Arrangement of people in a line Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Arrangement of six triangles in a hexagonGiven 5 children and 8 adults, how many ways can they be seated so that there are no two children sitting next to each other.Doubt on married couple seating arrangement problemHow many ways are there for 10 women and six men to stand in a linecounting McGraw HillSeating 10 people in a circular tablecircular arrangement vs. linear arrangement of people at a tableHow many different ways are there for eight men and five women to stand in a line so that no two women stand next to each other?In how many ways can the people line up if the first woman appears ahead of the first child?Ways to arrange $ngeq2$ people around a circular table, given two permanent seats.

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Arrangement of people in a line



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Arrangement of six triangles in a hexagonGiven 5 children and 8 adults, how many ways can they be seated so that there are no two children sitting next to each other.Doubt on married couple seating arrangement problemHow many ways are there for 10 women and six men to stand in a linecounting McGraw HillSeating 10 people in a circular tablecircular arrangement vs. linear arrangement of people at a tableHow many different ways are there for eight men and five women to stand in a line so that no two women stand next to each other?In how many ways can the people line up if the first woman appears ahead of the first child?Ways to arrange $ngeq2$ people around a circular table, given two permanent seats.










1












$begingroup$


Question:
6 men and 3 women stand in a line. How many possible arrangements are there if no two of the women are standing next to each other?



My attempted solution:



Arrange the 6 men first in 6! Ways. Then arrange the 3 women in the 7 spaces in-between the men ( 7 P 3 ) so final answer is : 151,200










share|cite|improve this question











$endgroup$











  • $begingroup$
    Your solution is correct.
    $endgroup$
    – John Douma
    Mar 27 at 2:50















1












$begingroup$


Question:
6 men and 3 women stand in a line. How many possible arrangements are there if no two of the women are standing next to each other?



My attempted solution:



Arrange the 6 men first in 6! Ways. Then arrange the 3 women in the 7 spaces in-between the men ( 7 P 3 ) so final answer is : 151,200










share|cite|improve this question











$endgroup$











  • $begingroup$
    Your solution is correct.
    $endgroup$
    – John Douma
    Mar 27 at 2:50













1












1








1





$begingroup$


Question:
6 men and 3 women stand in a line. How many possible arrangements are there if no two of the women are standing next to each other?



My attempted solution:



Arrange the 6 men first in 6! Ways. Then arrange the 3 women in the 7 spaces in-between the men ( 7 P 3 ) so final answer is : 151,200










share|cite|improve this question











$endgroup$




Question:
6 men and 3 women stand in a line. How many possible arrangements are there if no two of the women are standing next to each other?



My attempted solution:



Arrange the 6 men first in 6! Ways. Then arrange the 3 women in the 7 spaces in-between the men ( 7 P 3 ) so final answer is : 151,200







combinatorics permutations






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 27 at 9:18









N. F. Taussig

45.4k103358




45.4k103358










asked Mar 27 at 2:32









user122343user122343

1076




1076











  • $begingroup$
    Your solution is correct.
    $endgroup$
    – John Douma
    Mar 27 at 2:50
















  • $begingroup$
    Your solution is correct.
    $endgroup$
    – John Douma
    Mar 27 at 2:50















$begingroup$
Your solution is correct.
$endgroup$
– John Douma
Mar 27 at 2:50




$begingroup$
Your solution is correct.
$endgroup$
– John Douma
Mar 27 at 2:50










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