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Gateaux Derivative of Fourier Transform/Characteristic Function
Fourier Transform ConfusionFourier transform of the identity function $f(x)=x$Sampling, Fourier Transform, and Discrete Fourier TransformFourier Transform of derivative a vector functionCharacteristic Function and Inverse Fourier TransformDifferentiability of discrete-time Fourier transformWhat exactly is the Fourier transform?Functional derivatives of Fourier transformUnderstanding Fourier transform of derivative of distributionWhat is the square root of a Fourier transform?
$begingroup$
Suppose that $X$ is a square integrable random-variable defined on a probability space $(Omega,mathcalF,mathbbP)$. It's characteristic function/Fourier transform is defined to be
$$
mathfrakF[X](gamma)triangleq int_omega in Omega
e^-gamma X(omega)
mathbbP(domega)
.
$$
For any fixed $gamma in mathbbR$, when is the map
beginalign
L^2(Omega,mathcalF,mathbbP)rightarrow mathbbR
\
X mapsto mathfrakF[X](gamma),
endalign
Gateau differentiable (for what X)? Moreover, what is its Gateau derivative?
functional-analysis probability-theory fourier-analysis frechet-derivative gateaux-derivative
$endgroup$
add a comment |
$begingroup$
Suppose that $X$ is a square integrable random-variable defined on a probability space $(Omega,mathcalF,mathbbP)$. It's characteristic function/Fourier transform is defined to be
$$
mathfrakF[X](gamma)triangleq int_omega in Omega
e^-gamma X(omega)
mathbbP(domega)
.
$$
For any fixed $gamma in mathbbR$, when is the map
beginalign
L^2(Omega,mathcalF,mathbbP)rightarrow mathbbR
\
X mapsto mathfrakF[X](gamma),
endalign
Gateau differentiable (for what X)? Moreover, what is its Gateau derivative?
functional-analysis probability-theory fourier-analysis frechet-derivative gateaux-derivative
$endgroup$
$begingroup$
Square integrability is not enough for your characteristic function to exist. This is rather called the moment generating function (with $-gamma$ instead of $gamma$).
$endgroup$
– Abdelmalek Abdesselam
yesterday
$begingroup$
On the subspace of $L^2$ on which the MFG exists, what can be said about it derivative then?
$endgroup$
– AIM_BLB
yesterday
add a comment |
$begingroup$
Suppose that $X$ is a square integrable random-variable defined on a probability space $(Omega,mathcalF,mathbbP)$. It's characteristic function/Fourier transform is defined to be
$$
mathfrakF[X](gamma)triangleq int_omega in Omega
e^-gamma X(omega)
mathbbP(domega)
.
$$
For any fixed $gamma in mathbbR$, when is the map
beginalign
L^2(Omega,mathcalF,mathbbP)rightarrow mathbbR
\
X mapsto mathfrakF[X](gamma),
endalign
Gateau differentiable (for what X)? Moreover, what is its Gateau derivative?
functional-analysis probability-theory fourier-analysis frechet-derivative gateaux-derivative
$endgroup$
Suppose that $X$ is a square integrable random-variable defined on a probability space $(Omega,mathcalF,mathbbP)$. It's characteristic function/Fourier transform is defined to be
$$
mathfrakF[X](gamma)triangleq int_omega in Omega
e^-gamma X(omega)
mathbbP(domega)
.
$$
For any fixed $gamma in mathbbR$, when is the map
beginalign
L^2(Omega,mathcalF,mathbbP)rightarrow mathbbR
\
X mapsto mathfrakF[X](gamma),
endalign
Gateau differentiable (for what X)? Moreover, what is its Gateau derivative?
functional-analysis probability-theory fourier-analysis frechet-derivative gateaux-derivative
functional-analysis probability-theory fourier-analysis frechet-derivative gateaux-derivative
edited 17 hours ago
AIM_BLB
asked yesterday
AIM_BLBAIM_BLB
2,5152819
2,5152819
$begingroup$
Square integrability is not enough for your characteristic function to exist. This is rather called the moment generating function (with $-gamma$ instead of $gamma$).
$endgroup$
– Abdelmalek Abdesselam
yesterday
$begingroup$
On the subspace of $L^2$ on which the MFG exists, what can be said about it derivative then?
$endgroup$
– AIM_BLB
yesterday
add a comment |
$begingroup$
Square integrability is not enough for your characteristic function to exist. This is rather called the moment generating function (with $-gamma$ instead of $gamma$).
$endgroup$
– Abdelmalek Abdesselam
yesterday
$begingroup$
On the subspace of $L^2$ on which the MFG exists, what can be said about it derivative then?
$endgroup$
– AIM_BLB
yesterday
$begingroup$
Square integrability is not enough for your characteristic function to exist. This is rather called the moment generating function (with $-gamma$ instead of $gamma$).
$endgroup$
– Abdelmalek Abdesselam
yesterday
$begingroup$
Square integrability is not enough for your characteristic function to exist. This is rather called the moment generating function (with $-gamma$ instead of $gamma$).
$endgroup$
– Abdelmalek Abdesselam
yesterday
$begingroup$
On the subspace of $L^2$ on which the MFG exists, what can be said about it derivative then?
$endgroup$
– AIM_BLB
yesterday
$begingroup$
On the subspace of $L^2$ on which the MFG exists, what can be said about it derivative then?
$endgroup$
– AIM_BLB
yesterday
add a comment |
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$begingroup$
Square integrability is not enough for your characteristic function to exist. This is rather called the moment generating function (with $-gamma$ instead of $gamma$).
$endgroup$
– Abdelmalek Abdesselam
yesterday
$begingroup$
On the subspace of $L^2$ on which the MFG exists, what can be said about it derivative then?
$endgroup$
– AIM_BLB
yesterday