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What are sufficient conditions for finitely many equivalence classes of slice contours of surfaces?


Homotopy equivalence of two spaces, homeworkWhy is the tangent space to a real projective plane two dimensional?Orientability of manifoldWhat are Equivalence ClassesEquivalence relation for which there are infinitely many equivalence classes.$Phi$ and $Psi$ have the same orientation, prove there are at least two equivalence classes.direct sums in homotopy categoryProve that equivalence classes are the fibers of $f$Translate into first order logic: “$R$ has at least two classes of equivalence” and “$R$ has exactly two classes of equivalence”Uncountably Many Equivalence Classes













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Apologies in advance for imprecision of the question. Thanks for improving it. Let M be a compact, connected, orientable surface in three dimensional Euclidean space without boundary and without self-intersections, such as a sphere, or a torus. Define a slice contour C of M to be the non-empty intersection of M with a plane. (For example, the equator of a sphere is a slice contour; there are different ways that a torus admits slice contours consisting of two disjoint circles.) Define two slice contours C and D to be equivalent if there exists a continuous homotopy H from the inclusion map of C into M to the inclusion map of D into M, such that the inclusion map at every stage of H is an injective homeomorphism. This is an equivalence relation on the set of all slice contours. What are sufficient conditions for the following statements to be jointly true: (1) a slice contour is a finite 1-dimensional CW complex; (2) there is a finite number of equivalence classes; (3) there exists at least two equivalence classes with exactly one member; (4) there exists at least one equivalence class with a continuum of members.










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    Apologies in advance for imprecision of the question. Thanks for improving it. Let M be a compact, connected, orientable surface in three dimensional Euclidean space without boundary and without self-intersections, such as a sphere, or a torus. Define a slice contour C of M to be the non-empty intersection of M with a plane. (For example, the equator of a sphere is a slice contour; there are different ways that a torus admits slice contours consisting of two disjoint circles.) Define two slice contours C and D to be equivalent if there exists a continuous homotopy H from the inclusion map of C into M to the inclusion map of D into M, such that the inclusion map at every stage of H is an injective homeomorphism. This is an equivalence relation on the set of all slice contours. What are sufficient conditions for the following statements to be jointly true: (1) a slice contour is a finite 1-dimensional CW complex; (2) there is a finite number of equivalence classes; (3) there exists at least two equivalence classes with exactly one member; (4) there exists at least one equivalence class with a continuum of members.










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      Apologies in advance for imprecision of the question. Thanks for improving it. Let M be a compact, connected, orientable surface in three dimensional Euclidean space without boundary and without self-intersections, such as a sphere, or a torus. Define a slice contour C of M to be the non-empty intersection of M with a plane. (For example, the equator of a sphere is a slice contour; there are different ways that a torus admits slice contours consisting of two disjoint circles.) Define two slice contours C and D to be equivalent if there exists a continuous homotopy H from the inclusion map of C into M to the inclusion map of D into M, such that the inclusion map at every stage of H is an injective homeomorphism. This is an equivalence relation on the set of all slice contours. What are sufficient conditions for the following statements to be jointly true: (1) a slice contour is a finite 1-dimensional CW complex; (2) there is a finite number of equivalence classes; (3) there exists at least two equivalence classes with exactly one member; (4) there exists at least one equivalence class with a continuum of members.










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      Apologies in advance for imprecision of the question. Thanks for improving it. Let M be a compact, connected, orientable surface in three dimensional Euclidean space without boundary and without self-intersections, such as a sphere, or a torus. Define a slice contour C of M to be the non-empty intersection of M with a plane. (For example, the equator of a sphere is a slice contour; there are different ways that a torus admits slice contours consisting of two disjoint circles.) Define two slice contours C and D to be equivalent if there exists a continuous homotopy H from the inclusion map of C into M to the inclusion map of D into M, such that the inclusion map at every stage of H is an injective homeomorphism. This is an equivalence relation on the set of all slice contours. What are sufficient conditions for the following statements to be jointly true: (1) a slice contour is a finite 1-dimensional CW complex; (2) there is a finite number of equivalence classes; (3) there exists at least two equivalence classes with exactly one member; (4) there exists at least one equivalence class with a continuum of members.







      differential-geometry homotopy-theory equivalence-relations






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      asked Feb 20 at 20:07









      Ellis D CooperEllis D Cooper

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          A theorem and proof without additional assumptions except smoothness might proceed roughly along the following lines. First, a finite 2-dimensional simplicial complex in space consisting of points, closed line segments for 1-simplices, and closed triangles for 2-simplicies could satisfy the conditions that two 2-simplices meet at most along a 1-simplex, every 1-simplex is the intersection of exactly two 2-simplices, and every 2-simplex may be oriented so that any two 2-simplices meeting at a 1-simplex induce opposite orientations on it. I am guessing that the union of the simplices in such a complex satisfy a three-dimensional version of the Jordan Curve Theorem. Second, I am guessing that such a union satisfies the slice contour conditions (1)-(4) by induction on the number of 2-simplices. Second, if the surface M is sufficiently smooth, with an upper bound on its curvature, then it may be approximated by such a union with its vertices in M, and its 1-simplices very close to geodesics in M connecting the vertices, in the sense that the distance between a 1-simplex and its corresponding geodesic path in M is the supremum of the Euclidean distances between appropriately parametrized moving points. If epsilon is the upper bound on those suprema over all 1-simplices, then the finite number N of equivalence classes depends on epsilon, and third, N(epsilon) is bounded as epsilon goes to zero by some argument about curvature of M.






