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Convert Boolean function to NAND-only using De Morgan's law

Boolean Expression Simplification (De Morgan's)Nand this Boolean Algebra Function?Boolean Algebra, using DeMorgan's lawConvert boolean expression to pos then nor onlyImplement boolean function with OR-NAND and NOR-OR gatesDe Morgan's Law Operation orderPass a logic function using only NANDBoolean algebra with the definition of Huntington - prove de morgan's law without the use of associativityDe Morgan's Laws and Boolean SimplificationK-Map resulting in a simplified function of 1

0

1

$begingroup$

I have a function that I must convert to NAND-only. I've been trying to use the De Morgan's law but, I'm getting wrong results. Here is my function:

$$z = overlined overlinef(overlineace + acoverlinee + overlinebaoverlinec + overlineaboverlinecoverlinee + overlineaboverlinecoverlinee) + df(ace + overlineabcoverlinee + aoverlineboverlinecoverlinee) + de(overlinecoverlinef+aoverlinebcoverlinef) + abcoverlinedf$$

I used De Morgan's law:

$$overlinea+b = overlinea*overlineb$$

to get the following function

$$overlineoverlineoverlinedf(overlineaoverlinece * overlineoverlineace * overlineoverlineabc * overlineaoverlinebce * overlineaoverlinebce)
*
overlineoverlineoverlinedoverlinef(overlineoverlineaoverlinecoverlinee * overlineaoverlineboverlinece * overlineoverlineabce)
*
overlineoverlineoverlinedoverlinee(overlinecf * overlineoverlineaboverlinecf) * abcoverlinedf$$

which outputs wrong results.. This function even looks too difficult, I must be doing something wrong. I've been trying to get this working for two days now but it looks like I'll need help from the pros.

boolean-algebra

share|cite|improve this question

edited 17 hours ago

Rodrigo de Azevedo

13.1k41960

asked 18 hours ago

NedasNedas

1

New contributor

Nedas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

0

1

$begingroup$

I have a function that I must convert to NAND-only. I've been trying to use the De Morgan's law but, I'm getting wrong results. Here is my function:

$$z = overlined overlinef(overlineace + acoverlinee + overlinebaoverlinec + overlineaboverlinecoverlinee + overlineaboverlinecoverlinee) + df(ace + overlineabcoverlinee + aoverlineboverlinecoverlinee) + de(overlinecoverlinef+aoverlinebcoverlinef) + abcoverlinedf$$

I used De Morgan's law:

$$overlinea+b = overlinea*overlineb$$

to get the following function

$$overlineoverlineoverlinedf(overlineaoverlinece * overlineoverlineace * overlineoverlineabc * overlineaoverlinebce * overlineaoverlinebce)
*
overlineoverlineoverlinedoverlinef(overlineoverlineaoverlinecoverlinee * overlineaoverlineboverlinece * overlineoverlineabce)
*
overlineoverlineoverlinedoverlinee(overlinecf * overlineoverlineaboverlinecf) * abcoverlinedf$$

which outputs wrong results.. This function even looks too difficult, I must be doing something wrong. I've been trying to get this working for two days now but it looks like I'll need help from the pros.

boolean-algebra

share|cite|improve this question

edited 17 hours ago

Rodrigo de Azevedo

13.1k41960

asked 18 hours ago

NedasNedas

1

New contributor

Nedas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

add a comment | 

$begingroup$

I have a function that I must convert to NAND-only. I've been trying to use the De Morgan's law but, I'm getting wrong results. Here is my function:

$$z = overlined overlinef(overlineace + acoverlinee + overlinebaoverlinec + overlineaboverlinecoverlinee + overlineaboverlinecoverlinee) + df(ace + overlineabcoverlinee + aoverlineboverlinecoverlinee) + de(overlinecoverlinef+aoverlinebcoverlinef) + abcoverlinedf$$

I used De Morgan's law:

$$overlinea+b = overlinea*overlineb$$

to get the following function

$$overlineoverlineoverlinedf(overlineaoverlinece * overlineoverlineace * overlineoverlineabc * overlineaoverlinebce * overlineaoverlinebce)
*
overlineoverlineoverlinedoverlinef(overlineoverlineaoverlinecoverlinee * overlineaoverlineboverlinece * overlineoverlineabce)
*
overlineoverlineoverlinedoverlinee(overlinecf * overlineoverlineaboverlinecf) * abcoverlinedf$$

which outputs wrong results.. This function even looks too difficult, I must be doing something wrong. I've been trying to get this working for two days now but it looks like I'll need help from the pros.

boolean-algebra

share|cite|improve this question

edited 17 hours ago

Rodrigo de Azevedo

13.1k41960

asked 18 hours ago

NedasNedas

1

New contributor

Nedas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

share|cite|improve this question

edited 17 hours ago

Rodrigo de Azevedo

13.1k41960

asked 18 hours ago

NedasNedas

1

New contributor

Nedas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|cite|improve this question

edited 17 hours ago

Rodrigo de Azevedo

13.1k41960

asked 18 hours ago

NedasNedas

1

New contributor

Nedas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 17 hours ago

Rodrigo de Azevedo

13.1k41960

edited 17 hours ago

Rodrigo de Azevedo

13.1k41960

asked 18 hours ago

NedasNedas

1

New contributor

Nedas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 18 hours ago

NedasNedas

1