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Shortest maximum pairwise distance of points in a circle of radius R



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Mean distance between N equidistributed points in a circleA Sphere Containing Points of Pairwise Equal DistanceIs there any object/metric within all points are at same distance to each other?Determining the distance between 2 points based on their know distances to several other points.Given the pairwise distances between $n$ points, how can I find plausible coordinates for the points?Circle around three given circlesshowing that the maximum distance between any pair of points inside a circlemaximum distance between n points on unit circleGiven a pair of circle, Find 2 points on the perimeter of circle(one on each Circle) such that the Euclidean distance is K? Given Centre and Radius.How to localize points from an incomplete distance matrix in R?










2












$begingroup$


Given a positive real number $R$ and $n$ fixed points in a plane, find the largest possible value $M$ such that if the pairwise distance between the $n$ points is less or equal to $M$, there exists a circle of radius $R$ that contains all $n$ points.



I realize this is related to the smallest enclosing circle problem, but it is not the same. Basically, I have a set of points, and I know all the pairwise distances between them, and I am given a fixed radius. I want to be able to say that if the maximum pairwise distance between these points is less than $M$, then there is definitely a circle of radius $R$ that encloses all of them, where this M is as large as possible.



Obviously, for two points, the answer is $2R$. For three points, it gets more complicated, but using some geometry, I believe the answer is $sqrt2R$ (as in $sqrtR^2 + R^2$), but I haven't been able to prove it. I would like to generalize this to $n$ points, where I am fine with the answer being dependent on $n$.



My hypothesis is that $sqrt2R leq M leq 2R$ for all $n$, but I would be mainly interested in how large $M$ can be made as the number of points increases.










share|cite|improve this question









$endgroup$
















    2












    $begingroup$


    Given a positive real number $R$ and $n$ fixed points in a plane, find the largest possible value $M$ such that if the pairwise distance between the $n$ points is less or equal to $M$, there exists a circle of radius $R$ that contains all $n$ points.



    I realize this is related to the smallest enclosing circle problem, but it is not the same. Basically, I have a set of points, and I know all the pairwise distances between them, and I am given a fixed radius. I want to be able to say that if the maximum pairwise distance between these points is less than $M$, then there is definitely a circle of radius $R$ that encloses all of them, where this M is as large as possible.



    Obviously, for two points, the answer is $2R$. For three points, it gets more complicated, but using some geometry, I believe the answer is $sqrt2R$ (as in $sqrtR^2 + R^2$), but I haven't been able to prove it. I would like to generalize this to $n$ points, where I am fine with the answer being dependent on $n$.



    My hypothesis is that $sqrt2R leq M leq 2R$ for all $n$, but I would be mainly interested in how large $M$ can be made as the number of points increases.










    share|cite|improve this question









    $endgroup$














      2












      2








      2





      $begingroup$


      Given a positive real number $R$ and $n$ fixed points in a plane, find the largest possible value $M$ such that if the pairwise distance between the $n$ points is less or equal to $M$, there exists a circle of radius $R$ that contains all $n$ points.



      I realize this is related to the smallest enclosing circle problem, but it is not the same. Basically, I have a set of points, and I know all the pairwise distances between them, and I am given a fixed radius. I want to be able to say that if the maximum pairwise distance between these points is less than $M$, then there is definitely a circle of radius $R$ that encloses all of them, where this M is as large as possible.



      Obviously, for two points, the answer is $2R$. For three points, it gets more complicated, but using some geometry, I believe the answer is $sqrt2R$ (as in $sqrtR^2 + R^2$), but I haven't been able to prove it. I would like to generalize this to $n$ points, where I am fine with the answer being dependent on $n$.



      My hypothesis is that $sqrt2R leq M leq 2R$ for all $n$, but I would be mainly interested in how large $M$ can be made as the number of points increases.










      share|cite|improve this question









      $endgroup$




      Given a positive real number $R$ and $n$ fixed points in a plane, find the largest possible value $M$ such that if the pairwise distance between the $n$ points is less or equal to $M$, there exists a circle of radius $R$ that contains all $n$ points.



      I realize this is related to the smallest enclosing circle problem, but it is not the same. Basically, I have a set of points, and I know all the pairwise distances between them, and I am given a fixed radius. I want to be able to say that if the maximum pairwise distance between these points is less than $M$, then there is definitely a circle of radius $R$ that encloses all of them, where this M is as large as possible.



      Obviously, for two points, the answer is $2R$. For three points, it gets more complicated, but using some geometry, I believe the answer is $sqrt2R$ (as in $sqrtR^2 + R^2$), but I haven't been able to prove it. I would like to generalize this to $n$ points, where I am fine with the answer being dependent on $n$.



