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unsure how to expand a LAX pair for KDV equation



The Next CEO of Stack OverflowWhat exactly is meant by 'Integrate the Equation of Motion'?How to find Backlund transformation between the KdV and mKdV equations?Necc. and suff. conditions for a canonical transformation.Use conservation of energy to justify where the maximum speed of the sphere occursHow to find a Lax pairIs my derivation of constant acceleration equations correctFinding constants of a general solution to an ODEMagnetic force term in Kobe's derivation of Maxwell's equationsIs it possible to prove that the speed of a falling object in a quarter of a circle is $sqrtfrac3Rg4$ given these parameters?Understanding the notation when finding action-angle coordinates










0












$begingroup$


This is my first post so im not sure how to make it all mathsy so im going to write it on here, I know that to find the lax equation you find [LM-ML]=0 but im struggling to follow the expansion,



for eg $$L=left(fracddxright)^2+u$$
$$M=aleft(fracddxright)^3+bufracddx+cfracdudx$$



so LM would be $=a(d/dx)^5+$(on the book it says $b(d/dx)(u(d/dx)^2+(du/dx)(d/dx)$) i am unsure how this part comes about, ive tried to expand it and do it all but it doesn't simplify to that



im sorry if it doesnt look clear, again this is my first post.










share|cite|improve this question











$endgroup$











  • $begingroup$
    By "d/dx^2" do you mean $$left(fracddxright)^2$$ or $$fracddx^2$$ or anything else?
    $endgroup$
    – clathratus
    Mar 19 at 22:16










  • $begingroup$
    (d/dx)^2, sorry for not making that clear
    $endgroup$
    – 123123
    Mar 19 at 22:25















0












$begingroup$


This is my first post so im not sure how to make it all mathsy so im going to write it on here, I know that to find the lax equation you find [LM-ML]=0 but im struggling to follow the expansion,



for eg $$L=left(fracddxright)^2+u$$
$$M=aleft(fracddxright)^3+bufracddx+cfracdudx$$



so LM would be $=a(d/dx)^5+$(on the book it says $b(d/dx)(u(d/dx)^2+(du/dx)(d/dx)$) i am unsure how this part comes about, ive tried to expand it and do it all but it doesn't simplify to that



im sorry if it doesnt look clear, again this is my first post.










share|cite|improve this question











$endgroup$











  • $begingroup$
    By "d/dx^2" do you mean $$left(fracddxright)^2$$ or $$fracddx^2$$ or anything else?
    $endgroup$
    – clathratus
    Mar 19 at 22:16










  • $begingroup$
    (d/dx)^2, sorry for not making that clear
    $endgroup$
    – 123123
    Mar 19 at 22:25













0












0








0





$begingroup$


This is my first post so im not sure how to make it all mathsy so im going to write it on here, I know that to find the lax equation you find [LM-ML]=0 but im struggling to follow the expansion,



for eg $$L=left(fracddxright)^2+u$$
$$M=aleft(fracddxright)^3+bufracddx+cfracdudx$$



so LM would be $=a(d/dx)^5+$(on the book it says $b(d/dx)(u(d/dx)^2+(du/dx)(d/dx)$) i am unsure how this part comes about, ive tried to expand it and do it all but it doesn't simplify to that



im sorry if it doesnt look clear, again this is my first post.










share|cite|improve this question











$endgroup$




This is my first post so im not sure how to make it all mathsy so im going to write it on here, I know that to find the lax equation you find [LM-ML]=0 but im struggling to follow the expansion,



for eg $$L=left(fracddxright)^2+u$$
$$M=aleft(fracddxright)^3+bufracddx+cfracdudx$$



so LM would be $=a(d/dx)^5+$(on the book it says $b(d/dx)(u(d/dx)^2+(du/dx)(d/dx)$) i am unsure how this part comes about, ive tried to expand it and do it all but it doesn't simplify to that



im sorry if it doesnt look clear, again this is my first post.







classical-mechanics integrable-systems lax-pair






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 20 at 0:29









clathratus

5,0361438




5,0361438










asked Mar 19 at 21:58









123123123123

1




1











  • $begingroup$
    By "d/dx^2" do you mean $$left(fracddxright)^2$$ or $$fracddx^2$$ or anything else?
    $endgroup$
    – clathratus
    Mar 19 at 22:16










  • $begingroup$
    (d/dx)^2, sorry for not making that clear
    $endgroup$
    – 123123
    Mar 19 at 22:25
















  • $begingroup$
    By "d/dx^2" do you mean $$left(fracddxright)^2$$ or $$fracddx^2$$ or anything else?
    $endgroup$
    – clathratus
    Mar 19 at 22:16










  • $begingroup$
    (d/dx)^2, sorry for not making that clear
    $endgroup$
    – 123123
    Mar 19 at 22:25















$begingroup$
By "d/dx^2" do you mean $$left(fracddxright)^2$$ or $$fracddx^2$$ or anything else?
$endgroup$
– clathratus
Mar 19 at 22:16




$begingroup$
By "d/dx^2" do you mean $$left(fracddxright)^2$$ or $$fracddx^2$$ or anything else?
$endgroup$
– clathratus
Mar 19 at 22:16












$begingroup$
(d/dx)^2, sorry for not making that clear
$endgroup$
– 123123
Mar 19 at 22:25




$begingroup$
(d/dx)^2, sorry for not making that clear
$endgroup$
– 123123
Mar 19 at 22:25










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