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First index is not integer using foreach loop from 0



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Rotate a node but not its content: the case of the ellipse decorationHow to define the default vertical distance between nodes?Numerical conditional within tikz keys?Why do I get an extra white page before my TikZ picture?Input/Output Nodes - Specification and Description LanguageTikZ: Drawing an arc from an intersection to an intersectionHow to prevent rounded and duplicated tick labels in pgfplots with fixed precision?Drawing rectilinear curves in Tikz, aka an Etch-a-Sketch drawingHow to draw a square and its diagonals with arrows?Compound Pathway Problem with holes










7















I am trying to draw a tree using tikzpicture like this:



documentclassarticle
usepackagetikz
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = 1 - floor(nnodes / 2) - 1;
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[node] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



enter image description here










share|improve this question



















  • 1





    Welcome to TeX.SX. When you post a question, please provide a "Minimal Working Example" (MWE) that starts with documentclass, includes all relevant usepackage commands, ends with enddocument and compiles without errors, even if it does not produce your desired output.

    – Sandy G
    Mar 27 at 14:32















7















I am trying to draw a tree using tikzpicture like this:



documentclassarticle
usepackagetikz
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = 1 - floor(nnodes / 2) - 1;
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[node] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



enter image description here










share|improve this question



















  • 1





    Welcome to TeX.SX. When you post a question, please provide a "Minimal Working Example" (MWE) that starts with documentclass, includes all relevant usepackage commands, ends with enddocument and compiles without errors, even if it does not produce your desired output.

    – Sandy G
    Mar 27 at 14:32













7












7








7


1






I am trying to draw a tree using tikzpicture like this:



documentclassarticle
usepackagetikz
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = 1 - floor(nnodes / 2) - 1;
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[node] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



enter image description here










share|improve this question
















I am trying to draw a tree using tikzpicture like this:



documentclassarticle
usepackagetikz
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = 1 - floor(nnodes / 2) - 1;
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[node] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


I get the tree like the following picture. The texts are nodes' isibling within each layer. Most nodes are integers, but all leftmost nodes are not.



enter image description here







tikz-pgf foreach






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 28 at 4:47







landings

















asked Mar 27 at 4:10









landingslandings

414




414







  • 1





    Welcome to TeX.SX. When you post a question, please provide a "Minimal Working Example" (MWE) that starts with documentclass, includes all relevant usepackage commands, ends with enddocument and compiles without errors, even if it does not produce your desired output.

    – Sandy G
    Mar 27 at 14:32












  • 1





    Welcome to TeX.SX. When you post a question, please provide a "Minimal Working Example" (MWE) that starts with documentclass, includes all relevant usepackage commands, ends with enddocument and compiles without errors, even if it does not produce your desired output.

    – Sandy G
    Mar 27 at 14:32







1




1





Welcome to TeX.SX. When you post a question, please provide a "Minimal Working Example" (MWE) that starts with documentclass, includes all relevant usepackage commands, ends with enddocument and compiles without errors, even if it does not produce your desired output.

– Sandy G
Mar 27 at 14:32





Welcome to TeX.SX. When you post a question, please provide a "Minimal Working Example" (MWE) that starts with documentclass, includes all relevant usepackage commands, ends with enddocument and compiles without errors, even if it does not produce your desired output.

– Sandy G
Mar 27 at 14:32










2 Answers
2






active

oldest

votes


















10














You could just tell TikZ explicitly that you want an integer.



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = int(1 - floor(nnodes / 2) - 1);
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


enter image description here



Or



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath int nnodes,leftnum,rightnum;
nnodes = 3 ^ ilayer;
leftnum = 1 - floor(nnodes / 2) - 1;
rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
x = isibling * d;
y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


In principle you do not need the math library here.



documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer [evaluate=ilayer as nnodes using int(3 ^ ilayer),
evaluate=nnodes as leftnum using int(1 - floor(nnodes / 2) - 1),
evaluate=nnodes as rightnum using int(nnodes - floor(nnodes / 2) - 1)]
in 0,...,3
foreach isibling
[evaluate=ilayer as d using 3 ^ (- ilayer) * 15,
evaluate=isibling as x using isibling * d,
evaluate=ilayer as y using - ilayer * 2]
in leftnum,...,rightnum
node[mynode] (node_ilayer_isibling) at (x cm, y cm)
isibling;


endtikzpicture
enddocument


enter image description here






share|improve this answer

























  • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

    – landings
    Mar 27 at 4:27






  • 1





    @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

    – marmot
    Mar 27 at 4:33


















8














As @marmot said you do not need tikzmath here, but if you use it you can do it in more efficient way :



  • You can have a single tikzmath command with loops inside it.

