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Probability game of black and white
The Next CEO of Stack OverflowCalculate wining probability in a dart gameRound robin probability questionConditional Probability and Independence - Find the probability that player 1 wins the game.Ideal Card GameProbability of first player winning in an urn game?Strategy for Coin Toss Team Game with EliminationOptimal strategy: Two Player Gambling Die GameProbability of a random game tournamentcard war game probabilityDice game - how do find the expected number of rounds?
$begingroup$
There are 10 doors and behind each one is a black or white image. We don't know how many black or white images there are in total.
The game is played by a number of players (less than 10) and each time one player guesses correctly they move to the next round. If noone guesses correctly the round is repeated. Once all doors are opened, they are closed again and shuffled (but a different number of white and black can occur).
In the final round, the two remaining players have to play until one of them reaches 5 correct guesses.
If what I wrote doesn't make sense you can take a look at the game here: https://www.youtube.com/watch?v=uzrFIUNufIc.
My question is, is there a mathematical way to approach this? Any way to make an educated and not completely random guess?
probability
asked Mar 18 at 21:36
SystemSystem
12118
$endgroup$
add a comment |
$begingroup$
There are 10 doors and behind each one is a black or white image. We don't know how many black or white images there are in total.
The game is played by a number of players (less than 10) and each time one player guesses correctly they move to the next round. If noone guesses correctly the round is repeated. Once all doors are opened, they are closed again and shuffled (but a different number of white and black can occur).
In the final round, the two remaining players have to play until one of them reaches 5 correct guesses.
If what I wrote doesn't make sense you can take a look at the game here: https://www.youtube.com/watch?v=uzrFIUNufIc.
My question is, is there a mathematical way to approach this? Any way to make an educated and not completely random guess?
probability
asked Mar 18 at 21:36
SystemSystem
12118
$endgroup$
2
$begingroup$
What a boring game to watch! Your probability of winning is the same no matter how you guess.
$endgroup$
– Mike Earnest
Mar 18 at 21:43
2
$begingroup$
State as you have it, the game is completely and uniformly random, and any pick is as good as any other pick.However, assuming that players are eliminated when a round ends if any other players has moved to the next round, there is no guarantee that the last round will have exactly 2 remaining players.
$endgroup$
– Mark Fischler
Mar 18 at 21:43
$begingroup$
@MarkFischler true. If it's 3 players, the first one to win moves to the final and the other two battle it out until one of them guesses correctly and the other does not.
$endgroup$
– System
Mar 19 at 23:18
$begingroup$
@MikeEarnest I agree. I couldn't believe they chose this game in Survivor to give away a motorbike and a car... This is why I was asking. To see if someone can think of a way to "cheat"/make it more interesting to watch...
$endgroup$
– System
Mar 19 at 23:19
add a comment |
$begingroup$
There are 10 doors and behind each one is a black or white image. We don't know how many black or white images there are in total.
The game is played by a number of players (less than 10) and each time one player guesses correctly they move to the next round. If noone guesses correctly the round is repeated. Once all doors are opened, they are closed again and shuffled (but a different number of white and black can occur).
In the final round, the two remaining players have to play until one of them reaches 5 correct guesses.
If what I wrote doesn't make sense you can take a look at the game here: https://www.youtube.com/watch?v=uzrFIUNufIc.
My question is, is there a mathematical way to approach this? Any way to make an educated and not completely random guess?
probability
asked Mar 18 at 21:36
SystemSystem
12118
$endgroup$
There are 10 doors and behind each one is a black or white image. We don't know how many black or white images there are in total.
The game is played by a number of players (less than 10) and each time one player guesses correctly they move to the next round. If noone guesses correctly the round is repeated. Once all doors are opened, they are closed again and shuffled (but a different number of white and black can occur).
In the final round, the two remaining players have to play until one of them reaches 5 correct guesses.
If what I wrote doesn't make sense you can take a look at the game here: https://www.youtube.com/watch?v=uzrFIUNufIc.
My question is, is there a mathematical way to approach this? Any way to make an educated and not completely random guess?
probability
probability
asked Mar 18 at 21:36
SystemSystem
12118
asked Mar 18 at 21:36
SystemSystem
12118
asked Mar 18 at 21:36
SystemSystem
12118
asked Mar 18 at 21:36
SystemSystem
12118
asked Mar 18 at 21:36
SystemSystem
12118
12118
2
$begingroup$
What a boring game to watch! Your probability of winning is the same no matter how you guess.
