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Fourier coefficients of $sin + cos$


Determining Fourier series coefficientsFourier series for $cos( frac x2)$Coefficients of Fourier Series of (Cos(t))^3reciprocal of a Fourier Cosine seriesHow to calculate the Fourier coefficientsDoubt regarding Fourier series coefficients.Find the Fourier series coefficients of $x_1[n]r[n]$.Is just the product of their coefficients?Fourier coefficients of $sin(2 pi f_0 t)$Fourier coefficients of a sumFourier coefficients of $|cos x|$













0












$begingroup$


Fourier coefficients $x(t) = A_1 cos (2 pi f_0 t + E ) + A_3 cos (6 pi f_0 t + F )$



I applied the Fourier series definition with the integer from $0$ to $t * e^2if_0ktpi $ and I found that the series is $ 0 $ except for $k=1,-1,3,-3 $ but now I don’t know how to find the Fourier coefficients for this values of $k$.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Thanks for trying to format your question! You just need dollar signs around the parts you want to format: $x(t)$ becomes $x(t)$.
    $endgroup$
    – Toby Mak
    Mar 13 at 11:09
















0












$begingroup$


Fourier coefficients $x(t) = A_1 cos (2 pi f_0 t + E ) + A_3 cos (6 pi f_0 t + F )$



I applied the Fourier series definition with the integer from $0$ to $t * e^2if_0ktpi $ and I found that the series is $ 0 $ except for $k=1,-1,3,-3 $ but now I don’t know how to find the Fourier coefficients for this values of $k$.










share|cite|improve this question











$endgroup$











  • $begingroup$
    Thanks for trying to format your question! You just need dollar signs around the parts you want to format: $x(t)$ becomes $x(t)$.
    $endgroup$
    – Toby Mak
    Mar 13 at 11:09














0












0








0





$begingroup$


Fourier coefficients $x(t) = A_1 cos (2 pi f_0 t + E ) + A_3 cos (6 pi f_0 t + F )$



I applied the Fourier series definition with the integer from $0$ to $t * e^2if_0ktpi $ and I found that the series is $ 0 $ except for $k=1,-1,3,-3 $ but now I don’t know how to find the Fourier coefficients for this values of $k$.










share|cite|improve this question











$endgroup$




Fourier coefficients $x(t) = A_1 cos (2 pi f_0 t + E ) + A_3 cos (6 pi f_0 t + F )$



I applied the Fourier series definition with the integer from $0$ to $t * e^2if_0ktpi $ and I found that the series is $ 0 $ except for $k=1,-1,3,-3 $ but now I don’t know how to find the Fourier coefficients for this values of $k$.







fourier-series






share|cite|improve this question















share|cite|improve this question













share|cite|improve this question




share|cite|improve this question








edited Mar 17 at 11:55









Rócherz

3,0013821




3,0013821










asked Mar 13 at 10:48









Elena MartiniElena Martini

113




113











  • $begingroup$
    Thanks for trying to format your question! You just need dollar signs around the parts you want to format: $x(t)$ becomes $x(t)$.
    $endgroup$
    – Toby Mak
    Mar 13 at 11:09

















  • $begingroup$
    Thanks for trying to format your question! You just need dollar signs around the parts you want to format: $x(t)$ becomes $x(t)$.
    $endgroup$
    – Toby Mak
    Mar 13 at 11:09
















$begingroup$
Thanks for trying to format your question! You just need dollar signs around the parts you want to format: $x(t)$ becomes $x(t)$.
$endgroup$
– Toby Mak
Mar 13 at 11:09





$begingroup$
Thanks for trying to format your question! You just need dollar signs around the parts you want to format: $x(t)$ becomes $x(t)$.
$endgroup$
– Toby Mak
Mar 13 at 11:09











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