Heat equation - stationary solutionThe initial condition for a heat equation with stationary solution subtractedIs the parabolic heat equation with pure neumann conditions well posed?Monotone solutions of the heat equation1D Rod, Heat EquationFinding steady-state solution for two-dimensional heat equationDifferential equation with homogeneous Dirichlet-Neumann boundary conditions2D Heat Equation - Exact Solution$L^infty$ norm of the heat equation solution, with Neumann conditionsHeat equation with time-dependent transport termIs the steady state solution of the Heat Equation with Dirichlet boundary conditions always 0?
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Heat equation - stationary solution
The initial condition for a heat equation with stationary solution subtractedIs the parabolic heat equation with pure neumann conditions well posed?Monotone solutions of the heat equation1D Rod, Heat EquationFinding steady-state solution for two-dimensional heat equationDifferential equation with homogeneous Dirichlet-Neumann boundary conditions2D Heat Equation - Exact Solution$L^infty$ norm of the heat equation solution, with Neumann conditionsHeat equation with time-dependent transport termIs the steady state solution of the Heat Equation with Dirichlet boundary conditions always 0?
$begingroup$
What are the conditions for the solution of the heat equation to become [sufficiently] stationary, i.e. to not change any more over time?
Here, I am talking about the 3D heat equation with Neumann and Dirichlet boundary data:
$$ partial_t u - a Delta u = f $$
with initial condition
$$ u(x,0) = u_0(x) $$
and boundary conditions
$$ u = g $$ and
$$ partial_n u = q $$
on some part of the boundary each.
Let's assume that $f,u_0,g,q$ and the unspecified domain are "sufficiently nice" for our problem. I am more looking for a broad answer regarding the convergence to the steady-state solution, as I observed this behaviour during some experiments.
Some thoughts of mine so far:
I guess that $f,g,q$ cannot change over time, to allow a steady-state solution? Or do I even need some form of $q=0$?
Or is this a simple matter of solving the new elliptic problem resulting from $partial_t u = 0$
A followup question would be: Can one do a time estimate for when such a solution might be reached?
pde heat-equation
$endgroup$
add a comment |
$begingroup$
What are the conditions for the solution of the heat equation to become [sufficiently] stationary, i.e. to not change any more over time?
Here, I am talking about the 3D heat equation with Neumann and Dirichlet boundary data:
$$ partial_t u - a Delta u = f $$
with initial condition
$$ u(x,0) = u_0(x) $$
and boundary conditions
$$ u = g $$ and
$$ partial_n u = q $$
on some part of the boundary each.
Let's assume that $f,u_0,g,q$ and the unspecified domain are "sufficiently nice" for our problem. I am more looking for a broad answer regarding the convergence to the steady-state solution, as I observed this behaviour during some experiments.
Some thoughts of mine so far:
I guess that $f,g,q$ cannot change over time, to allow a steady-state solution? Or do I even need some form of $q=0$?
Or is this a simple matter of solving the new elliptic problem resulting from $partial_t u = 0$
A followup question would be: Can one do a time estimate for when such a solution might be reached?
pde heat-equation
$endgroup$
$begingroup$
You are correct that $f,g, q$ must all become constant with respect to time, since all three can be expressed in terms of $u$, if $u$ is not time-dependent, they cannot be either. I suspect that is also a sufficient condition. If there is nothing exciting the system, I would expect it to enter a steady-state. But I don't have a mathematical demonstration.
$endgroup$
– Paul Sinclair
Mar 16 at 20:21
add a comment |
$begingroup$
What are the conditions for the solution of the heat equation to become [sufficiently] stationary, i.e. to not change any more over time?
Here, I am talking about the 3D heat equation with Neumann and Dirichlet boundary data:
$$ partial_t u - a Delta u = f $$
with initial condition
$$ u(x,0) = u_0(x) $$
and boundary conditions
$$ u = g $$ and
$$ partial_n u = q $$
on some part of the boundary each.
Let's assume that $f,u_0,g,q$ and the unspecified domain are "sufficiently nice" for our problem. I am more looking for a broad answer regarding the convergence to the steady-state solution, as I observed this behaviour during some experiments.
Some thoughts of mine so far:
I guess that $f,g,q$ cannot change over time, to allow a steady-state solution? Or do I even need some form of $q=0$?
Or is this a simple matter of solving the new elliptic problem resulting from $partial_t u = 0$
A followup question would be: Can one do a time estimate for when such a solution might be reached?
pde heat-equation
$endgroup$
What are the conditions for the solution of the heat equation to become [sufficiently] stationary, i.e. to not change any more over time?
Here, I am talking about the 3D heat equation with Neumann and Dirichlet boundary data:
$$ partial_t u - a Delta u = f $$
with initial condition
$$ u(x,0) = u_0(x) $$
and boundary conditions
$$ u = g $$ and
$$ partial_n u = q $$
on some part of the boundary each.
Let's assume that $f,u_0,g,q$ and the unspecified domain are "sufficiently nice" for our problem. I am more looking for a broad answer regarding the convergence to the steady-state solution, as I observed this behaviour during some experiments.
Some thoughts of mine so far:
I guess that $f,g,q$ cannot change over time, to allow a steady-state solution? Or do I even need some form of $q=0$?
Or is this a simple matter of solving the new elliptic problem resulting from $partial_t u = 0$
A followup question would be: Can one do a time estimate for when such a solution might be reached?
pde heat-equation
pde heat-equation
asked Mar 16 at 10:19
mh333mh333
1
1
$begingroup$
You are correct that $f,g, q$ must all become constant with respect to time, since all three can be expressed in terms of $u$, if $u$ is not time-dependent, they cannot be either. I suspect that is also a sufficient condition. If there is nothing exciting the system, I would expect it to enter a steady-state. But I don't have a mathematical demonstration.
$endgroup$
– Paul Sinclair
Mar 16 at 20:21
add a comment |
$begingroup$
You are correct that $f,g, q$ must all become constant with respect to time, since all three can be expressed in terms of $u$, if $u$ is not time-dependent, they cannot be either. I suspect that is also a sufficient condition. If there is nothing exciting the system, I would expect it to enter a steady-state. But I don't have a mathematical demonstration.
$endgroup$
– Paul Sinclair
Mar 16 at 20:21
$begingroup$
You are correct that $f,g, q$ must all become constant with respect to time, since all three can be expressed in terms of $u$, if $u$ is not time-dependent, they cannot be either. I suspect that is also a sufficient condition. If there is nothing exciting the system, I would expect it to enter a steady-state. But I don't have a mathematical demonstration.
$endgroup$
– Paul Sinclair
Mar 16 at 20:21
$begingroup$
You are correct that $f,g, q$ must all become constant with respect to time, since all three can be expressed in terms of $u$, if $u$ is not time-dependent, they cannot be either. I suspect that is also a sufficient condition. If there is nothing exciting the system, I would expect it to enter a steady-state. But I don't have a mathematical demonstration.
$endgroup$
– Paul Sinclair
Mar 16 at 20:21
add a comment |
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$begingroup$
You are correct that $f,g, q$ must all become constant with respect to time, since all three can be expressed in terms of $u$, if $u$ is not time-dependent, they cannot be either. I suspect that is also a sufficient condition. If there is nothing exciting the system, I would expect it to enter a steady-state. But I don't have a mathematical demonstration.
$endgroup$
– Paul Sinclair
Mar 16 at 20:21