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Show that $f$ is periodic, where $int_x^x+af(t)dt=b$


Differential Equation has a unique solution periodicHow do I show that all continuous periodic functions are bounded and uniform continuous?determine if a function is periodicCompute Limit Involving Integral and Periodic functionQuestion about a continuous periodic functionPeriodic solution: ODEIntegration of a Periodic FunctionProve that $F(x)=int_0^x f$ is periodicIs this function periodic function?Show that $lim_ntoinfty int_0^1f(x)g(nx)dx = 0$ $g$ periodic on $mathbbR$













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$begingroup$


Let $f:mathbbRrightarrowmathbbR$ continuous, for which there is an $a>0$, $binmathbbR$ such that $int_x^x+af(t)dt=b$, any $xinmathbbR$. Show that $f$ is periodic. By $F(x)=int_0^xf(t)dt$, I get that $b=F(x+a)-F(x)$ (Leibniz-Newton theorem) and by differentiating, the period is $a$. Is this sufficient?










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Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • $begingroup$
    Yeah. It's logical.
    $endgroup$
    – SinTan1729
    2 days ago















1












$begingroup$


Let $f:mathbbRrightarrowmathbbR$ continuous, for which there is an $a>0$, $binmathbbR$ such that $int_x^x+af(t)dt=b$, any $xinmathbbR$. Show that $f$ is periodic. By $F(x)=int_0^xf(t)dt$, I get that $b=F(x+a)-F(x)$ (Leibniz-Newton theorem) and by differentiating, the period is $a$. Is this sufficient?










share|cite|improve this question







New contributor




Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$











  • $begingroup$
    Yeah. It's logical.
    $endgroup$
    – SinTan1729
    2 days ago













1












1








1


1



$begingroup$


Let $f:mathbbRrightarrowmathbbR$ continuous, for which there is an $a>0$, $binmathbbR$ such that $int_x^x+af(t)dt=b$, any $xinmathbbR$. Show that $f$ is periodic. By $F(x)=int_0^xf(t)dt$, I get that $b=F(x+a)-F(x)$ (Leibniz-Newton theorem) and by differentiating, the period is $a$. Is this sufficient?










share|cite|improve this question







New contributor




Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




Let $f:mathbbRrightarrowmathbbR$ continuous, for which there is an $a>0$, $binmathbbR$ such that $int_x^x+af(t)dt=b$, any $xinmathbbR$. Show that $f$ is periodic. By $F(x)=int_0^xf(t)dt$, I get that $b=F(x+a)-F(x)$ (Leibniz-Newton theorem) and by differentiating, the period is $a$. Is this sufficient?







integration definite-integrals periodic-functions






share|cite|improve this question







New contributor




Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question







New contributor




Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question






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Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 2 days ago









Jacob DeniculaJacob Denicula

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New contributor





Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Jacob Denicula is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    Yeah. It's logical.
    $endgroup$
    – SinTan1729
    2 days ago
















  • $begingroup$
    Yeah. It's logical.
    $endgroup$
    – SinTan1729
    2 days ago















$begingroup$
Yeah. It's logical.
$endgroup$
– SinTan1729
2 days ago




$begingroup$
Yeah. It's logical.
$endgroup$
– SinTan1729
2 days ago










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