Unknown Emm, the earlier question is also in the book Manifolds and Differential Forms together with this question and not on the website, sorry for my inaccurate expression
$endgroup$
– Ziqin He
Mar 15 at 5:39










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