Find An Eigenvalue & Eigenvector from a given Eigenvalue and eigenvector The Next CEO of Stack OverflowEigenvector of A to given Eigenvalue which requires row swapping to get reduced echelon formGiven matrix A with eigenvalue $lambda$ and corresponding eigenvector x, prove $A^k$ has eigenvalue $lambda^k$How to find eigenvector of given matrix?Find orthogonal Q given eigenvalue and eigenvector?Find eigenvector and eigenvelue of 2 by 2 symmetric matrix, given another eigenvector and eigenvalueUnique Eigenvalue and Unique EigenvectorGiven eigenvalue and eigenvector Find $A^101 $Eigenvalue defined indirectly by eigenvector?Finding the eigenvector given eigenvalue and $A$?Question regarding the definition of eigenvalue and eigenvector
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Find An Eigenvalue & Eigenvector from a given Eigenvalue and eigenvector
The Next CEO of Stack OverflowEigenvector of A to given Eigenvalue which requires row swapping to get reduced echelon formGiven matrix A with eigenvalue $lambda$ and corresponding eigenvector x, prove $A^k$ has eigenvalue $lambda^k$How to find eigenvector of given matrix?Find orthogonal Q given eigenvalue and eigenvector?Find eigenvector and eigenvelue of 2 by 2 symmetric matrix, given another eigenvector and eigenvalueUnique Eigenvalue and Unique EigenvectorGiven eigenvalue and eigenvector Find $A^101 $Eigenvalue defined indirectly by eigenvector?Finding the eigenvector given eigenvalue and $A$?Question regarding the definition of eigenvalue and eigenvector
$begingroup$
I was given a 3x3 matrix and I was given a complex Eigenvalue of -2+6i. They also gave me the eigenvector
[-6-2i]
[1]
[9i].
I have to find another eigenvector and eigenvalue that isn't given.
I attempted to use the formula Ax=lamdax. I was trying to solve for A with x being the eigenvector and lamda being -2+6i. That doesn't give me a matrix though. I'm lost.
linear-algebra eigenvalues-eigenvectors
$endgroup$
add a comment |
$begingroup$
I was given a 3x3 matrix and I was given a complex Eigenvalue of -2+6i. They also gave me the eigenvector
[-6-2i]
[1]
[9i].
I have to find another eigenvector and eigenvalue that isn't given.
I attempted to use the formula Ax=lamdax. I was trying to solve for A with x being the eigenvector and lamda being -2+6i. That doesn't give me a matrix though. I'm lost.
linear-algebra eigenvalues-eigenvectors
$endgroup$
2
$begingroup$
Hint: If the matrix has only real values, then another eigenvalue will be $lambda = -2 - 6i$ (the complex conjugate).
$endgroup$
– Hyperion
Mar 19 at 21:46
$begingroup$
Oh. I feel dumb, thank you. Simple and easy
$endgroup$
– Amy Kulp
Mar 19 at 21:49
add a comment |
$begingroup$
I was given a 3x3 matrix and I was given a complex Eigenvalue of -2+6i. They also gave me the eigenvector
[-6-2i]
[1]
[9i].
I have to find another eigenvector and eigenvalue that isn't given.
I attempted to use the formula Ax=lamdax. I was trying to solve for A with x being the eigenvector and lamda being -2+6i. That doesn't give me a matrix though. I'm lost.
linear-algebra eigenvalues-eigenvectors
$endgroup$
I was given a 3x3 matrix and I was given a complex Eigenvalue of -2+6i. They also gave me the eigenvector
[-6-2i]
[1]
[9i].
I have to find another eigenvector and eigenvalue that isn't given.
I attempted to use the formula Ax=lamdax. I was trying to solve for A with x being the eigenvector and lamda being -2+6i. That doesn't give me a matrix though. I'm lost.
linear-algebra eigenvalues-eigenvectors
linear-algebra eigenvalues-eigenvectors
asked Mar 19 at 21:44
Amy KulpAmy Kulp
426
426
2
$begingroup$
Hint: If the matrix has only real values, then another eigenvalue will be $lambda = -2 - 6i$ (the complex conjugate).
$endgroup$
– Hyperion
Mar 19 at 21:46
$begingroup$
Oh. I feel dumb, thank you. Simple and easy
$endgroup$
– Amy Kulp
Mar 19 at 21:49
add a comment |
2
$begingroup$
Hint: If the matrix has only real values, then another eigenvalue will be $lambda = -2 - 6i$ (the complex conjugate).
$endgroup$
– Hyperion
Mar 19 at 21:46
$begingroup$
Oh. I feel dumb, thank you. Simple and easy
$endgroup$
– Amy Kulp
Mar 19 at 21:49
2
2
$begingroup$
Hint: If the matrix has only real values, then another eigenvalue will be $lambda = -2 - 6i$ (the complex conjugate).
$endgroup$
– Hyperion
Mar 19 at 21:46
$begingroup$
Hint: If the matrix has only real values, then another eigenvalue will be $lambda = -2 - 6i$ (the complex conjugate).
$endgroup$
– Hyperion
Mar 19 at 21:46
$begingroup$
Oh. I feel dumb, thank you. Simple and easy
$endgroup$
– Amy Kulp
Mar 19 at 21:49
$begingroup$
Oh. I feel dumb, thank you. Simple and easy
$endgroup$
– Amy Kulp
Mar 19 at 21:49
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Like Hyperion said, the new eigenvalue is -2-6i, so the eigenvector is -6+2i,1,-9i
$endgroup$
$begingroup$
Please use the edit link on your question to add additional information. The Post Answer button should be used only for complete answers to the question. - From Review
$endgroup$
– clathratus
Mar 19 at 22:18
$begingroup$
@clathratus If I am not mistaken, this is a complete answer.
