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Let $X sim operatornameGeo(p)$, find the probability mass function of $Y = X + 2$.
The Next CEO of Stack OverflowBernoulli distribution vs the probability mass functionfinding probability mass functionProbability, Mass FunctionLegitimate Probability Mass functionConditional probability mass function of flipping a fair coin.Find the probability mass function of a poisson distributionHow do I prove the probability mass function of the binomial distribution has only one peak?Find probability mass function and conditional expectationUnion of Two Geometric Random VariablesProbability distribution vs. probability mass function / Probability density function terms: what's the difference
$begingroup$
Let $X sim operatornameGeo(p)$, find the probability mass function of $Y = X + 2$.
I did the following but I don't know if its correct.
Since X follows the geometric distribution we have that $mathbbP(X=n)=p(1-p)^n-1$.
Therefore, $mathbbP(Y=n) = mathbbP(X+2=n)=mathbbP(X=n-2)=p(1-p)^n-3$.
probability-theory
edited Mar 18 at 22:36
Bernard
123k741117
asked Mar 18 at 22:13
Jasper Jasper
607
$endgroup$
add a comment |
$begingroup$
Let $X sim operatornameGeo(p)$, find the probability mass function of $Y = X + 2$.
I did the following but I don't know if its correct.
Since X follows the geometric distribution we have that $mathbbP(X=n)=p(1-p)^n-1$.
Therefore, $mathbbP(Y=n) = mathbbP(X+2=n)=mathbbP(X=n-2)=p(1-p)^n-3$.
probability-theory
edited Mar 18 at 22:36
Bernard
123k741117
asked Mar 18 at 22:13
Jasper Jasper
607
$endgroup$
$begingroup$
Looks good, probably best to specify the range of $n$ too (for $Y$).
$endgroup$
– Minus One-Twelfth
Mar 18 at 22:18
add a comment |
$begingroup$
Let $X sim operatornameGeo(p)$, find the probability mass function of $Y = X + 2$.
I did the following but I don't know if its correct.
Since X follows the geometric distribution we have that $mathbbP(X=n)=p(1-p)^n-1$.
Therefore, $mathbbP(Y=n) = mathbbP(X+2=n)=mathbbP(X=n-2)=p(1-p)^n-3$.
probability-theory
edited Mar 18 at 22:36
Bernard
123k741117
asked Mar 18 at 22:13
Jasper Jasper
607
$endgroup$
Let $X sim operatornameGeo(p)$, find the probability mass function of $Y = X + 2$.
I did the following but I don't know if its correct.
Since X follows the geometric distribution we have that $mathbbP(X=n)=p(1-p)^n-1$.
Therefore, $mathbbP(Y=n) = mathbbP(X+2=n)=mathbbP(X=n-2)=p(1-p)^n-3$.
probability-theory
probability-theory
edited Mar 18 at 22:36
Bernard
123k741117
asked Mar 18 at 22:13
Jasper Jasper
607
edited Mar 18 at 22:36
Bernard
123k741117
asked Mar 18 at 22:13
Jasper Jasper
607
edited Mar 18 at 22:36
Bernard
123k741117
edited Mar 18 at 22:36
Bernard
123k741117
edited Mar 18 at 22:36
Bernard
123k741117
123k741117
asked Mar 18 at 22:13
Jasper Jasper
607
asked Mar 18 at 22:13
Jasper Jasper
607
asked Mar 18 at 22:13
Jasper Jasper
607
607
$begingroup$
Looks good, probably best to specify the range of $n$ too (for $Y$).
$endgroup$
– Minus One-Twelfth
Mar 18 at 22:18
add a comment |
$begingroup$
Looks good, probably best to specify the range of $n$ too (for $Y$).
$endgroup$
– Minus One-Twelfth
Mar 18 at 22:18
$begingroup$
Looks good, probably best to specify the range of $n$ too (for $Y$).
$endgroup$
– Minus One-Twelfth
Mar 18 at 22:18
$begingroup$
Looks good, probably best to specify the range of $n$ too (for $Y$).
$endgroup$
– Minus One-Twelfth
Mar 18 at 22:18
add a comment |
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$begingroup$
Looks good, probably best to specify the range of $n$ too (for $Y$).
$endgroup$
– Minus One-Twelfth
Mar 18 at 22:18