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            A theorem and proof without additional assumptions except smoothness might proceed roughly along the following lines. First, a finite 2-dimensional simplicial complex in space consisting of points, closed line segments for 1-simplices, and closed triangles for 2-simplicies could satisfy the conditions that two 2-simplices meet at most along a 1-simplex, every 1-simplex is the intersection of exactly two 2-simplices, and every 2-simplex may be oriented so that any two 2-simplices meeting at a 1-simplex induce opposite orientations on it. I am guessing that the union of the simplices in such a complex satisfy a three-dimensional version of the Jordan Curve Theorem. Second, I am guessing that such a union satisfies the slice contour conditions (1)-(4) by induction on the number of 2-simplices. Second, if the surface M is sufficiently smooth, with an upper bound on its curvature, then it may be approximated by such a union with its vertices in M, and its 1-simplices very close to geodesics in M connecting the vertices, in the sense that the distance between a 1-simplex and its corresponding geodesic path in M is the supremum of the Euclidean distances between appropriately parametrized moving points. If epsilon is the upper bound on those suprema over all 1-simplices, then the finite number N of equivalence classes depends on epsilon, and third, N(epsilon) is bounded as epsilon goes to zero by some argument about curvature of M.






            share|cite|improve this answer









            $endgroup$

















              0












              $begingroup$

              A theorem and proof without additional assumptions except smoothness might proceed roughly along the following lines. First, a finite 2-dimensional simplicial complex in space consisting of points, closed line segments for 1-simplices, and closed triangles for 2-simplicies could satisfy the conditions that two 2-simplices meet at most along a 1-simplex, every 1-simplex is the intersection of exactly two 2-simplices, and every 2-simplex may be oriented so that any two 2-simplices meeting at a 1-simplex induce opposite orientations on it. I am guessing that the union of the simplices in such a complex satisfy a three-dimensional version of the Jordan Curve Theorem. Second, I am guessing that such a union satisfies the slice contour conditions (1)-(4) by induction on the number of 2-simplices. Second, if the surface M is sufficiently smooth, with an upper bound on its curvature, then it may be approximated by such a union with its vertices in M, and its 1-simplices very close to geodesics in M connecting the vertices, in the sense that the distance between a 1-simplex and its corresponding geodesic path in M is the supremum of the Euclidean distances between appropriately parametrized moving points. If epsilon is the upper bound on those suprema over all 1-simplices, then the finite number N of equivalence classes depends on epsilon, and third, N(epsilon) is bounded as epsilon goes to zero by some argument about curvature of M.






              share|cite|improve this answer









              $endgroup$















                0












                0








                0





                $begingroup$

                A theorem and proof without additional assumptions except smoothness might proceed roughly along the following lines. First, a finite 2-dimensional simplicial complex in space consisting of points, closed line segments for 1-simplices, and closed triangles for 2-simplicies could satisfy the conditions that two 2-simplices meet at most along a 1-simplex, every 1-simplex is the intersection of exactly two 2-simplices, and every 2-simplex may be oriented so that any two 2-simplices meeting at a 1-simplex induce opposite orientations on it. I am guessing that the union of the simplices in such a complex satisfy a three-dimensional version of the Jordan Curve Theorem. Second, I am guessing that such a union satisfies the slice contour conditions (1)-(4) by induction on the number of 2-simplices. Second, if the surface M is sufficiently smooth, with an upper bound on its curvature, then it may be approximated by such a union with its vertices in M, and its 1-simplices very close to geodesics in M connecting the vertices, in the sense that the distance between a 1-simplex and its corresponding geodesic path in M is the supremum of the Euclidean distances between appropriately parametrized moving points. If epsilon is the upper bound on those suprema over all 1-simplices, then the finite number N of equivalence classes depends on epsilon, and third, N(epsilon) is bounded as epsilon goes to zero by some argument about curvature of M.






                share|cite|improve this answer









                $endgroup$



                A theorem and proof without additional assumptions except smoothness might proceed roughly along the following lines. First, a finite 2-dimensional simplicial complex in space consisting of points, closed line segments for 1-simplices, and closed triangles for 2-simplicies could satisfy the conditions that two 2-simplices meet at most along a 1-simplex, every 1-simplex is the intersection of exactly two 2-simplices, and every 2-simplex may be oriented so that any two 2-simplices meeting at a 1-simplex induce opposite orientations on it. I am guessing that the union of the simplices in such a complex satisfy a three-dimensional version of the Jordan Curve Theorem. Second, I am guessing that such a union satisfies the slice contour conditions (1)-(4) by induction on the number of 2-simplices. Second, if the surface M is sufficiently smooth, with an upper bound on its curvature, then it may be approximated by such a union with its vertices in M, and its 1-simplices very close to geodesics in M connecting the vertices, in the sense that the distance between a 1-simplex and its corresponding geodesic path in M is the supremum of the Euclidean distances between appropriately parametrized moving points. If epsilon is the upper bound on those suprema over all 1-simplices, then the finite number N of equivalence classes depends on epsilon, and third, N(epsilon) is bounded as epsilon goes to zero by some argument about curvature of M.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered Mar 13 at 17:52









                Ellis D CooperEllis D Cooper

                114




                114



























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