      My hypothesis is that $sqrt2R leq M leq 2R$ for all $n$, but I would be mainly interested in how large $M$ can be made as the number of points increases.







      geometry euclidean-geometry






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 26 at 17:36









      DennisDennis

      111




      111




















          1 Answer
          1






          active

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          0












          $begingroup$

          I don't have a complete solution but I can prove that your conclusion for $n=3$ points is wrong. Suppose that the maximum pairwise distance between 3 points is $M$. WLOG, suppose that the maximum distance $M$ is reached between points $A$ and $B$.



          Where is the third point $C$? It has to be somewhere in the pink region. The borders of that region are segment $AB$ and two arcs, each encompassing $60^circ$ with centers at points $A$ and $B$. Wherever you put the third point ($C',C''$), you can always cover the whole triangle with the blue circle. But the blue circle cannot be any smaller because in that case it could not cover the triangle $ABC$. And in that case:



          $$M=Rsqrt3$$



          enter image description here






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Thanks! Just realized my flaw for the $n=3$ case. Theoretically, since points can be arbitrarily close together, I think $M$ cannot be any larger than $Rsqrt3$, and since adding more points only puts more restrictions on where the next one can go, I don't think $M$ gets any smaller, either. For my practical application, though, it would be interesting to see if $M$ could be made larger with a relatively high probability for points that are reasonably "spread out."
            $endgroup$
            – Dennis
            Mar 27 at 21:07










          • $begingroup$
            @Dennis If you find the answer useful, consider upvoting it, you don’t have to accept it.
            $endgroup$
            – Oldboy
            Mar 27 at 22:19










          • $begingroup$
            I did. Just didn't register because apparently I don't have enough "reputation points" or whatever.
            $endgroup$
            – Dennis
            Mar 27 at 22:31











          Your Answer








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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

          votes






          active

          oldest

          votes









          0












          $begingroup$

          I don't have a complete solution but I can prove that your conclusion for $n=3$ points is wrong. Suppose that the maximum pairwise distance between 3 points is $M$. WLOG, suppose that the maximum distance $M$ is reached between points $A$ and $B$.



          Where is the third point $C$? It has to be somewhere in the pink region. The borders of that region are segment $AB$ and two arcs, each encompassing $60^circ$ with centers at points $A$ and $B$. Wherever you put the third point ($C',C''$), you can always cover the whole triangle with the blue circle. But the blue circle cannot be any smaller because in that case it could not cover the triangle $ABC$. And in that case:



          $$M=Rsqrt3$$



          enter image description here






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Thanks! Just realized my flaw for the $n=3$ case. Theoretically, since points can be arbitrarily close together, I think $M$ cannot be any larger than $Rsqrt3$, and since adding more points only puts more restrictions on where the next one can go, I don't think $M$ gets any smaller, either. For my practical application, though, it would be interesting to see if $M$ could be made larger with a relatively high probability for points that are reasonably "spread out."
            $endgroup$
            – Dennis
            Mar 27 at 21:07










          • $begingroup$
            @Dennis If you find the answer useful, consider upvoting it, you don’t have to accept it.
            $endgroup$
            – Oldboy
            Mar 27 at 22:19










          • $begingroup$
            I did. Just didn't register because apparently I don't have enough "reputation points" or whatever.
            $endgroup$
            – Dennis
            Mar 27 at 22:31















          0












          $begingroup$

          I don't have a complete solution but I can prove that your conclusion for $n=3$ points is wrong. Suppose that the maximum pairwise distance between 3 points is $M$. WLOG, suppose that the maximum distance $M$ is reached between points $A$ and $B$.



          Where is the third point $C$? It has to be somewhere in the pink region. The borders of that region are segment $AB$ and two arcs, each encompassing $60^circ$ with centers at points $A$ and $B$. Wherever you put the third point ($C',C''$), you can always cover the whole triangle with the blue circle. But the blue circle cannot be any smaller because in that case it could not cover the triangle $ABC$. And in that case:



          $$M=Rsqrt3$$



          enter image description here






          share|cite|improve this answer









          $endgroup$












          • $begingroup$
            Thanks! Just realized my flaw for the $n=3$ case. Theoretically, since points can be arbitrarily close together, I think $M$ cannot be any larger than $Rsqrt3$, and since adding more points only puts more restrictions on where the next one can go, I don't think $M$ gets any smaller, either. For my practical application, though, it would be interesting to see if $M$ could be made larger with a relatively high probability for points that are reasonably "spread out."
            $endgroup$
            – Dennis
            Mar 27 at 21:07










          • $begingroup$
            @Dennis If you find the answer useful, consider upvoting it, you don’t have to accept it.
            $endgroup$
            – Oldboy
            Mar 27 at 22:19










          • $begingroup$
            I did. Just didn't register because apparently I don't have enough "reputation points" or whatever.
            $endgroup$
            – Dennis
            Mar 27 at 22:31













          0












          0








          0





          $begingroup$

          I don't have a complete solution but I can prove that your conclusion for $n=3$ points is wrong. Suppose that the maximum pairwise distance between 3 points is $M$. WLOG, suppose that the maximum distance $M$ is reached between points $A$ and $B$.