$endgroup$
– YiFan
Mar 19 at 22:20
$begingroup$
Then accept your answer.
$endgroup$
– clathratus
Mar 19 at 22:21
$begingroup$
@clathratus You can’t accept your own answer to a question until 48 hours have elapsed. You’d do well to familiarize yourself with these and other restrictions.
$endgroup$
– amd
Mar 19 at 23:06
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Like Hyperion said, the new eigenvalue is -2-6i, so the eigenvector is -6+2i,1,-9i
$endgroup$
$begingroup$
Please use the edit link on your question to add additional information. The Post Answer button should be used only for complete answers to the question. - From Review
$endgroup$
– clathratus
Mar 19 at 22:18
$begingroup$
@clathratus If I am not mistaken, this is a complete answer.
$endgroup$
– YiFan
Mar 19 at 22:20
$begingroup$
Then accept your answer.
$endgroup$
– clathratus
Mar 19 at 22:21
$begingroup$
@clathratus You can’t accept your own answer to a question until 48 hours have elapsed. You’d do well to familiarize yourself with these and other restrictions.
$endgroup$
– amd
Mar 19 at 23:06
add a comment |
$begingroup$
Like Hyperion said, the new eigenvalue is -2-6i, so the eigenvector is -6+2i,1,-9i
$endgroup$
$begingroup$
Please use the edit link on your question to add additional information. The Post Answer button should be used only for complete answers to the question. - From Review
$endgroup$
– clathratus
Mar 19 at 22:18
$begingroup$
@clathratus If I am not mistaken, this is a complete answer.
$endgroup$
– YiFan
Mar 19 at 22:20
$begingroup$
Then accept your answer.
$endgroup$
– clathratus
Mar 19 at 22:21
$begingroup$
@clathratus You can’t accept your own answer to a question until 48 hours have elapsed. You’d do well to familiarize yourself with these and other restrictions.
$endgroup$
– amd
Mar 19 at 23:06
add a comment |
$begingroup$
Like Hyperion said, the new eigenvalue is -2-6i, so the eigenvector is -6+2i,1,-9i
$endgroup$
Like Hyperion said, the new eigenvalue is -2-6i, so the eigenvector is -6+2i,1,-9i
answered Mar 19 at 21:50
Amy KulpAmy Kulp
426
426
$begingroup$
Please use the edit link on your question to add additional information. The Post Answer button should be used only for complete answers to the question. - From Review
$endgroup$
– clathratus
Mar 19 at 22:18
$begingroup$
@clathratus If I am not mistaken, this is a complete answer.
$endgroup$
– YiFan
Mar 19 at 22:20
$begingroup$
Then accept your answer.
$endgroup$
– clathratus
Mar 19 at 22:21
$begingroup$
@clathratus You can’t accept your own answer to a question until 48 hours have elapsed. You’d do well to familiarize yourself with these and other restrictions.
$endgroup$
– amd
Mar 19 at 23:06
add a comment |
$begingroup$
Please use the edit link on your question to add additional information. The Post Answer button should be used only for complete answers to the question. - From Review
$endgroup$
– clathratus
Mar 19 at 22:18
$begingroup$
@clathratus If I am not mistaken, this is a complete answer.
$endgroup$
– YiFan
Mar 19 at 22:20
$begingroup$
Then accept your answer.
$endgroup$
– clathratus
Mar 19 at 22:21
$begingroup$
@clathratus You can’t accept your own answer to a question until 48 hours have elapsed. You’d do well to familiarize yourself with these and other restrictions.
$endgroup$
– amd
Mar 19 at 23:06
$begingroup$
Please use the edit link on your question to add additional information. The Post Answer button should be used only for complete answers to the question. - From Review
$endgroup$
– clathratus
Mar 19 at 22:18
$begingroup$
Please use the edit link on your question to add additional information. The Post Answer button should be used only for complete answers to the question. - From Review
$endgroup$
– clathratus
Mar 19 at 22:18
$begingroup$
@clathratus If I am not mistaken, this is a complete answer.
$endgroup$
– YiFan
Mar 19 at 22:20
$begingroup$
@clathratus If I am not mistaken, this is a complete answer.
$endgroup$
– YiFan
Mar 19 at 22:20
$begingroup$
Then accept your answer.
$endgroup$
– clathratus
Mar 19 at 22:21
$begingroup$
Then accept your answer.
$endgroup$
– clathratus
Mar 19 at 22:21
$begingroup$
@clathratus You can’t accept your own answer to a question until 48 hours have elapsed. You’d do well to familiarize yourself with these and other restrictions.
$endgroup$
– amd
Mar 19 at 23:06
$begingroup$
@clathratus You can’t accept your own answer to a question until 48 hours have elapsed. You’d do well to familiarize yourself with these and other restrictions.
$endgroup$
– amd
Mar 19 at 23:06
add a comment |
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$begingroup$
Hint: If the matrix has only real values, then another eigenvalue will be $lambda = -2 - 6i$ (the complex conjugate).
$endgroup$
– Hyperion
Mar 19 at 21:46
$begingroup$
Oh. I feel dumb, thank you. Simple and easy
$endgroup$
– Amy Kulp
Mar 19 at 21:49