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How to determine the sequence of this graph?


Result obtained on deletion of finite number of Fourier CoefficientsComplex Fourier series and its represntationFourier series coefficients' relation to original functionIs it possible to visualize the graph of a cosine or sine fourier series of an arbitrary function without calculating the coefficients?Visualize Fourier SeriesWays to determine how fast a sequence diverge/convergeDoubt regarding Fourier series coefficients.How can I determine general formula of this sequence?Finding Fourier Series TroubleFourier coefficients of $sin + cos$













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I can solve a Fourier series, but I don’t know how to determine the sequence.
It is necessary to determine the values ​​of the imaginary part of the Fourier coefficients of the following sequence: Graph in Picture. Click here










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    0












    $begingroup$


    I can solve a Fourier series, but I don’t know how to determine the sequence.
    It is necessary to determine the values ​​of the imaginary part of the Fourier coefficients of the following sequence: Graph in Picture. Click here










    share|cite|improve this question









    $endgroup$














      0












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      0





      $begingroup$


      I can solve a Fourier series, but I don’t know how to determine the sequence.
      It is necessary to determine the values ​​of the imaginary part of the Fourier coefficients of the following sequence: Graph in Picture. Click here










      share|cite|improve this question









      $endgroup$




      I can solve a Fourier series, but I don’t know how to determine the sequence.
      It is necessary to determine the values ​​of the imaginary part of the Fourier coefficients of the following sequence: Graph in Picture. Click here







      sequences-and-series analysis fourier-series






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      asked Mar 16 at 9:32









      ElyEly

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          You can define this as a periodic function with period $T$: $$f(t)=dfrac1Ttquadtextwhere,,kTlt tle (k+1)Tquadtextfor,,kinmathbb Z$$ since when $t=0$, $f(0)=0$ and when $t=T$, $f(T)=1.$






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            $begingroup$

            You can define this as a periodic function with period $T$: $$f(t)=dfrac1Ttquadtextwhere,,kTlt tle (k+1)Tquadtextfor,,kinmathbb Z$$ since when $t=0$, $f(0)=0$ and when $t=T$, $f(T)=1.$






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              0












              $begingroup$

              You can define this as a periodic function with period $T$: $$f(t)=dfrac1Ttquadtextwhere,,kTlt tle (k+1)Tquadtextfor,,kinmathbb Z$$ since when $t=0$, $f(0)=0$ and when $t=T$, $f(T)=1.$






              share|cite|improve this answer









              $endgroup$















                0












                0








                0





                $begingroup$

                You can define this as a periodic function with period $T$: $$f(t)=dfrac1Ttquadtextwhere,,kTlt tle (k+1)Tquadtextfor,,kinmathbb Z$$ since when $t=0$, $f(0)=0$ and when $t=T$, $f(T)=1.$






                share|cite|improve this answer









                $endgroup$



                You can define this as a periodic function with period $T$: $$f(t)=dfrac1Ttquadtextwhere,,kTlt tle (k+1)Tquadtextfor,,kinmathbb Z$$ since when $t=0$, $f(0)=0$ and when $t=T$, $f(T)=1.$







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                share|cite|improve this answer










                answered Mar 16 at 16:09









                poyeapoyea

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