          Where is the third point $C$? It has to be somewhere in the pink region. The borders of that region are segment $AB$ and two arcs, each encompassing $60^circ$ with centers at points $A$ and $B$. Wherever you put the third point ($C',C''$), you can always cover the whole triangle with the blue circle. But the blue circle cannot be any smaller because in that case it could not cover the triangle $ABC$. And in that case:



          $$M=Rsqrt3$$



          enter image description here






          share|cite|improve this answer









          $endgroup$



          I don't have a complete solution but I can prove that your conclusion for $n=3$ points is wrong. Suppose that the maximum pairwise distance between 3 points is $M$. WLOG, suppose that the maximum distance $M$ is reached between points $A$ and $B$.



          Where is the third point $C$? It has to be somewhere in the pink region. The borders of that region are segment $AB$ and two arcs, each encompassing $60^circ$ with centers at points $A$ and $B$. Wherever you put the third point ($C',C''$), you can always cover the whole triangle with the blue circle. But the blue circle cannot be any smaller because in that case it could not cover the triangle $ABC$. And in that case:



          $$M=Rsqrt3$$



          enter image description here







          share|cite|improve this answer












          share|cite|improve this answer



          share|cite|improve this answer










          answered Mar 27 at 16:53









          OldboyOldboy

          9,53411138




          9,53411138











          • $begingroup$
            Thanks! Just realized my flaw for the $n=3$ case. Theoretically, since points can be arbitrarily close together, I think $M$ cannot be any larger than $Rsqrt3$, and since adding more points only puts more restrictions on where the next one can go, I don't think $M$ gets any smaller, either. For my practical application, though, it would be interesting to see if $M$ could be made larger with a relatively high probability for points that are reasonably "spread out."
            $endgroup$
            – Dennis
            Mar 27 at 21:07










          • $begingroup$
            @Dennis If you find the answer useful, consider upvoting it, you don’t have to accept it.
            $endgroup$
            – Oldboy
            Mar 27 at 22:19










          • $begingroup$
            I did. Just didn't register because apparently I don't have enough "reputation points" or whatever.
            $endgroup$
            – Dennis
            Mar 27 at 22:31
















          • $begingroup$
            Thanks! Just realized my flaw for the $n=3$ case. Theoretically, since points can be arbitrarily close together, I think $M$ cannot be any larger than $Rsqrt3$, and since adding more points only puts more restrictions on where the next one can go, I don't think $M$ gets any smaller, either. For my practical application, though, it would be interesting to see if $M$ could be made larger with a relatively high probability for points that are reasonably "spread out."
            $endgroup$
            – Dennis
            Mar 27 at 21:07










          • $begingroup$
            @Dennis If you find the answer useful, consider upvoting it, you don’t have to accept it.
            $endgroup$
            – Oldboy
            Mar 27 at 22:19










          • $begingroup$
            I did. Just didn't register because apparently I don't have enough "reputation points" or whatever.
            $endgroup$
            – Dennis
            Mar 27 at 22:31















          $begingroup$
          Thanks! Just realized my flaw for the $n=3$ case. Theoretically, since points can be arbitrarily close together, I think $M$ cannot be any larger than $Rsqrt3$, and since adding more points only puts more restrictions on where the next one can go, I don't think $M$ gets any smaller, either. For my practical application, though, it would be interesting to see if $M$ could be made larger with a relatively high probability for points that are reasonably "spread out."
          $endgroup$
          – Dennis
          Mar 27 at 21:07




          $begingroup$
          Thanks! Just realized my flaw for the $n=3$ case. Theoretically, since points can be arbitrarily close together, I think $M$ cannot be any larger than $Rsqrt3$, and since adding more points only puts more restrictions on where the next one can go, I don't think $M$ gets any smaller, either. For my practical application, though, it would be interesting to see if $M$ could be made larger with a relatively high probability for points that are reasonably "spread out."
          $endgroup$
          – Dennis
          Mar 27 at 21:07












          $begingroup$
          @Dennis If you find the answer useful, consider upvoting it, you don’t have to accept it.
          $endgroup$
          – Oldboy
          Mar 27 at 22:19




          $begingroup$
          @Dennis If you find the answer useful, consider upvoting it, you don’t have to accept it.
          $endgroup$
          – Oldboy
          Mar 27 at 22:19












          $begingroup$
          I did. Just didn't register because apparently I don't have enough "reputation points" or whatever.
          $endgroup$
          – Dennis
          Mar 27 at 22:31




          $begingroup$
          I did. Just didn't register because apparently I don't have enough "reputation points" or whatever.
          $endgroup$
          – Dennis
          Mar 27 at 22:31

















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