  • You can declare your integer variables as int so you do not need to do int() afterward.

  • As nnodes is odd you do not need separate rightnum and leftnum as rightnum = - leftnum;

  • Why you use 1-floor(nnodes/2)-1 in place of -floor(nnodes/2) ?

  • The value d can be calculated in the outer loop.

  • Instead of using x=isibling*d you can say [x=d cm] and then use isibling asx. And in the same way y can be replaced by ilayer using [y=-2cm].

So here is my proposal :



documentclass[tikz,border=7pt]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
tikzmath
int ilayer,nnodes,rightnum,isibling;
nnodes = 1;
for ilayer in 0,...,3
rightnum = (nnodes-1)/2;
d = 15/nnodes;
for isibling in -rightnum,...,rightnum

path[x=d cm,y=-2cm]
node[node] (node_ilayer_isibling) at (isibling, ilayer) isibling;
;
;
nnodes = 3*nnodes;
;

endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    Thanks for your help. I am new to LaTeX and need more practice. I didn't know I could loop and draw things just inside tikzmath code.

    – landings
    Mar 27 at 8:03






  • 2





    Don't worry, even some experts don't know how to use tikzmath ;)

    – Kpym
    Mar 27 at 9:34











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2 Answers
2






active

oldest

votes








2 Answers
2






active

oldest

votes









active

oldest

votes






active

oldest

votes









10














You could just tell TikZ explicitly that you want an integer.



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = int(1 - floor(nnodes / 2) - 1);
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


enter image description here



Or



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath int nnodes,leftnum,rightnum;
nnodes = 3 ^ ilayer;
leftnum = 1 - floor(nnodes / 2) - 1;
rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
x = isibling * d;
y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


In principle you do not need the math library here.



documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer [evaluate=ilayer as nnodes using int(3 ^ ilayer),
evaluate=nnodes as leftnum using int(1 - floor(nnodes / 2) - 1),
evaluate=nnodes as rightnum using int(nnodes - floor(nnodes / 2) - 1)]
in 0,...,3
foreach isibling
[evaluate=ilayer as d using 3 ^ (- ilayer) * 15,
evaluate=isibling as x using isibling * d,
evaluate=ilayer as y using - ilayer * 2]
in leftnum,...,rightnum
node[mynode] (node_ilayer_isibling) at (x cm, y cm)
isibling;


endtikzpicture
enddocument


enter image description here






share|improve this answer

























  • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

    – landings
    Mar 27 at 4:27






  • 1





    @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

    – marmot
    Mar 27 at 4:33















10














You could just tell TikZ explicitly that you want an integer.



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = int(1 - floor(nnodes / 2) - 1);
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


enter image description here



Or



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath int nnodes,leftnum,rightnum;
nnodes = 3 ^ ilayer;
leftnum = 1 - floor(nnodes / 2) - 1;
rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
x = isibling * d;
y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


In principle you do not need the math library here.



documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer [evaluate=ilayer as nnodes using int(3 ^ ilayer),
evaluate=nnodes as leftnum using int(1 - floor(nnodes / 2) - 1),
evaluate=nnodes as rightnum using int(nnodes - floor(nnodes / 2) - 1)]
in 0,...,3
foreach isibling
[evaluate=ilayer as d using 3 ^ (- ilayer) * 15,
evaluate=isibling as x using isibling * d,
evaluate=ilayer as y using - ilayer * 2]
in leftnum,...,rightnum
node[mynode] (node_ilayer_isibling) at (x cm, y cm)
isibling;


endtikzpicture
enddocument


enter image description here






share|improve this answer

























  • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

    – landings
    Mar 27 at 4:27






  • 1





    @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

    – marmot
    Mar 27 at 4:33













10












10








10







You could just tell TikZ explicitly that you want an integer.



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = int(1 - floor(nnodes / 2) - 1);
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


enter image description here



Or



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath int nnodes,leftnum,rightnum;
nnodes = 3 ^ ilayer;
leftnum = 1 - floor(nnodes / 2) - 1;
rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
x = isibling * d;
y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


In principle you do not need the math library here.



documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer [evaluate=ilayer as nnodes using int(3 ^ ilayer),
evaluate=nnodes as leftnum using int(1 - floor(nnodes / 2) - 1),
evaluate=nnodes as rightnum using int(nnodes - floor(nnodes / 2) - 1)]
in 0,...,3
foreach isibling
[evaluate=ilayer as d using 3 ^ (- ilayer) * 15,
evaluate=isibling as x using isibling * d,
evaluate=ilayer as y using - ilayer * 2]
in leftnum,...,rightnum
node[mynode] (node_ilayer_isibling) at (x cm, y cm)
isibling;


endtikzpicture
enddocument


enter image description here






share|improve this answer















You could just tell TikZ explicitly that you want an integer.



