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Could anyone just tell me what does he, mean by at the point $2$, selecting a number according to the probabilities, $p(x_0)$? does he meant to chhose the largest one out of $p_i(x_0), i=1,2,dots,N$?, let me write, $p_i$ are probability functions $X$, and $sum_i=1^N p_i(x)=1forall xin X, sigma_n=1,2,3,dots, N $, $omega_sigma_n$
are mappings on $X$.
I am also not comfortable with the notation $sigma_n$.

Thanks for helping. A little example would be fine too.

probability-theory iterated-function-system chaos-game

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asked 2 days ago

MarkovMarkov

17.3k1059181

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  I would take it to mean randomly choose a number from $1$ to $N,$ where the probability of choosing $k$ is $p_k(x_0).$ He must mean to say choose $sigma_1in1,dots,N$ since it doesn't make sense to apply an integer to $x_0.$
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  – saulspatz
  2 days ago
  

  
  
  
  


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  OKay Thanks, I was thinking that too. What do you think about the notation $sigma_n$? Can it be better?
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  – Markov
  2 days ago
  
  

  
  
  
  


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  I don't see why you object to $sigma_n$ What would you prefer?
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  – saulspatz
  2 days ago
  

  
  
  
  


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  what is $n$? he has not defined before, only $N$ I understand.
  $endgroup$
  – Markov
  2 days ago
  

  
  
  
  


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  Okay, $sigma_i$ then. The subscript is a variable, it doesn't matter what you call it. Still, what don't you like about $sigma_i?$
  $endgroup$
  – saulspatz
  2 days ago
  

  
  
  
  

add a comment | 

0

$begingroup$

Could anyone just tell me what does he, mean by at the point $2$, selecting a number according to the probabilities, $p(x_0)$? does he meant to chhose the largest one out of $p_i(x_0), i=1,2,dots,N$?, let me write, $p_i$ are probability functions $X$, and $sum_i=1^N p_i(x)=1forall xin X, sigma_n=1,2,3,dots, N $, $omega_sigma_n$
are mappings on $X$.
I am also not comfortable with the notation $sigma_n$.

Thanks for helping. A little example would be fine too.

probability-theory iterated-function-system chaos-game

share|cite|improve this question

asked 2 days ago

MarkovMarkov

17.3k1059181

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I would take it to mean randomly choose a number from $1$ to $N,$ where the probability of choosing $k$ is $p_k(x_0).$ He must mean to say choose $sigma_1in1,dots,N$ since it doesn't make sense to apply an integer to $x_0.$
  $endgroup$
  – saulspatz
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  OKay Thanks, I was thinking that too. What do you think about the notation $sigma_n$? Can it be better?
  $endgroup$
  – Markov
  2 days ago
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  I don't see why you object to $sigma_n$ What would you prefer?
  $endgroup$
  – saulspatz
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  what is $n$? he has not defined before, only $N$ I understand.
  $endgroup$
  – Markov
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  Okay, $sigma_i$ then. The subscript is a variable, it doesn't matter what you call it. Still, what don't you like about $sigma_i?$
  $endgroup$
  – saulspatz
  2 days ago
  

  
  
  
  

add a comment | 

$begingroup$

Could anyone just tell me what does he, mean by at the point $2$, selecting a number according to the probabilities, $p(x_0)$? does he meant to chhose the largest one out of $p_i(x_0), i=1,2,dots,N$?, let me write, $p_i$ are probability functions $X$, and $sum_i=1^N p_i(x)=1forall xin X, sigma_n=1,2,3,dots, N $, $omega_sigma_n$
are mappings on $X$.
I am also not comfortable with the notation $sigma_n$.

Thanks for helping. A little example would be fine too.

probability-theory iterated-function-system chaos-game

share|cite|improve this question

asked 2 days ago

MarkovMarkov

17.3k1059181

$endgroup$

share|cite|improve this question

asked 2 days ago

MarkovMarkov

17.3k1059181

share|cite|improve this question

asked 2 days ago

MarkovMarkov

17.3k1059181

asked 2 days ago

MarkovMarkov

17.3k1059181

asked 2 days ago

MarkovMarkov

17.3k1059181