Name for a poset where incomparability is an equivalence relation The Next CEO of Stack OverflowQuestion about posets and maxima/minimaEquivalence relation and partitions.equivalence relation partitioning for the set $[0,1]$Proving the relation is an equivalence relation.Showing that ~ is an equivalence relationAre equivalence relations total, i.e. are all elements of an equivalence relation related one to each other?Is Love $subseteq$ Person $times$ Person an equivalence relation, partial order or total order?Partially Ordered Set and Equivalence Relationship~$_P$ is an equivalence relation in A.Is there any work on partition a partial order set into minimum number total order subsets?
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Name for a poset where incomparability is an equivalence relation
The Next CEO of Stack OverflowQuestion about posets and maxima/minimaEquivalence relation and partitions.equivalence relation partitioning for the set $[0,1]$Proving the relation is an equivalence relation.Showing that ~ is an equivalence relationAre equivalence relations total, i.e. are all elements of an equivalence relation related one to each other?Is Love $subseteq$ Person $times$ Person an equivalence relation, partial order or total order?Partially Ordered Set and Equivalence Relationship~$_P$ is an equivalence relation in A.Is there any work on partition a partial order set into minimum number total order subsets?
$begingroup$
Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.
Is there a name for the following restriction on the partial order?
$sim$ is an equivalence relation.
If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.
order-theory equivalence-relations
$endgroup$
add a comment |
$begingroup$
Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.
Is there a name for the following restriction on the partial order?
$sim$ is an equivalence relation.
If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.
order-theory equivalence-relations
$endgroup$
2
$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42
1
$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54
$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29
add a comment |
$begingroup$
Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.
Is there a name for the following restriction on the partial order?
$sim$ is an equivalence relation.
If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.
order-theory equivalence-relations
$endgroup$
Say I have a partial order $leq$ on a set $S$. Let me write $a sim b$ if $a$ and $b$ are incomparable under this order.
Is there a name for the following restriction on the partial order?
$sim$ is an equivalence relation.
If this holds, then we can use the equivalence relation to partition $S$ into totally ordered subsets where $S_i preceq S_j$ if and only if $a leq b$ and $b notleq a$ for all $a in S_i$ and $b in S_j$. Each each $S_i$ contains only elements that are not comparable under the original partial order. So it seems like a nice property.
order-theory equivalence-relations
order-theory equivalence-relations
asked Mar 18 at 19:38
usulusul
1,7101422
1,7101422
2
$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42
1
$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54
$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29
add a comment |
2
$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42
1
$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54
$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29
2
2
$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42
$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42
1
1
$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54
$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54
$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29
$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29
add a comment |
0
active
oldest
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$begingroup$
Since $anotsim a,$ it ($sim$) cannot be an equivalence relation, unless the poset is empty.
$endgroup$
– Thomas Andrews
Mar 18 at 19:42
1
$begingroup$
Even after correcting for Thomas' comment, the notion you'll get will just be equivalent to the poset being a disjoint union of linear orders. Such posets are not terribly interesting and so do not warrant a name. Certainly, most posets in nature are not of that type.
$endgroup$
– Ittay Weiss
Mar 18 at 19:54
$begingroup$
Yes, I forgot the condition "or a=b". @IttayWeiss, if you can convert that comment into an answer, I can accept it.
$endgroup$
– usul
Mar 18 at 21:29