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath nnodes = 3 ^ ilayer;
tikzmath leftnum = int(1 - floor(nnodes / 2) - 1);
tikzmath rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
tikzmath x = isibling * d;
tikzmath y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


enter image description here



Or



documentclass[tikz,border=3.14mm]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer in 0,...,3
tikzmath int nnodes,leftnum,rightnum;
nnodes = 3 ^ ilayer;
leftnum = 1 - floor(nnodes / 2) - 1;
rightnum = nnodes - floor(nnodes / 2) - 1;
foreach isibling in leftnum,...,rightnum
tikzmath d = 3 ^ (- ilayer) * 15;
x = isibling * d;
y = - ilayer * 2;
node[mynode] (node_ilayer_isibling) at (x cm, y cm) isibling;


endtikzpicture
enddocument


In principle you do not need the math library here.



documentclass[tikz,border=3.14mm]standalone
begindocument
begintikzpicture
tikzsetmynode/.style=circle, fill=blue!25, minimum size=0.1 cm
foreach ilayer [evaluate=ilayer as nnodes using int(3 ^ ilayer),
evaluate=nnodes as leftnum using int(1 - floor(nnodes / 2) - 1),
evaluate=nnodes as rightnum using int(nnodes - floor(nnodes / 2) - 1)]
in 0,...,3
foreach isibling
[evaluate=ilayer as d using 3 ^ (- ilayer) * 15,
evaluate=isibling as x using isibling * d,
evaluate=ilayer as y using - ilayer * 2]
in leftnum,...,rightnum
node[mynode] (node_ilayer_isibling) at (x cm, y cm)
isibling;


endtikzpicture
enddocument


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 27 at 4:29

























answered Mar 27 at 4:16









marmotmarmot

119k6154288




119k6154288












  • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

    – landings
    Mar 27 at 4:27






  • 1





    @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

    – marmot
    Mar 27 at 4:33

















  • Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

    – landings
    Mar 27 at 4:27






  • 1





    @landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

    – marmot
    Mar 27 at 4:33
















Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

– landings
Mar 27 at 4:27





Thanks a lot. I finally get where the problem starts. Why 1 - floor(nnodes / 2) - 1 can be non-integer? Even 1 - int(nnodes / 2) - 1 is problematic.

– landings
Mar 27 at 4:27




1




1





@landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

– marmot
Mar 27 at 4:33





@landings It is due to the way foreach is implemented, internally TikZ computes with dimensions and this can lead to slight inconsistencies. So it is better to wrap the full expression into int.

– marmot
Mar 27 at 4:33











8














As @marmot said you do not need tikzmath here, but if you use it you can do it in more efficient way :



  • You can have a single tikzmath command with loops inside it.

  • You can declare your integer variables as int so you do not need to do int() afterward.

  • As nnodes is odd you do not need separate rightnum and leftnum as rightnum = - leftnum;

  • Why you use 1-floor(nnodes/2)-1 in place of -floor(nnodes/2) ?

  • The value d can be calculated in the outer loop.

  • Instead of using x=isibling*d you can say [x=d cm] and then use isibling asx. And in the same way y can be replaced by ilayer using [y=-2cm].

So here is my proposal :



documentclass[tikz,border=7pt]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
tikzmath
int ilayer,nnodes,rightnum,isibling;
nnodes = 1;
for ilayer in 0,...,3
rightnum = (nnodes-1)/2;
d = 15/nnodes;
for isibling in -rightnum,...,rightnum

path[x=d cm,y=-2cm]
node[node] (node_ilayer_isibling) at (isibling, ilayer) isibling;
;
;
nnodes = 3*nnodes;
;

endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    Thanks for your help. I am new to LaTeX and need more practice. I didn't know I could loop and draw things just inside tikzmath code.

    – landings
    Mar 27 at 8:03






  • 2





    Don't worry, even some experts don't know how to use tikzmath ;)

    – Kpym
    Mar 27 at 9:34















8














As @marmot said you do not need tikzmath here, but if you use it you can do it in more efficient way :



  • You can have a single tikzmath command with loops inside it.

  • You can declare your integer variables as int so you do not need to do int() afterward.

  • As nnodes is odd you do not need separate rightnum and leftnum as rightnum = - leftnum;

  • Why you use 1-floor(nnodes/2)-1 in place of -floor(nnodes/2) ?

  • The value d can be calculated in the outer loop.