$endgroup$
– Mike Earnest
Mar 18 at 21:43
2
$begingroup$
State as you have it, the game is completely and uniformly random, and any pick is as good as any other pick.However, assuming that players are eliminated when a round ends if any other players has moved to the next round, there is no guarantee that the last round will have exactly 2 remaining players.
$endgroup$
– Mark Fischler
Mar 18 at 21:43
$begingroup$
@MarkFischler true. If it's 3 players, the first one to win moves to the final and the other two battle it out until one of them guesses correctly and the other does not.
$endgroup$
– System
Mar 19 at 23:18
$begingroup$
@MikeEarnest I agree. I couldn't believe they chose this game in Survivor to give away a motorbike and a car... This is why I was asking. To see if someone can think of a way to "cheat"/make it more interesting to watch...
$endgroup$
– System
Mar 19 at 23:19
add a comment |
2
$begingroup$
What a boring game to watch! Your probability of winning is the same no matter how you guess.
$endgroup$
– Mike Earnest
Mar 18 at 21:43
2
$begingroup$
State as you have it, the game is completely and uniformly random, and any pick is as good as any other pick.However, assuming that players are eliminated when a round ends if any other players has moved to the next round, there is no guarantee that the last round will have exactly 2 remaining players.
$endgroup$
– Mark Fischler
Mar 18 at 21:43
$begingroup$
@MarkFischler true. If it's 3 players, the first one to win moves to the final and the other two battle it out until one of them guesses correctly and the other does not.
$endgroup$
– System
Mar 19 at 23:18
$begingroup$
@MikeEarnest I agree. I couldn't believe they chose this game in Survivor to give away a motorbike and a car... This is why I was asking. To see if someone can think of a way to "cheat"/make it more interesting to watch...
$endgroup$
– System
Mar 19 at 23:19
2
2
$begingroup$
What a boring game to watch! Your probability of winning is the same no matter how you guess.
$endgroup$
– Mike Earnest
Mar 18 at 21:43
$begingroup$
What a boring game to watch! Your probability of winning is the same no matter how you guess.
$endgroup$
– Mike Earnest
Mar 18 at 21:43
2
2
$begingroup$
State as you have it, the game is completely and uniformly random, and any pick is as good as any other pick.However, assuming that players are eliminated when a round ends if any other players has moved to the next round, there is no guarantee that the last round will have exactly 2 remaining players.
$endgroup$
– Mark Fischler
Mar 18 at 21:43
$begingroup$
State as you have it, the game is completely and uniformly random, and any pick is as good as any other pick.However, assuming that players are eliminated when a round ends if any other players has moved to the next round, there is no guarantee that the last round will have exactly 2 remaining players.
$endgroup$
– Mark Fischler
Mar 18 at 21:43
$begingroup$
@MarkFischler true. If it's 3 players, the first one to win moves to the final and the other two battle it out until one of them guesses correctly and the other does not.
$endgroup$
– System
Mar 19 at 23:18
$begingroup$
@MarkFischler true. If it's 3 players, the first one to win moves to the final and the other two battle it out until one of them guesses correctly and the other does not.
$endgroup$
– System
Mar 19 at 23:18
$begingroup$
@MikeEarnest I agree. I couldn't believe they chose this game in Survivor to give away a motorbike and a car... This is why I was asking. To see if someone can think of a way to "cheat"/make it more interesting to watch...
$endgroup$
– System
Mar 19 at 23:19
$begingroup$
@MikeEarnest I agree. I couldn't believe they chose this game in Survivor to give away a motorbike and a car... This is why I was asking. To see if someone can think of a way to "cheat"/make it more interesting to watch...
$endgroup$
– System
Mar 19 at 23:19
add a comment |
0
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2
$begingroup$
What a boring game to watch! Your probability of winning is the same no matter how you guess.
$endgroup$
– Mike Earnest
Mar 18 at 21:43
2
$begingroup$
State as you have it, the game is completely and uniformly random, and any pick is as good as any other pick.However, assuming that players are eliminated when a round ends if any other players has moved to the next round, there is no guarantee that the last round will have exactly 2 remaining players.
$endgroup$
– Mark Fischler
Mar 18 at 21:43
$begingroup$
@MarkFischler true. If it's 3 players, the first one to win moves to the final and the other two battle it out until one of them guesses correctly and the other does not.
$endgroup$
– System
Mar 19 at 23:18
$begingroup$
@MikeEarnest I agree. I couldn't believe they chose this game in Survivor to give away a motorbike and a car... This is why I was asking. To see if someone can think of a way to "cheat"/make it more interesting to watch...
$endgroup$
– System
Mar 19 at 23:19