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Sphere immersions in 4-manifolds



The Next CEO of Stack OverflowFramed manifolds and framed knotsCellular Homology of the 3-TorusIf a smooth map between manifolds is injective, is the induced map on the tangent spaces injective too?Some questions about homology with local coefficients.smooth embedding between manifoldsFundamental group of the sphere with n-points identifiedConfusion with immersions, embeddings, local homeomorphisms, and local diffeomorphisms.Fundamental group of common Klein bottle immersionDoes any isomorphism between $pi_1(X,x_0)$ and $pi_1(Y,y_0)$ always induce a homeomorphism between $(X,x_0)$ and $(Y,y_0)$?I'm having trouble understanding manifolds.










0












$begingroup$


I'm having trouble understanding the homomorphisms $pi_1g(S^2)longrightarrow pi_1 M^4$ where $g: S^2longrightarrow M^4$ can be a framed or unframed immersion.



Any reference on this?










share|cite|improve this question









$endgroup$











  • $begingroup$
    You typically learn this in an algebraic topology class/textbook: A continuous map of pointed topological spaces $(X,x)to (Y,y)$ induces a homomorphism $pi_1(X,x)to pi_1(Y,y)$. The extra assumptions ($g$ is an immersion etc) are irrelevant here. In your case, $X=S^2$ is simply-connected, hence, your homomorphism is trivial. My suggestion is to read Chapter 1.1 of Hatcher's "Algebraic Topology".
    $endgroup$
    – Moishe Kohan
    Mar 20 at 17:51










  • $begingroup$
    No, my homomorphism is $pi_1g(S^2)rightlongarrowpi_1M. The immersed sphere would have finitely many self intersections.@MoisheKohan
    $endgroup$
    – sarah
    Mar 21 at 3:07
















0












$begingroup$


I'm having trouble understanding the homomorphisms $pi_1g(S^2)longrightarrow pi_1 M^4$ where $g: S^2longrightarrow M^4$ can be a framed or unframed immersion.



Any reference on this?










share|cite|improve this question









$endgroup$











  • $begingroup$
    You typically learn this in an algebraic topology class/textbook: A continuous map of pointed topological spaces $(X,x)to (Y,y)$ induces a homomorphism $pi_1(X,x)to pi_1(Y,y)$. The extra assumptions ($g$ is an immersion etc) are irrelevant here. In your case, $X=S^2$ is simply-connected, hence, your homomorphism is trivial. My suggestion is to read Chapter 1.1 of Hatcher's "Algebraic Topology".
    $endgroup$
    – Moishe Kohan
    Mar 20 at 17:51










  • $begingroup$
    No, my homomorphism is $pi_1g(S^2)rightlongarrowpi_1M. The immersed sphere would have finitely many self intersections.@MoisheKohan
    $endgroup$
    – sarah
    Mar 21 at 3:07














0












0








0





$begingroup$


I'm having trouble understanding the homomorphisms $pi_1g(S^2)longrightarrow pi_1 M^4$ where $g: S^2longrightarrow M^4$ can be a framed or unframed immersion.



Any reference on this?










share|cite|improve this question









$endgroup$




I'm having trouble understanding the homomorphisms $pi_1g(S^2)longrightarrow pi_1 M^4$ where $g: S^2longrightarrow M^4$ can be a framed or unframed immersion.



Any reference on this?







algebraic-topology manifolds spheres






share|cite|improve this question













share|cite|improve this question











share|cite|improve this question




share|cite|improve this question










asked Mar 18 at 20:39









sarahsarah

1




1











  • $begingroup$
    You typically learn this in an algebraic topology class/textbook: A continuous map of pointed topological spaces $(X,x)to (Y,y)$ induces a homomorphism $pi_1(X,x)to pi_1(Y,y)$. The extra assumptions ($g$ is an immersion etc) are irrelevant here. In your case, $X=S^2$ is simply-connected, hence, your homomorphism is trivial. My suggestion is to read Chapter 1.1 of Hatcher's "Algebraic Topology".
    $endgroup$
    – Moishe Kohan
    Mar 20 at 17:51










  • $begingroup$
    No, my homomorphism is $pi_1g(S^2)rightlongarrowpi_1M. The immersed sphere would have finitely many self intersections.@MoisheKohan
    $endgroup$
    – sarah
    Mar 21 at 3:07

















  • $begingroup$
    You typically learn this in an algebraic topology class/textbook: A continuous map of pointed topological spaces $(X,x)to (Y,y)$ induces a homomorphism $pi_1(X,x)to pi_1(Y,y)$. The extra assumptions ($g$ is an immersion etc) are irrelevant here. In your case, $X=S^2$ is simply-connected, hence, your homomorphism is trivial. My suggestion is to read Chapter 1.1 of Hatcher's "Algebraic Topology".
    $endgroup$
    – Moishe Kohan
    Mar 20 at 17:51










  • $begingroup$
    No, my homomorphism is $pi_1g(S^2)rightlongarrowpi_1M. The immersed sphere would have finitely many self intersections.@MoisheKohan
    $endgroup$
    – sarah
    Mar 21 at 3:07
















$begingroup$
You typically learn this in an algebraic topology class/textbook: A continuous map of pointed topological spaces $(X,x)to (Y,y)$ induces a homomorphism $pi_1(X,x)to pi_1(Y,y)$. The extra assumptions ($g$ is an immersion etc) are irrelevant here. In your case, $X=S^2$ is simply-connected, hence, your homomorphism is trivial. My suggestion is to read Chapter 1.1 of Hatcher's "Algebraic Topology".
$endgroup$
– Moishe Kohan
Mar 20 at 17:51




$begingroup$
You typically learn this in an algebraic topology class/textbook: A continuous map of pointed topological spaces $(X,x)to (Y,y)$ induces a homomorphism $pi_1(X,x)to pi_1(Y,y)$. The extra assumptions ($g$ is an immersion etc) are irrelevant here. In your case, $X=S^2$ is simply-connected, hence, your homomorphism is trivial. My suggestion is to read Chapter 1.1 of Hatcher's "Algebraic Topology".
$endgroup$
– Moishe Kohan
Mar 20 at 17:51












$begingroup$
No, my homomorphism is $pi_1g(S^2)rightlongarrowpi_1M. The immersed sphere would have finitely many self intersections.@MoisheKohan
$endgroup$
– sarah
Mar 21 at 3:07





$begingroup$
No, my homomorphism is $pi_1g(S^2)rightlongarrowpi_1M. The immersed sphere would have finitely many self intersections.@MoisheKohan
$endgroup$
– sarah
Mar 21 at 3:07











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