  • Instead of using x=isibling*d you can say [x=d cm] and then use isibling asx. And in the same way y can be replaced by ilayer using [y=-2cm].

So here is my proposal :



documentclass[tikz,border=7pt]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
tikzmath
int ilayer,nnodes,rightnum,isibling;
nnodes = 1;
for ilayer in 0,...,3
rightnum = (nnodes-1)/2;
d = 15/nnodes;
for isibling in -rightnum,...,rightnum

path[x=d cm,y=-2cm]
node[node] (node_ilayer_isibling) at (isibling, ilayer) isibling;
;
;
nnodes = 3*nnodes;
;

endtikzpicture
enddocument


enter image description here






share|improve this answer




















  • 1





    Thanks for your help. I am new to LaTeX and need more practice. I didn't know I could loop and draw things just inside tikzmath code.

    – landings
    Mar 27 at 8:03






  • 2





    Don't worry, even some experts don't know how to use tikzmath ;)

    – Kpym
    Mar 27 at 9:34













8












8








8







As @marmot said you do not need tikzmath here, but if you use it you can do it in more efficient way :



  • You can have a single tikzmath command with loops inside it.

  • You can declare your integer variables as int so you do not need to do int() afterward.

  • As nnodes is odd you do not need separate rightnum and leftnum as rightnum = - leftnum;

  • Why you use 1-floor(nnodes/2)-1 in place of -floor(nnodes/2) ?

  • The value d can be calculated in the outer loop.

  • Instead of using x=isibling*d you can say [x=d cm] and then use isibling asx. And in the same way y can be replaced by ilayer using [y=-2cm].

So here is my proposal :



documentclass[tikz,border=7pt]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
tikzmath
int ilayer,nnodes,rightnum,isibling;
nnodes = 1;
for ilayer in 0,...,3
rightnum = (nnodes-1)/2;
d = 15/nnodes;
for isibling in -rightnum,...,rightnum

path[x=d cm,y=-2cm]
node[node] (node_ilayer_isibling) at (isibling, ilayer) isibling;
;
;
nnodes = 3*nnodes;
;

endtikzpicture
enddocument


enter image description here






share|improve this answer















As @marmot said you do not need tikzmath here, but if you use it you can do it in more efficient way :



  • You can have a single tikzmath command with loops inside it.

  • You can declare your integer variables as int so you do not need to do int() afterward.

  • As nnodes is odd you do not need separate rightnum and leftnum as rightnum = - leftnum;

  • Why you use 1-floor(nnodes/2)-1 in place of -floor(nnodes/2) ?

  • The value d can be calculated in the outer loop.

  • Instead of using x=isibling*d you can say [x=d cm] and then use isibling asx. And in the same way y can be replaced by ilayer using [y=-2cm].

So here is my proposal :



documentclass[tikz,border=7pt]standalone
usetikzlibrarymath
begindocument
begintikzpicture
tikzstylenode=[circle, fill=blue!25, minimum size=0.1 cm];
tikzmath
int ilayer,nnodes,rightnum,isibling;
nnodes = 1;
for ilayer in 0,...,3
rightnum = (nnodes-1)/2;
d = 15/nnodes;
for isibling in -rightnum,...,rightnum

path[x=d cm,y=-2cm]
node[node] (node_ilayer_isibling) at (isibling, ilayer) isibling;
;
;
nnodes = 3*nnodes;
;

endtikzpicture
enddocument


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 27 at 10:51

























answered Mar 27 at 7:04









KpymKpym

17.9k24192




17.9k24192







  • 1





    Thanks for your help. I am new to LaTeX and need more practice. I didn't know I could loop and draw things just inside tikzmath code.

    – landings
    Mar 27 at 8:03






  • 2





    Don't worry, even some experts don't know how to use tikzmath ;)

    – Kpym
    Mar 27 at 9:34












  • 1





    Thanks for your help. I am new to LaTeX and need more practice. I didn't know I could loop and draw things just inside tikzmath code.

    – landings
    Mar 27 at 8:03






  • 2





    Don't worry, even some experts don't know how to use tikzmath ;)

    – Kpym
    Mar 27 at 9:34







1




1





Thanks for your help. I am new to LaTeX and need more practice. I didn't know I could loop and draw things just inside tikzmath code.

– landings
Mar 27 at 8:03





Thanks for your help. I am new to LaTeX and need more practice. I didn't know I could loop and draw things just inside tikzmath code.

– landings
Mar 27 at 8:03




2




2





Don't worry, even some experts don't know how to use tikzmath ;)

– Kpym
Mar 27 at 9:34





Don't worry, even some experts don't know how to use tikzmath ;)

– Kpym
Mar 27 at 9:34

















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