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Grothendieck topology on stacks/fibred category



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Stack on commutative ring spectra?What are Mumford's 'moduli topologies'?Bijection between left exact localizations of $PSh(C)$ and Grothendieck topologies on $C$Covering sieves in a Grothendieck topologyIntersection condition for a Grothendieck topologyIs an étale morphism of algebraic stacks locally quasi-finite?Structures on Artin stacks and fppf-descentStacks and Grothendieck topology.Is a topological category a Grothendieck site?Set theoretic issues in the definition of a site in Stacks Project










1












$begingroup$


Let $p : mathcalS rightarrow mathcalC$ be a stack (or fibred category, I do not know if just being a fibred category is enough) over the site $mathcalC$.



I have read somewhere (I forgot where but I think on "Stacks project") that the site $mathcalC$ induces a Grothendieck topology on $mathcalS$ (something to do with a definition of strongly Cartesian) but I forgot the link and also the proof.



Can somebody explain to me the proof of this result (or the link)?










share|cite|improve this question









$endgroup$
















    1












    $begingroup$


    Let $p : mathcalS rightarrow mathcalC$ be a stack (or fibred category, I do not know if just being a fibred category is enough) over the site $mathcalC$.



    I have read somewhere (I forgot where but I think on "Stacks project") that the site $mathcalC$ induces a Grothendieck topology on $mathcalS$ (something to do with a definition of strongly Cartesian) but I forgot the link and also the proof.



    Can somebody explain to me the proof of this result (or the link)?










    share|cite|improve this question









    $endgroup$














      1












      1








      1





      $begingroup$


      Let $p : mathcalS rightarrow mathcalC$ be a stack (or fibred category, I do not know if just being a fibred category is enough) over the site $mathcalC$.



      I have read somewhere (I forgot where but I think on "Stacks project") that the site $mathcalC$ induces a Grothendieck topology on $mathcalS$ (something to do with a definition of strongly Cartesian) but I forgot the link and also the proof.



      Can somebody explain to me the proof of this result (or the link)?










      share|cite|improve this question









      $endgroup$




      Let $p : mathcalS rightarrow mathcalC$ be a stack (or fibred category, I do not know if just being a fibred category is enough) over the site $mathcalC$.



      I have read somewhere (I forgot where but I think on "Stacks project") that the site $mathcalC$ induces a Grothendieck topology on $mathcalS$ (something to do with a definition of strongly Cartesian) but I forgot the link and also the proof.



      Can somebody explain to me the proof of this result (or the link)?







      category-theory grothendieck-topologies algebraic-stacks topological-stacks






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 26 at 16:38









      MathemagicianMathemagician

      717




      717




















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