Name for a poset where incomparability is an equivalence relation The Next CEO of Stack OverflowQuestion about posets and maxima/minimaEquivalence relation and partitions.equivalence relation partitioning for the set $[0,1]$Proving the relation is an equivalence relation.Showing that ~ is an equivalence relationAre equivalence relations total, i.e. are all elements of an equivalence relation related one to each other?Is Love $subseteq$ Person $times$ Person an equivalence relation, partial order or total order?Partially Ordered Set and Equivalence Relationship~$_P$ is an equivalence relation in A.Is there any work on partition a partial order set into minimum number total order subsets?

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Name for a poset where incomparability is an equivalence relation



The Next CEO of Stack OverflowQuestion about posets and maxima/minimaEquivalence relation and partitions.equivalence relation partitioning for the set $[0,1]$Proving the relation is an equivalence relation.Showing that ~ is an equivalence relationAre equivalence relations total, i.e. are all elements of an equivalence relation related one to each other?Is Love $subseteq$ Person $times$ Person an equivalence relation, partial order or total order?Partially Ordered Set and Equivalence Relationship~$_P$ is an equivalence relation in A.Is there any work on partition a partial order set into minimum number total order subsets?










0












$begingroup$


Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.



Is there a name for the following restriction on the partial order?




$sim$ is an equivalence relation.




If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.










share|cite|improve this question









$endgroup$







  • 2




    $begingroup$
    Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
    $endgroup$
    – Thomas Andrews
    Mar 18 at 19:42







  • 1




    $begingroup$
    Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
    $endgroup$
    – Ittay Weiss
    Mar 18 at 19:54










  • $begingroup$
    Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
    $endgroup$
    – usul
    Mar 18 at 21:29















0












$begingroup$


Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.



Is there a name for the following restriction on the partial order?




$sim$ is an equivalence relation.




If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.










share|cite|improve this question









$endgroup$







  • 2




    $begingroup$
    Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
    $endgroup$
    – Thomas Andrews
    Mar 18 at 19:42







  • 1




    $begingroup$
    Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
    $endgroup$
    – Ittay Weiss
    Mar 18 at 19:54










  • $begingroup$
    Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
    $endgroup$
    – usul
    Mar 18 at 21:29













0












0








0





$begingroup$


Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.



Is there a name for the following restriction on the partial order?




$sim$ is an equivalence relation.




If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.










share|cite|improve this question









$endgroup$




Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.



Is there a name for the following restriction on the partial order?




$sim$ is an equivalence relation.




If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.







order-theory equivalence-relations






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 18 at 19:38









usulusul

1,7101422




1,7101422







  • 2




    $begingroup$
    Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
    $endgroup$
    – Thomas Andrews
    Mar 18 at 19:42







  • 1




    $begingroup$
    Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
    $endgroup$
    – Ittay Weiss
    Mar 18 at 19:54










  • $begingroup$
    Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
    $endgroup$
    – usul
    Mar 18 at 21:29












  • 2




    $begingroup$
    Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
    $endgroup$
    – Thomas Andrews
    Mar 18 at 19:42







  • 1




    $begingroup$
    Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
    $endgroup$
    – Ittay Weiss
    Mar 18 at 19:54










  • $begingroup$
    Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
    $endgroup$
    – usul
    Mar 18 at 21:29







2




2




$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42





$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42





1




1




$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54




$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54












$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29




$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29










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