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Prove for a random variable $X$,$(E|X|^2)^2le E|X|E|X|^3$


a question about random variableWhen is there in a probability space no null sets?Computing Char. Function of a Random VariableInequality for inverse random variableConvergence in probability of exponentially distributed random variableDo we have $ int_A chi_B mu = mu(A) $ in a probability space?Chebyshev inequality for some random variableHow to show a binomial random variable dominates another binomial random variable with a smaller success value?Upper bound for quantile a random variableAlmost sure convergence of product of two random variable













1












$begingroup$


More general, for $alphain[0,2)$, is $(E|X|^2)^2le E|X|^2-alphaE|X|^2+alpha$ always true?



I don't have any idea to deal with such inequality concerning three expectations. Can someone give an idea on proving it? Thank you!










share|cite|improve this question











$endgroup$







  • 4




    $begingroup$
    Apply Cauchy's inequality with $f=|X|^(2-a)/2$, $g=|X|^(2+a)/2$.
    $endgroup$
    – user647486
    Mar 16 at 11:33










  • $begingroup$
    Thank you so much!
    $endgroup$
    – zbh2047
    Mar 16 at 13:03















1












$begingroup$


More general, for $alphain[0,2)$, is $(E|X|^2)^2le E|X|^2-alphaE|X|^2+alpha$ always true?



I don't have any idea to deal with such inequality concerning three expectations. Can someone give an idea on proving it? Thank you!










share|cite|improve this question











$endgroup$







  • 4




    $begingroup$
    Apply Cauchy's inequality with $f=|X|^(2-a)/2$, $g=|X|^(2+a)/2$.
    $endgroup$
    – user647486
    Mar 16 at 11:33










  • $begingroup$
    Thank you so much!
    $endgroup$
    – zbh2047
    Mar 16 at 13:03













1












1








1


1



$begingroup$


More general, for $alphain[0,2)$, is $(E|X|^2)^2le E|X|^2-alphaE|X|^2+alpha$ always true?



I don't have any idea to deal with such inequality concerning three expectations. Can someone give an idea on proving it? Thank you!










share|cite|improve this question











$endgroup$




More general, for $alphain[0,2)$, is $(E|X|^2)^2le E|X|^2-alphaE|X|^2+alpha$ always true?



I don't have any idea to deal with such inequality concerning three expectations. Can someone give an idea on proving it? Thank you!







probability-theory






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 16 at 10:24







zbh2047

















asked Mar 16 at 10:19









zbh2047zbh2047

639




639







  • 4




    $begingroup$
    Apply Cauchy's inequality with $f=|X|^(2-a)/2$, $g=|X|^(2+a)/2$.
    $endgroup$
    – user647486
    Mar 16 at 11:33










  • $begingroup$
    Thank you so much!
    $endgroup$
    – zbh2047
    Mar 16 at 13:03












  • 4




    $begingroup$
    Apply Cauchy's inequality with $f=|X|^(2-a)/2$, $g=|X|^(2+a)/2$.
    $endgroup$
    – user647486
    Mar 16 at 11:33










  • $begingroup$
    Thank you so much!
    $endgroup$
    – zbh2047
    Mar 16 at 13:03







4




4




$begingroup$
Apply Cauchy's inequality with $f=|X|^(2-a)/2$, $g=|X|^(2+a)/2$.
$endgroup$
– user647486
Mar 16 at 11:33




$begingroup$
Apply Cauchy's inequality with $f=|X|^(2-a)/2$, $g=|X|^(2+a)/2$.
$endgroup$
– user647486
Mar 16 at 11:33












$begingroup$
Thank you so much!
$endgroup$
– zbh2047
Mar 16 at 13:03




$begingroup$
Thank you so much!
$endgroup$
– zbh2047
Mar 16 at 13:03










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