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If a change is a sum of changes in components, what is a component's proportion of the change?
The algebra of clopen sets vs. the algebra of connected componentswhat is the meaning of the “closure of a sequence ”Estimating the number of connected components of a curve contained in a given setIs the sum of two complete metrics complete?About the question “what are the connected components of $mathbbR_l$?”What changes if the basis of topology on the metric space is defined as closed balls rather than open balls?What is the name of (1 - sum of component-wise min)? Is it a metric?The limit of a sequence of $ell^p$ is the limit of each components?What is the metric used here?Changing the distance considered on a metric space changes open sets inside?
$begingroup$
Let's say you have a balance which changes by $Delta$, where the change is net of an increase less a decrease i.e. $Delta := uparrow - downarrow$. Both the increase and decrease are caused by 2 components: A and B
$ uparrow:= uparrow^A + uparrow^B$ and similarly,
$ downarrow:= downarrow^A + downarrow^B$
Clearly
How do I create a metric $hatDelta^A$ (which is supposed to represent the proportion of the total change that is attributable to A) such that:
$hatDelta^A + hatDelta^B = 1$ (propotions add to 1)
For $k in A,B$, we have:
(a) $0 leq hatDelta^k leq 1$ (proportions are not greater than 1 or negative)
(b) $If Delta^k = Delta implies hatDelta^k = 1$ (If the change attributable to $k$ is the same as the total change, then $k$ is responsible for the total change.
metric-spaces
$endgroup$
add a comment |
$begingroup$
Let's say you have a balance which changes by $Delta$, where the change is net of an increase less a decrease i.e. $Delta := uparrow - downarrow$. Both the increase and decrease are caused by 2 components: A and B
$ uparrow:= uparrow^A + uparrow^B$ and similarly,
$ downarrow:= downarrow^A + downarrow^B$
Clearly
How do I create a metric $hatDelta^A$ (which is supposed to represent the proportion of the total change that is attributable to A) such that:
$hatDelta^A + hatDelta^B = 1$ (propotions add to 1)
For $k in A,B$, we have:
(a) $0 leq hatDelta^k leq 1$ (proportions are not greater than 1 or negative)
(b) $If Delta^k = Delta implies hatDelta^k = 1$ (If the change attributable to $k$ is the same as the total change, then $k$ is responsible for the total change.
metric-spaces
$endgroup$
add a comment |
$begingroup$
Let's say you have a balance which changes by $Delta$, where the change is net of an increase less a decrease i.e. $Delta := uparrow - downarrow$. Both the increase and decrease are caused by 2 components: A and B
$ uparrow:= uparrow^A + uparrow^B$ and similarly,
$ downarrow:= downarrow^A + downarrow^B$
Clearly
How do I create a metric $hatDelta^A$ (which is supposed to represent the proportion of the total change that is attributable to A) such that:
$hatDelta^A + hatDelta^B = 1$ (propotions add to 1)
For $k in A,B$, we have:
(a) $0 leq hatDelta^k leq 1$ (proportions are not greater than 1 or negative)
(b) $If Delta^k = Delta implies hatDelta^k = 1$ (If the change attributable to $k$ is the same as the total change, then $k$ is responsible for the total change.
metric-spaces
$endgroup$
Let's say you have a balance which changes by $Delta$, where the change is net of an increase less a decrease i.e. $Delta := uparrow - downarrow$. Both the increase and decrease are caused by 2 components: A and B
$ uparrow:= uparrow^A + uparrow^B$ and similarly,
$ downarrow:= downarrow^A + downarrow^B$
Clearly
How do I create a metric $hatDelta^A$ (which is supposed to represent the proportion of the total change that is attributable to A) such that:
$hatDelta^A + hatDelta^B = 1$ (propotions add to 1)
For $k in A,B$, we have:
(a) $0 leq hatDelta^k leq 1$ (proportions are not greater than 1 or negative)
(b) $If Delta^k = Delta implies hatDelta^k = 1$ (If the change attributable to $k$ is the same as the total change, then $k$ is responsible for the total change.
metric-spaces
metric-spaces
asked 17 hours ago
Vykta WakandigaraVykta Wakandigara
11
11
add a comment |
add a comment |
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